COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 5, Problem 9QAP
To determine
Why is the minimum force required for moving bones in a typical knee joint different for different people, in spite of the fact that their joints have the same coefficient of friction
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Is the coefficient of
static
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the same for two
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Why?
In the figure below, a climber leans out against a vertical ice wall that has negligible friction. Distance a is 0.956 m and distance L is 2.00 m. His center of mass is distance d = 0.944 m from the
feet-ground contact point. If he is on the verge of sliding, what is the coefficient of static friction between feet and ground?
|---Select-- v
com-
Determine the force Prequired to force the 11° wedge under the 76-kg uniform crate which rests against the small stop at A. The
coefficient of friction for all surfaces is 0.30.
2.3 m
1.2 m
76 kg
A
1
11°
Answer: P =
Chapter 5 Solutions
COLLEGE PHYSICS
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- A rectangular block twice as high as it is wide is resting on a board. The coefficient of static friction between board and incline is 0.63. If the board’s inclination angle is gradually increased, will the block first tip over or first begin sliding?arrow_forward18E. (a) An 11.0 kg salami is supported by a cord that runs to a spring scale, which is supported by another cord from the ceiling (Fig. 5-43a). What is the reading on the scale? (b) In Fig. 5-43b the salami is supported by a cord that runs around a pulley and to a scale. The opposite end of the scale is attached by a cord to a wall. What is the reading on the scale? (c) In Fig. 5-43c the wall has been replaced with a second 1.0 kg salami on the left, and the assembly is stationary, What is the reading on the scale now? Spring scale Spring scale 11 kg (b) Spring scale I1 kg (a) 11 kg 11 kg (6)arrow_forwardEX) The uniform crate shown in fig: has a mass of 20 kg. boX IF force P= 80 N is applied to the crate, determine if i remains in equilibrium. The coefficient of static Friction is 0:3 (M=0:3) P= 80N 0.8M Sol) 30° 20 Kg EFx=0>80 Cos 30-F = 0 0.2marrow_forward
- Logs weighing 1.3 kg and 2.2 kg lie on a flat surface and are connected by a rope that breaks at a force of 20 N. The coefficient of friction between the lighter log and the base is 0.50, and between the heavier log and the base 0.30. With what maximum force can we pull the lighter log so that the string does not break?arrow_forwardThe upper half of an inclined plane of inclination 0 is perfectly smooth while lower half is rough. A block starting from rest at the top of the plane will again come to rest at the bottom, if the coefficient of friction between the block and lower half of the plane is given by -arrow_forwardJamal and Dayo are lifting a large chest, weighing 207 lb, by using the two rope handles attached to either side. As they lift and hold it up so that it is motionless, each handle makes a different angle with respect to the vertical side of the chest (Fig. P5.76). If the angle between Jamals handle and the vertical side is 25.0 and the angle between Dayos handle and the vertical side of the chest is 30.0, what are the tensions in each handle? FIGURE P5.76arrow_forward
- We know from studying friction forces that static friction increases with increasing normal force between the surfaces, which becomes important for vehicles traveling on icy or snowy roads that have coefficients of static friction much smaller than those of dry pavement. In particular, the greater the normal force on the drive wheels (those coupled to the engine), the better the traction. The horizontal position of the center of mass of a typical compact automobile is located 1.1 m toward the rear as measured from the front wheel axle. The wheelbase (distance from the front wheel axle to the rear wheel axle) is 2.7 m. Assume the car is stationary on level ground and has a weight of 12,000 N. Determine the total normal force on the two front tires and on the two rear tires. Which do you suppose are the drive wheels in this case?arrow_forwardIf you hold a horizontal metal bar several centimeters above the ground and move it through grass, each leaf of grass bends out of the way. If you increase the speed of the bar, each leaf of grass will bend more quickly. How then does a rotary power lawn mower manage to cut grass? How can it exert enough force on a leaf of grass to shear it off?arrow_forwardThis problem returns to the tightrope walker studied in Example 4.6, who created a tension of 3.94103 N in a wire making an angle 5.0° below the horizontal with each supporting pole. Calculate how much this tension stretches the steel wire if it was originally 15 m long and 0.50 cm in diameter.arrow_forward
- The base of an automobile jackstand forms an equilateral triangle of side length 12 in. and is centered under the collar A. Model the structure as one with a ball and socket at each joint and determine the force in members BC, BD, and CD. The forces are positive if in tension, negative if in compression. Neglect any horizontal reaction components under the feet B, C, and D. Assume F-700 lb, b-12 in., h-17 in. Answers: BC- i BD= i CD- i lb lb lbarrow_forward--A 535-g squirrel with a surface area of 935 cm2 falls from a 6.0-m tree to the ground. Estimate its terminal velocity. (Use the drag coefficient for a horizontal skydiver. Assume that the squirrel can be approximated as a rectanglar prism with cross-sectional area of width 11.6 cm and length 23.2 cm. Note, the squirrel may not reach terminal velocity by the time it hits the ground. a-Give the squirrel's terminal velocity, not it's velocity as it hits the ground.)____ m/sb-What will be the velocity of a 53.5-kg person hitting the ground, assuming no drag contribution in such a short distance? ____m/sarrow_forwardProblem 2: Determine the force P necessary to start the V-shaped wedge to the right if the coefficient of friction is f= 0.445 at each of the three surfaces of contact. Wg =1000N WA =200N в P- 30° 150arrow_forward
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