Genetic Analysis: An Integrated Approach (3rd Edition)
3rd Edition
ISBN: 9780134605173
Author: Mark F. Sanders, John L. Bowman
Publisher: PEARSON
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Chapter 20, Problem 29P
A sample of
a. What are the frequencies of
b. Is this population in
c. Is inbreeding a possible genetic explanation for the observed distribution of genotypes? Why or why not?
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In a large herd of 5468 sheep, 76 animals have yellow fat, and the rest of the members of the herd have white fat. Yellow fat is inherited as a recessive trait. This herd is assumed to be in Hardy-Weinberg equilibrium.
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In a population with 1000 individuals and at Hardy-Weinberg equilibrium, the frequency of individuals with galactosemia is 4%.a. What are the frequencies of the dominant and recessive alleles?b. What is the expected frequency of the homozygous dominant in the population?c. What would be the expected frequency of the heterozygous dominant after five generations?
The human MN blood type is determined by two codominant alleles, LMand LN. The frequency of LM in Eskimos on a small Arctic island is0.80.a. If random mating takes place in this population, what are the expectedfrequencies of the M, MN, and N blood types on the island?b. If the inbreeding coefficient for this population is 0.05, what are theexpected frequencies of the M, MN, and N blood types on the island?
Chapter 20 Solutions
Genetic Analysis: An Integrated Approach (3rd Edition)
Ch. 20 - 20.1 Compare and contrast the terms in each of the...Ch. 20 - In a population, what is the consequence of...Ch. 20 - 20.3 Identify and describe the evolutionary forces...Ch. 20 - Describe how natural selection can produce...Ch. 20 - Thinking creatively about evolutionary mechanisms,...Ch. 20 - 20.6 Genetic drift, an evolutionary process...Ch. 20 - Over the course of many generations in a small...Ch. 20 - Catastrophic events such as loss of habitat,...Ch. 20 - 20.9 George Udny Yule was wrong in suggesting that...Ch. 20 - 20.10 The ability to taste the bitter compound...
Ch. 20 - Figure 20.6 illustrates the effect of an ethanol ...Ch. 20 - 20.12 Biologists have proposed that the use of...Ch. 20 - 20.13 Two populations of deer, one of them large...Ch. 20 - 20.14 Directional selection presents an apparent...Ch. 20 - 20.15 What is inbreeding depression? Why is...Ch. 20 - 20.16 Certain animal species, such as the...Ch. 20 - Genetic Analysis 20.1 predicts the number of...Ch. 20 - 20.18 In a population of rabbits, and . The...Ch. 20 - Sickle cell disease (SCD) is found in numerous...Ch. 20 - 20.20 Epidemiologic data on the population in the...Ch. 20 - The frequency of tasters and nontasters of PTC...Ch. 20 - Tay-Sachs disease is an autosomal recessive...Ch. 20 - 20.23 Cystic fibrosis (CF) is the most common...Ch. 20 - 20.24 In the mouse, Mus musculus, survival in...Ch. 20 - 20.25 In a population of flowers growing in a...Ch. 20 - Assume that the flower population described in the...Ch. 20 - 20.27 ABO blood type is examined in a Taiwanese...Ch. 20 - 20.28 A total ofmembers of a Central American...Ch. 20 - 20.29 A sample offield mice contains individuals...Ch. 20 - Prob. 30PCh. 20 - Albinism, an autosomal recessive trait...Ch. 20 - 20.32 The frequency of an autosomal recessive...Ch. 20 - 20.33 Evaluate the following pedigree, and answer...Ch. 20 - Evaluate the following pedigree, and answer the...Ch. 20 - The following is a partial pedigree of the British...Ch. 20 - Draw a separate hypothetical pedigree identifying...Ch. 20 - Prob. 37PCh. 20 - 20.38 Achromatopsia is a rare autosomal recessive...Ch. 20 - 20.39 New allopolyploid plant species can arise by...
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- Consider a sample of 100 individuals sampled from a population in Hardy-Weinberg equilibrium that are genotyped at a single locus. Of these 100 individuals, 25 individuals are A¡A1, 45 are A1A2, and 30 are A2A2. What is the actual (observed) allele frequency of the A1 allele in this sample? (you may use a calculator if needed) O A. 0.325 O B. 0.275 O C. 0.475 O D. 0.525arrow_forwardA new beneficial allele arises in a population, and it confers a moderate fitness benefit(s=0.01).A. If the mutation is partially recessive (h=0.2), what is the probability of fixation?B. If the mutation is additive (h=0.5), what is the probability of fixation?C. Explain in 1-2 sentences why the probability of fixation depends on the dominancecoefficient.arrow_forwardA family pedigree is shown here. A. What is the inbreeding coefficient for individual IV-2? Who is/ are her parents’ common ancestor(s)? B. Based on the data shown in this pedigree, is individual III-4 inbredarrow_forward
- Consider the following pedigree below for a rare autosomal trait. Be sure to take into account the inbreeding convention, when needed. 1. What is the probability that individual B is heterozygous? 2. What is the inbreeding coefficient of individual E? 3. After divorce, individual “A” decides to marry at random outside the pedigree. If the population allele frequency of the rare autosomal trait is 0.012, what are the chances of having an affected child for his first born of his second marriage?arrow_forwardYou discover two segregating genes (A and B) that affect resistance in a population of snails. You are interested in determining if the two loci are in LD. You analyzed 100 snails for allelic and haplotype states, and observed the frequencies reported in the table below. a. Calculate D for genes A and B. (D = gAB9ab - gAb9aB) b. Is this population in linkage equilibrium or linkage disequilibrium with respect to genes A and B? Frequency Allele A 0.6 Allele a 0.4 Allele B 0.8 Allele b 0.2 Haplotype AB Haplotype Ab Haplotype aB Haplotype ab 0.48 0.12 0.32 0.08arrow_forwardIn a population at Hardy-Weinberg equilibrium, 190 out of 1000 individuals have polydactyly. Note that the trait is dominant. a. What is the frequency of the dominant and recessive alleles? b. How many are expected to be heterozygotes for the trait? c. How many are expected to be homozygous dominant?arrow_forward
- An autosomal locus has alleles A and a. The allele frequencies in a population at Hardy Weinberg equilibrium are p = Freq(A) = 0.5 q = Freq(a) = 0.5 What is the frequency of homozygous wild-type (AA) in this population? Enter a single number between 0 and 1, for example, 0.33arrow_forwardImagine a population of 100 snails in which the shell colour is controlled by two alleles: B (black) and b (yellow) I) What is the total no. of loci for shell colour gene in this population II) in the snail population above, 20 out of the snails are yellow (bb) and 80 are black (BB or Bb). Of the 80 black snails, 30 are homozygous and 50 are heterozygous. How many loci for this gene are occupied by the B allele? III) What is the frequency of B allele? IV) Assuming that sexual reproduction takes place with random mating, no gene flow and no selection, what will be the frequency of yellow snails in next generation of the population described above? V) What will be the frequency of b allele in the next generation of the snail population describedarrow_forwardA mouse mutation with incomplete dominance (t =tailless) causes short tails in heterozygotes (t+/t). Thesame mutation acts as a recessive lethal that causeshomozygotes (t/t) to die in utero. In a populationconsisting of 150 mice, 60 are t+/t+ and 90 areheterozygotes.a. What are the allele frequencies in this population?b. Given that there is random mating among mice, nomigration, and no mutation, and ignoring the effects of random genetic drift, what are the expectednumbers of the different genotypes in this nextgeneration if 200 offspring are born?c. Two populations (called Pop 1 and Pop 2) of micecome into contact and interbreed randomly. Thesepopulations initially are composed of the followingnumbers of wild-type (t+/t+) homozygotes andtailless (t+/t) heterozygotes:Pop 1 Pop 2Wild type 16 48Tailless 48 36What are the frequencies of the two genotypes in thenext generation?arrow_forward
- The relative fitness values of three genotypes are wA/A =1.0, wA/a = 1.0, and wa/a = 0.7.a. If the population starts at the allele frequency p =0.5, what is the value of p in the next generation?b. What is the predicted equilibrium allele frequency ifthe rate of mutation of A to a is 2 × 10−5?arrow_forwardAlbinism is due to a recessive allele of an autosomal gene. Let a represent the albino allele and A represent the normal non-albino allele. If one out of every 10,000 people were albino and assuming that the population is in Hardy-Weinberg equilibrium, A. what would be the phenotype frequencies of albino and non-albino ? B. what would be the allele frequencies of a and of A? C. what fraction of people can be expected to be of the genotype Aa? D. what fraction of people can be expected to be of the genotype AA?arrow_forwardA total of 6500 North American Caucasians were blood typed for the MN locus, which is determined by two codominant alleles LM and LN. The following data were obtained: Blood Type M MN N a. 0.52, b. 0.23 a. 0.52, b. 0.12 0.48, 0.12 Number a. What is the allele frequency of LM in the population (LM=p) b. What is the genotypic frequency of LNLN? a. 0.48, b. 0.23 1800 3200 1500arrow_forward
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