Modern Physics for Scientists and Engineers
4th Edition
ISBN: 9781133103721
Author: Stephen T. Thornton, Andrew Rex
Publisher: Cengage Learning
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Textbook Question
Chapter 4, Problem 8P
What fraction of 5-MeV α particles will be scattered through angles greater than 8° from a gold foil (Z = 79, density = 19.3 g/cm3) of thickness 10−8 m?
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What fraction of 5-MeV - particles will be scattered through angles greater than 8° from a gold foil (Z = 79, density=19.3 g/cm3) of thickness 10-8 m?
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Question 2 (1) Assume that the average energy of β-rays (electrons) emitted from the S-ray source is 0.8 MeV, and the average ionization energy of gas molecules (atoms) in the GM counter tube is about 30 eV. Find the number of gas molecules ionized when one electron enters the GM tube (1MeV = 10°eV). (2) Assuming that the electrons and cations thus generated are attracted to the electrode as they are, what is the total amount of negative charge generated by ionization in C (coulombs)? (3) If this ionization takes 10-4s, what is the current flowing through the anode?
Find the fraction of 7.7-MeV α particles that is deflected at an angle of 90° or more from a gold foil of 10 -6 m thickness.
Chapter 4 Solutions
Modern Physics for Scientists and Engineers
Ch. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4QCh. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10Q
Ch. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - What fraction of 5-MeV α particles will be...Ch. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61P
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- = = Imagine that we have a box that emits electrons in a definite but unknown spin state y). If we send electrons from this box through an SGz device, we find that 20% are determined to have Sz +ħ and 80% to have S₂ -ħ. If we send electrons from this box through an SGx device, we find that 90% are determined to have Sx +ħ and 10% to have Sx Determine the state vector for electrons emerging from the box. You may assume that the vector components are real. -1/ħ. = -arrow_forwardA beam of 8.0-MeV - particles scatters from a thin gold foil. What is the ratio of the number of ∝ particles scattered to angles greater than 1° to the number scattered to angles greater than 2°?arrow_forwardCalculate the fraction per mm2 area of 7.7-MeV α particles scattered at 45° from a gold foil of thickness 2.1 x 10 -7 m at a distance of 1.0 cm from the target.arrow_forward
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- Measured X-ray energies for Silver (Z=47) are: K_alpha= 21.990 keV, K_beta=25.145. The binding energy of the K shell electron in Silver is 25.514 keV. Using these find the energy of L_alpha X-ray and binding energy of the L electron.arrow_forwardIn a scattering experiment, you concentrate on Alpha particles with impact parameters b=0, 1×10^-3, and 1×10^0 mm. For which b will the behavior of the Alpha particle be very different in Thomson's and Rutherford's models and for which will it be nearly similar?arrow_forwardA beam of α particles of kinetic energy E = 10 MeV and intensity I = 1 μ A hits a lead target [A = 207, Z = 82, ρ = 1.14 x 104 kg m-3] of thickness t = 0.2 mm. We locate a counter of area S = 1 cm2 at a distance of l = 0.5 m beyond the target at the angle θ = 40°. Neglecting, when necessary, the variation of the angle on the detector find: (a) the number of incident particles per second Ri, (b) the solid angle ΔΩ under which the target sees the detector, (c) the differential cross-section at the detector, and (d) how many hits the detector counts per second.arrow_forward
- The Ka X-ray emission line of tungsten occurs at λ = 0.021 nm. The energy difference between K and L levels in this atoms is about (a) 0.51 MeV (b) 1.2 MeV (c) 59 keV (d) 13.6 eVarrow_forwardWhat is the energy of H2 trapped in a zeolite, which can be modeled by a particle in a cube given nX = 10, nY = 10, nZ = 10 and LX = LY = LZ = 10−9 m.arrow_forwardIn an experiment done by scattering 5.5-MeV a particles from a thin gold foil, students find that 10,000 a particles are scattered at an angle greater than 50⁰. (a) How many of these particles will be scattered greater than 110°? particles (b) How many will be scattered between 58° and 76°? particlesarrow_forward
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