COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 10QAP
To determine
Whether there is a contradiction of the situations which at low speeds the drag force on an object moving through a fluid is proportional to its velocity and according to Newton's law, force is proportional to acceleration.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A car is a height of 1.6 meters and width of 2 meters. (the length is immaterial). The following is an actual excerpt from the manufacturers specifications:
Fuel capacity: 51 liters/ 13.5 US gal/ 11.2 gal
Drag coefficient 0.42 (at highway speed)
a) If I am driving at 100 km/hr through air what is the drag force on the car. Note this is the same as if the car were stationary in at 100 km/hr wind. Air density is 1.2 kg/m^3 viscosity is 0.018 cp
A ballon is being pushed upwards by the force of the hot air inside it. If the ballon has a mass of 250 kg, how much force is needed to accelerate it upwards at 0.3 m/s^2? (This question was already answered, don't answer)The balloon from the other question is getting too high. You grab a rope hanging from it and pull it down. Using the same conditions and information, how hard would you have to pull on it to bring it back down at a constant speed? (answer this one)
After an annual checkup, you leave your physician's office, where you weighed 714.76 N. You then get into an
elevator that, conveniently, has a scale. Compute for the reading of the weighing scale in Newtons if the
acceleration of the elevator is 0.87 m/s^2. (kindly take note of the sign of the acceleration. if the acceleration
is positive it is directed upward, if the acceleration is negative it is directed downward)
(express your answer in 2 decimal places)
Chapter 5 Solutions
COLLEGE PHYSICS
Ch. 5 - Prob. 1QAPCh. 5 - Prob. 2QAPCh. 5 - Prob. 3QAPCh. 5 - Prob. 4QAPCh. 5 - Prob. 5QAPCh. 5 - Prob. 6QAPCh. 5 - Prob. 7QAPCh. 5 - Prob. 8QAPCh. 5 - Prob. 9QAPCh. 5 - Prob. 10QAP
Ch. 5 - Prob. 11QAPCh. 5 - Prob. 12QAPCh. 5 - Prob. 13QAPCh. 5 - Prob. 14QAPCh. 5 - Prob. 15QAPCh. 5 - Prob. 16QAPCh. 5 - Prob. 17QAPCh. 5 - Prob. 18QAPCh. 5 - Prob. 19QAPCh. 5 - Prob. 20QAPCh. 5 - Prob. 21QAPCh. 5 - Prob. 22QAPCh. 5 - Prob. 23QAPCh. 5 - Prob. 24QAPCh. 5 - Prob. 25QAPCh. 5 - Prob. 26QAPCh. 5 - Prob. 27QAPCh. 5 - Prob. 28QAPCh. 5 - Prob. 29QAPCh. 5 - Prob. 30QAPCh. 5 - Prob. 31QAPCh. 5 - Prob. 32QAPCh. 5 - Prob. 33QAPCh. 5 - Prob. 34QAPCh. 5 - Prob. 35QAPCh. 5 - Prob. 36QAPCh. 5 - Prob. 37QAPCh. 5 - Prob. 38QAPCh. 5 - Prob. 39QAPCh. 5 - Prob. 40QAPCh. 5 - Prob. 41QAPCh. 5 - Prob. 42QAPCh. 5 - Prob. 43QAPCh. 5 - Prob. 44QAPCh. 5 - Prob. 45QAPCh. 5 - Prob. 46QAPCh. 5 - Prob. 47QAPCh. 5 - Prob. 48QAPCh. 5 - Prob. 49QAPCh. 5 - Prob. 50QAPCh. 5 - Prob. 51QAPCh. 5 - Prob. 52QAPCh. 5 - Prob. 53QAPCh. 5 - Prob. 54QAPCh. 5 - Prob. 55QAPCh. 5 - Prob. 56QAPCh. 5 - Prob. 57QAPCh. 5 - Prob. 58QAPCh. 5 - Prob. 59QAPCh. 5 - Prob. 60QAPCh. 5 - Prob. 61QAPCh. 5 - Prob. 62QAPCh. 5 - Prob. 63QAPCh. 5 - Prob. 64QAPCh. 5 - Prob. 65QAPCh. 5 - Prob. 66QAPCh. 5 - Prob. 67QAPCh. 5 - Prob. 68QAPCh. 5 - Prob. 69QAPCh. 5 - Prob. 70QAPCh. 5 - Prob. 71QAPCh. 5 - Prob. 72QAPCh. 5 - Prob. 73QAPCh. 5 - Prob. 74QAPCh. 5 - Prob. 75QAPCh. 5 - Prob. 76QAPCh. 5 - Prob. 77QAPCh. 5 - Prob. 78QAPCh. 5 - Prob. 79QAPCh. 5 - Prob. 80QAPCh. 5 - Prob. 81QAPCh. 5 - Prob. 82QAPCh. 5 - Prob. 83QAPCh. 5 - Prob. 84QAPCh. 5 - Prob. 85QAPCh. 5 - Prob. 86QAPCh. 5 - Prob. 87QAPCh. 5 - Prob. 88QAPCh. 5 - Prob. 89QAPCh. 5 - Prob. 90QAP
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Physics Review A soap bubble hovers motionlessly in the air. If the soap bubbles mass, including the air inside it, is 2.00 104 kg determine the magnitude of the upward force acting on it. (See Section 4.5.)arrow_forwardA suspended mass of 20 grams located at 210° in the force table is the same as:arrow_forwardAs relative velocity goes down , the fluid force acting on an object decreases linearly. is this true or false ?arrow_forward
- . Estimate the speed at which the drag on a 150-g steel ball becomes equal to about 1% of its weight. (The density of steel is about 7900 kg/m3, and C for a sphere is about equal to 0.5.) Take the density of air to be 1.2 kg/m3. The speed is ______m/s.arrow_forwardAn airplane in flight is subject to an air resistanceforce proportional to the square of its speed v. But there is an additionalresistive force because the airplane has wings. Air flowing over thewings is pushed down and slightly forward, so from Newton’s third lawthe air exerts a force on the wings and airplane that is up and slightlybackward (Fig.). The upward force is the lift force that keeps theairplane aloft, and the backward force is called induced drag. At flyingspeeds, induced drag is inversely proportional to v2, so the total airresistance force can be expressed by Fair = av2 + b/v2, where a andb are positive constants that depend on the shape and size of the airplaneand the density of the air. For a Cessna 150, a small single-engineairplane, a = 0.30 N . s2/m2 and b = 3.5 * 105 N . m2/s2. In steadyflight, the engine must provide a forward force that exactly balances theair resistance force. (a) Calculate the speed 1in km>h2 at which this airplanewill have the maximum…arrow_forwardAn airplane in flight is subject to an air resistance force proportional to the square of its speed v. But there is an additional resistive force because the airplane has wings. Air flowing over the wings is pushed down and slightly forward, so from Newton’s third law the air exerts a force on the wings and airplane that is up and slightly backward. The upward force is the lift force that keeps the airplane aloft, and the backward force is called induced drag. At flying speeds, induced drag is inversely proportional to v 2 , so that the total air resistance force can be expressed by Fair = av2 + b/v2 where a and b are positive constants that depend on the shape and size of the airplane and the density of the air. For a Cessna 150, a small single-engine airplane, a = 0.30 N.s2 /m2 and b = 3.5×105 N.m2 /s 2 . In steady flight, the engine must provide a forward force that exactly balances the air resistance force. 1. Calculate the speed (in km/h) at which this airplane will have the…arrow_forward
- The drag force, Fa, imposed by the surrounding air on a vehicle moving with velocity Vis given by Fa Ca ApV²/2 where Ca is a constant called the drag coefficient, A is the projected frontal area of the vehicle, and p is the air density. An automobile is moving at V = 40 miles per hour with C = 0.28, A = 24 ft², and p = 0.075 lb/ft³. Determine the force, in lbf, and the power, in hp, required to overcome aerodynamic drag.arrow_forward42. A block initially at rest slides down a ramp of length L that makes an angle of θ with the horizontal. (a) Derive an equation that predicts the time required for the block to reach the bottom of the ramp in terms of L, θ, g, and μ, the coefficient of friction. (b) This derived equation has no real solutions for angles θ ≤ tan–1 (μ). Show algebraically this is the case and explain the physical significance of this – i.e. what does this mean about an actual block on an actual ramp with actual friction?arrow_forwardThe terminal velocity of a human being is 200 km/hr, and it takes about 12 seconds to achieve this. This calculation considers for air friction of course. What would a person’s speed be if they free fell for 12 seconds instead (no air friction present)?arrow_forward
- A 170-kg granite rock (r = 2700 kg/m3) is dropped into a lake. A man dives in and tries to lift the rock. Determine how much force the man needs to apply to lift it from the bottom of the lake. Do you think he can do it?arrow_forwardA man was originally walking at 1.5 m/s and then reaches a speed of 8.1 m/s in 2.4 s. He estimated that his coefficient of friction was 0.30. Was it above or below this value?arrow_forwardDetermine the unbalanced force acting on an iron ball (r = 1.5 cm, p= 7.8 g/cm) when just released while totally immersed in (a) water and (b) mercury (p = 13.6 g/cm). What will be the initial acceleration of the Ans. (a) 0.94 N down, 8.6 m/s down; (b) 0.80 N up, 7.3 m/s up %3D ball in each case?arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781938168000Author:Paul Peter Urone, Roger HinrichsPublisher:OpenStax College
- An Introduction to Physical SciencePhysicsISBN:9781305079137Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar TorresPublisher:Cengage LearningCollege PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
An Introduction to Physical Science
Physics
ISBN:9781305079137
Author:James Shipman, Jerry D. Wilson, Charles A. Higgins, Omar Torres
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Newton's First Law of Motion: Mass and Inertia; Author: Professor Dave explains;https://www.youtube.com/watch?v=1XSyyjcEHo0;License: Standard YouTube License, CC-BY