Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Chapter 19, Problem 19.5P
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In the Bolted Connection shown, find the following by ASD.Specifications:M20 Bolts in standard holes. Nominal hole diameter = 22mmEffective Hole diameter = nominal hole diameter + 2 mmA325 steel boltAssume thread in shear planeFv = 372 MPaProperties of Angle Bar< 125 x 125 x 13 mmA = 3065 mm²x = 36.3 mmy = 36.3 mmFy = 248 MPa , Fu = 410 MPa
1. For angle bars used as bolted tension element connected to another element only on one leg, the effective area Ae = UAn. Where: An = Net area, U = Shear lag factor = 1 – x/L, L= center to center longitudinal distance of extremely located fasteners, X= distance from centroid of angle bar to surface of contact of joined elements. What is the shear lag factor of our angular bar?
a. 0.454
b. 0.9
c. 0.838
d. 0.869
2. Considering RUPTURE of angle bar, what is the allowable force P that the connection can handle if allowable RUPTURE stress in net area of angle bar is Fu/2
a. 463.83 kN…
Problem 1:
The pin in a Box-Pin coupling is acted upon by a force (F), that varies as random
variable due to misalignment as (2, 0.08) kN. The load act at a distance (1) that
varies as (25 ± 3) mm. The diameter of the pin (D) is 18 mm. The fillet radius at
the pin shoulder is about 1.5 mm. The stress concentration factor due to fatique
in bending is thus a random variable kb that could vary from 1.3 to 1.5. The pin
is made of steel AISI 4340 with mean endurance strength in bending of 400 MPa,
and a standard deviation of 25 MPa. Determine the pin diameter (d), if one pin
in every 10000 may be permitted to fail.
R1.6 O
L
Problem (1)
The width of the belt used if its thickness is 6 mm.
Ans. 261 mm
8. A nylon-core flat belt has an elastomer envelop; is 200 mm wide, and transmits 60 KW at a belt speed
of 25 m/s. The belt has a mass of 2 kg/m of the belt length. The belt is used in a crossed configuration to
connect a 300 mm diameter driving pulley to a 900 mm diameter driven pulley at a shaft spacing of 6 m.
A. Calculate the belt length and the angles of wrap. Ans. 13.95 m, 3.34 rad or 191.4°
B. Compute the belt tensions based on a coefficient of friction of 0.33. Ans. 1.76 KN, 1.96 KN
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
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