Modern Physics for Scientists and Engineers
4th Edition
ISBN: 9781133103721
Author: Stephen T. Thornton, Andrew Rex
Publisher: Cengage Learning
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Chapter 4, Problem 28P
(a)
To determine
The visible absorption spectra for a hydrogen atom.
(b)
To determine
The visible absorption spectra for an ionized helium atom
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Describe the visible absorption spectra for (a) a hydrogen atom and (b) an ionized helium atom, He+.
A photoelectron is emitted from K shell (n = 1) of a carbon atom, and an election in L shell (n = 2) moves down to the vacancy in K shell. What is the wavelength, in the unit of nm, of the photon emitted during this transition?
Use for the energy difference between two states in an atom.
E0 = 13.6 eV and atomic number of carbon is Z = 12.
Use σ = 1 for the transition to K shell and σ = 7.4 for the transition to L shell
Compare the Balmer series of hydrogen with the series where n ℓ= 4 for the ionized helium atom He+. What is the difference between the wavelengths of the L ∝ and Lℓ line of hydrogen and the nu = 6 and 8 of He+? Is there a wavelength of the Balmer series that is very similar to any wavelength values where n ℓ = 4 in He+? Explain.
Chapter 4 Solutions
Modern Physics for Scientists and Engineers
Ch. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4QCh. 4 - Prob. 5QCh. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10Q
Ch. 4 - Prob. 11QCh. 4 - Prob. 12QCh. 4 - Prob. 13QCh. 4 - Prob. 2PCh. 4 - Prob. 3PCh. 4 - Prob. 4PCh. 4 - Prob. 5PCh. 4 - Prob. 6PCh. 4 - Prob. 7PCh. 4 - What fraction of 5-MeV α particles will be...Ch. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44PCh. 4 - Prob. 45PCh. 4 - Prob. 46PCh. 4 - Prob. 47PCh. 4 - Prob. 48PCh. 4 - Prob. 49PCh. 4 - Prob. 50PCh. 4 - Prob. 51PCh. 4 - Prob. 52PCh. 4 - Prob. 54PCh. 4 - Prob. 55PCh. 4 - Prob. 56PCh. 4 - Prob. 57PCh. 4 - Prob. 59PCh. 4 - Prob. 60PCh. 4 - Prob. 61P
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- The light observed that is emitted by a hydrogen atom is explained by a simple model of its structure with one proton in its nucleus and an electron bound to it, but only with internal energies of the atom satisfying EH=−RH/n2EH=−RH/n2 where RHRH is the Rydberg constant and nn is an integer such as 1, 2, 3 ... and so on. When a hydrogen atom in an excited state emits light, the photon carries away energy and the atom goes into a lower energy state. Be careful about units. The Rydberg constant in eV is 13.605693009 eV That would be multiplied by the charge on the electron 1.602× 10-19 C to give 2.18× 10-18 J A photon with this energy would have a frequency f such that E=hf. Its wavelength would be λ = c/f = hc/E. Sometimes it is handy to measure the Rydberg constant in units of 1/length for this reason. You may see it given as 109737 cm-1 if you search the web, so be aware that's not joules. The following questions are intended to help you understand the connection between…arrow_forwardQ) A hydrogen atom is initially in the ground state, (i.e., n = 1 level), absorbed a photon, and as a result of this absorption, a transition occurred for the electron and ended at the n = 4 level. A- What is the frequency of the photon? *arrow_forwardThe allowed energies of a simple atom are 0.00 eV. 4.12 eV, and 6.44 eV. ▼ Part A What wavelengths appear in the atom's emission spectrum? Enter your answers in ascending order separated by commas. 195] ΑΣΦ ? nm Request Answer Part B What wavelengths appear in the atom's absorption spectrum? Enter your answers in ascending order separated by commas. 195] ΑΣΦ ? nm Submit Submit Request Answerarrow_forward
- What is the difference in energy between two states (n = 1; n = 2) of the Fe atom that originates this transition? What is the corresponding energy difference for the hydrogen atom? use this equation to calculate the energy difference ΔΕ 327²e}h’n²arrow_forwardTutorial Week 15 1. Find the amount of energy needed in the transition of hydrogen electrons into higher orbits (total of three), absorbing photons which have wavelengths of (1) 1005 nm (2) 1282 nm and (3) 1875 nm. 2. Determine the longest and shortest wavelengths of the Lyman series. 3. Suppose the initial amount of Cesium-137 is 1.5 kg, find the amount of Cesium-137 remain after 1000 years.arrow_forwardH-alpha line is a red visible spectral line in hydrogen atom with a wavelength of 656.3 nm. Consider five distant stars labeled A, B, C, D, and E. The light from these starts was detected on Earth and, after performing spectral analysis, the following H-alpha wavelengths were measured: A = 665.5 nm, AB = 643.7 nm, Ac = 653.9 nm, Ap = 663 nm, and AE = 661.2 nm. Which star has the slowest speed relative to Earth, in which direction and how fast does it move? ✓ Earth. The slowest star is CV and it moves towards The speed of the slowest star (in km/s), Vslowest Which star has the fastest speed relative to Earth, in which direction and how fast does it move? The fastest star is B ✓ and it moves towards = -1.095E12 X Units km/s The speed of the fastest star (in km/s), Vfastest = -5.73E6 Earth. x Units km/sarrow_forward
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