COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 5, Problem 87QAP
To determine
The tension in the string and the speed of circular motion of the smaller object.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
The block at point A is released from rest on a smooth track, which is one quadrant of a circle of radius 5m. It continues to move along a rough surface from point B to E and acquires a velocity of 8.6 m/s at point C. If its velocity at E is 2.25 m/s, calculate: a) velocity at B b) the coefficient of friction between the block and the surface B to E c) mass of the block, if the loss in KE between points D to C is 24.05 J d) velocity at D e) distance DE
What is your apparent weight as you drive over the top of this hill, in terms of the
given information.
Given information:
• R (radius of curvature of the road)
m (mass of the driver)
M. (mass of the car)
Car is traveling at constant speed
Car is traveling at 3/4 the maximum
speed possible without losing
R
contact with the road
g (acceleration of gravity)
• Car is a Tesla, it is white in color
A string can support a stationary hanging load of mass
25 kg before breaking. a) Calculate the maximum tension
that the string can support. b) Suppose one end of the
string is attached to an object of mass m = 3 kg, while the
other end is fixed to the center of a frictionless table as
shown in the figure. When given an initial speed, the object
moves along a horizontal circle of radius R = 0.8 m.
Calculate the maximum speed the object can have before
the string breaks.
Chapter 5 Solutions
COLLEGE PHYSICS
Ch. 5 - Prob. 1QAPCh. 5 - Prob. 2QAPCh. 5 - Prob. 3QAPCh. 5 - Prob. 4QAPCh. 5 - Prob. 5QAPCh. 5 - Prob. 6QAPCh. 5 - Prob. 7QAPCh. 5 - Prob. 8QAPCh. 5 - Prob. 9QAPCh. 5 - Prob. 10QAP
Ch. 5 - Prob. 11QAPCh. 5 - Prob. 12QAPCh. 5 - Prob. 13QAPCh. 5 - Prob. 14QAPCh. 5 - Prob. 15QAPCh. 5 - Prob. 16QAPCh. 5 - Prob. 17QAPCh. 5 - Prob. 18QAPCh. 5 - Prob. 19QAPCh. 5 - Prob. 20QAPCh. 5 - Prob. 21QAPCh. 5 - Prob. 22QAPCh. 5 - Prob. 23QAPCh. 5 - Prob. 24QAPCh. 5 - Prob. 25QAPCh. 5 - Prob. 26QAPCh. 5 - Prob. 27QAPCh. 5 - Prob. 28QAPCh. 5 - Prob. 29QAPCh. 5 - Prob. 30QAPCh. 5 - Prob. 31QAPCh. 5 - Prob. 32QAPCh. 5 - Prob. 33QAPCh. 5 - Prob. 34QAPCh. 5 - Prob. 35QAPCh. 5 - Prob. 36QAPCh. 5 - Prob. 37QAPCh. 5 - Prob. 38QAPCh. 5 - Prob. 39QAPCh. 5 - Prob. 40QAPCh. 5 - Prob. 41QAPCh. 5 - Prob. 42QAPCh. 5 - Prob. 43QAPCh. 5 - Prob. 44QAPCh. 5 - Prob. 45QAPCh. 5 - Prob. 46QAPCh. 5 - Prob. 47QAPCh. 5 - Prob. 48QAPCh. 5 - Prob. 49QAPCh. 5 - Prob. 50QAPCh. 5 - Prob. 51QAPCh. 5 - Prob. 52QAPCh. 5 - Prob. 53QAPCh. 5 - Prob. 54QAPCh. 5 - Prob. 55QAPCh. 5 - Prob. 56QAPCh. 5 - Prob. 57QAPCh. 5 - Prob. 58QAPCh. 5 - Prob. 59QAPCh. 5 - Prob. 60QAPCh. 5 - Prob. 61QAPCh. 5 - Prob. 62QAPCh. 5 - Prob. 63QAPCh. 5 - Prob. 64QAPCh. 5 - Prob. 65QAPCh. 5 - Prob. 66QAPCh. 5 - Prob. 67QAPCh. 5 - Prob. 68QAPCh. 5 - Prob. 69QAPCh. 5 - Prob. 70QAPCh. 5 - Prob. 71QAPCh. 5 - Prob. 72QAPCh. 5 - Prob. 73QAPCh. 5 - Prob. 74QAPCh. 5 - Prob. 75QAPCh. 5 - Prob. 76QAPCh. 5 - Prob. 77QAPCh. 5 - Prob. 78QAPCh. 5 - Prob. 79QAPCh. 5 - Prob. 80QAPCh. 5 - Prob. 81QAPCh. 5 - Prob. 82QAPCh. 5 - Prob. 83QAPCh. 5 - Prob. 84QAPCh. 5 - Prob. 85QAPCh. 5 - Prob. 86QAPCh. 5 - Prob. 87QAPCh. 5 - Prob. 88QAPCh. 5 - Prob. 89QAPCh. 5 - Prob. 90QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Two ocean liners, each with a mass of 40 000 metric tons, are moving on parallel courses 100 m apart. What is the magnitude of the acceleration of one of the liners toward the other due to their mutual gravitational attraction? Model the ships as particles.arrow_forwardQ1) Circular motionA carnival ride has people stand inside a vertical cylinder with theirbacks to the wall. The cylinder starts spinning counterclockwise and theriders find that they are “stuck” to the wall and don’t slide down, evenwhen the floor is removed.The ride has a radius of r. The person has a mass of m and is movingwith a constant speed of v. The coefficient of static friction between theperson and the wall is μs , and kinetic friction μk. The person is onlytouching the wall, not touching the floor.a) Draw a free body diagram for the person when they are on the left-hand side, as shown.Clearly label all forces. Use the notation used in class.b) What is the magnitude and direction of the acceleration of the person?Give your answer in terms of variables only (r, v, m, μs, μk, and g)c) What is the magnitude of the normal force of the wall on the person?Solve this problem using Newton’s 2nd Law. Show all your work.Give your answer in terms of variables only (r, v, m, μs, μk, and…arrow_forwardDriving in your car with a constant speed of v = 22 m/s, you encounter a bump in the road that has a circular cross-section, as indicated in the figure (Figure 1). Part A For the steps and strategies involved in solving a similar problem, you may view the following Quick Example 6-17 video: If the radius of curvature of the bump is 52 m, find the apparent weight of a 66-kg person in your car as you pass over the top of the bump. SOLUTION Express your answer in newtons. We use Newton's secend lew 2R, = may ? Wa = Submit Request Answer Provide Feedback Figurearrow_forward
- 92. •A curve that has a radius of 100 m is banked at an angle of 10° (Figure 5-42). If a 1000-kg car navigates the curve at 65 km/h without skidding, what is the mini- mum coefficient of static friction between the pavement and the tires? 10 Figure 5-42 Problem 92arrow_forwardQuestion 2 - Go Kart Track Your go karts have a mass of 450kg and travel around a circular curve on a flat, horizontal track at a radius of 42 m. a) Draw a diagram to show the go kart on the track and add an arrow to show the direction of the frictional force needed for the car to travel around the curve at a radius of 42 m. b) The maximum frictional force between the tyres and the road is equal to 20% of the weight of the car and driver. Calculate the coefficient of friction when an adult of mass 70kg is driving the kart. c) Calculate maximum angular velocity at which the car can travel round the curve at a constant radius of 42 m.arrow_forward4) An air-hockey puck of mass m spins in a circle without friction around a central hole at constant speed v. The entire string has total length 3h. The horizontal portion of the string has length h, the vertical part of the string has length 2h. A block of relative mass 3m hangs from the same string, providing the tension necessary to stabilize the spinning puck. What is the speed v of the puck? A)V3gh/2 B) Vgh/3 C) Vgh/2 XD) Bgh E) V2gh F) gh m 2h Зтarrow_forward
- 3) You tie a small rock of mass m to the end of a string of radius r and start to twirl it about your head. By making your hand move in a very small circle so it is always pulling slightly forward on the rock you are able to continuously apply a force of F to the rock in the tangential direction. Ignore the fact that the rock is always a bit lower than your hand so you can make the approximation that the string is always level. a) Find the linear acceleration of the rock, and find its velocity as a function of time. b) Make a drawing showing the tangential acceleration vector atand any other acceleration vectors.Find the magnitude of the total acceleration of the rock (as a function of time). c) The string breaks when the tension on it exceeds Tm. What would the total acceleration need to be to make it break, in terms of just Tm and m?d) Find the time tm at which the string breaksarrow_forward16. A 0.50-kg object moves on a horizontal frictionless circular track with a radius of 2.5 m. An external force of 3.0 N, always tangent to the track, causes the object to speed up as it goes around. If it starts from rest, then at the end of one revolution the radial component of the force of the track on it is: A) 19 N B) 38 N C) 47 N D) 75 N E) 96 N 17. A 1.5 kg crate falls from a height of 2.0 m onto an industrial spring scale with a spring constant of 1.5x10° N/m. At its greatest compression the reading on the scale is: A) 15 N B) 30 N C) 1.5x103 N D) 2.1x103N E) 3.0x103 Narrow_forward1) A car moving at 12.0 m/s tries to negotiate a corner in a circular roadway of radius 15.0 m. The roadway is flat. a) Draw a free body diagram for the car as it makes this circular turn. b) Derive the algebraic expression for the coefficient of friction between the wheels and the road if the car is to not skid? c) How does the mass of the car affect the coefficient of friction? d) Calculate the coefficient of friction.arrow_forward
- Skidding in a Curve A car is traveling on a curve that forms a circular arc. The force F needed to keep the car from skid- ding is jointly proportional to the weight w of the car and the square of its speed s and is inversely proportional to the radius r of the curve. (a) Write an equation that expresses this variation. (b) A car weighing 1600 lb travels around a curve at 60 mi/h. The next car to round this curve weighs 2500 lb and requires the same force as the first car to keep from skidding. How fast is the second car traveling?arrow_forward3) A ball of mass m = 1.34 kg is rotated around a rod as shown in the figure. The length (L) of the ropes to which the mass is attached and the distance (d) between the tie points of the ropes is 1.7 m‘. During this movement where friction is neglected, if the tension on the upper rope is 35 N: a) How many N N is the tension in the lower rope? b) What is the magnitude of the net force on the mass? c) What is the speed of the mass?arrow_forwardWhy do you feel thrown to the outside when a car in which you are riding goes around a curve, even though there is no force acting on you in that direction? simple explanationarrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...PhysicsISBN:9781305116399Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Newton's Second Law of Motion: F = ma; Author: Professor Dave explains;https://www.youtube.com/watch?v=xzA6IBWUEDE;License: Standard YouTube License, CC-BY