Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n 3 / 2 R .

Question

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Answer 1

Question

Chapter 4, Problem 60P

(a)

To determine

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

(b)

To determine

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

(c)

To determine

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

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Students have asked these similar questions

·Shown here is the visible part of the spectrum of some gas. There are 11 lines. There could be 6. more, they just aren't in the wavelength range of the spectrum. The wavelength increases toward the right. :.. de f gh k (a) Which line or lines correspond(s) to the two closest spaced energy levels? Explain. (b) Which line or lines correspond(s) to the two farthest spaced energy levels? Explain. (c) What is the minimum number of energy levels in an atom of the gas that could produce the lines in this spectrum? Explain.

Consider a hydrogen atom. Show the calculation of the wavelength of the light emitted when an electron drops from the n=3 to the n=2 state, to four significant figures. Important, start with the energies of these states in your calculation, to four significant figures. Do not use Rydberg shortcut.

Which one of the following statements about the exchange energy of the few lowest excited states of helium, in which the two electrons are in different subshells, is incorrect? Select an answer and submit. For keyboard navigation, use the up/down arrow keys to select an answer. b с d e In the absence of the exchange energy, the degeneracy between 1s¹2s¹ and 1s¹2p¹ configurations would only be lifted by relativistic corrections. For a given configuration and L the exchange energy favours (ie the energy is lower for) S-1 compared with S=0 O For a given configuration and L the exchange energy favours states that are spatially anti-symmetric The exchange energy gives larger shifts in the levels than relativistic corrections L, S remain good quantum numbers in the presence of the exchange energy

Answer 2

Question

Chapter 4, Problem 60P

(a)

To determine

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

(b)

To determine

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

(c)

To determine

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

Expert Solution & Answer

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Answer 3

Question

Chapter 4, Problem 60P

(a)

To determine

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

(b)

To determine

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

(c)

To determine

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

Expert Solution & Answer

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See solution

Answer 4

Question

Chapter 4, Problem 60P

(a)

To determine

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

(b)

To determine

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

(c)

To determine

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

Expert Solution & Answer

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Answer 5

Chapter 4, Problem 60P

(a)

To determine

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

(b)

To determine

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

(c)

To determine

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

Answer 6

Chapter 4, Problem 60P

(a)

To determine

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

Answer 7

Chapter 4, Problem 60P

(a)

To determine

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

Answer 8

(b)

To determine

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

Answer 9

(b)

To determine

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

Answer 10

(c)

To determine

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

Answer 11

(c)

To determine

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

Answer 12

Expert Solution & Answer

Answer 13

Expert Solution & Answer

Answer 14

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Answer 15

Ch. 4 - Prob. 1Q Ch. 4 - Prob. 2Q Ch. 4 - Prob. 3Q Ch. 4 - Prob. 4Q Ch. 4 - Prob. 5Q Ch. 4 - Prob. 6Q Ch. 4 - Prob. 7Q Ch. 4 - Prob. 8Q Ch. 4 - Prob. 9Q Ch. 4 - Prob. 10Q

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n 3 / 2 R .

Solution Summary: The author explains how the binomial expansion shows that the transition produces a photon with wavelength approximately n3/2R.

Concept explainers

Start with Equation (4.30) use the binomial expansion to show that this transition produces a photon with wavelength approximately n3/2R.

Obtain the same result as in part (a), this time start with Equation (4.25) and compute dE/dn .

Using the approximate expression you derived in (a) and (b) compute the wavelength for a transition from n=101 to n=100 in hydrogen and compare the answer with the exact wavelength for this transition computed using equation (4.30).

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Chapter 4 Solutions