Applied Statics and Strength of Materials (6th Edition)
6th Edition
ISBN: 9780133840544
Author: George F. Limbrunner, Craig D'Allaird, Leonard Spiegel
Publisher: PEARSON
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Textbook Question
Chapter 19, Problem 19.11P
A fillet weld between two steel plates intersecting at right angles was made with one
leg and one
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Note: the drawing below shows the end view of a weldment consisting of 7 tubes.
8.625"
4.
What is the c-c distance between each of the seven tubes in the weldment above?
D
What is the service life of this weld? The
thickness of the plate is t = 50mm, the
measured
axis offset is em = 6.5mm. The construction
experiences the following load every year:
Ao (MPa)
Number of cycles
150
5000
80
80 000
30
2 000 000
Make assumptions if information is missing
O wrapping the weld around the corner a minuimum of the specified weld size and ar
wrapping the weld around the corner for a distance not less than two times nor mor
QUESTION 4
On all CJP groove welds in butt joints transverse to the computed tensile stress, they:.
O A. Shall have no visible porosity that exceeds 1/32"
O B. shall have no visible porosity that exceeds 3/32"
O C. shall have no visible porosity
O D. shall not have a sum of visible porosity that exceeds 3/8"
O E. shall not have a sum of visible porosity that exceeds 1/2"
QUESTION 5
Chapter 19 Solutions
Applied Statics and Strength of Materials (6th Edition)
Ch. 19 - Prob. 19.1PCh. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Rework Problem 19.1 assuming a bearing-type...Ch. 19 - Compute the allowable tensile load for the...Ch. 19 - Rework Problem 19.4 assuming a bearing-type...Ch. 19 - Rework Problem 19.4 assuming that the bolts are 34...Ch. 19 - Select the number and arrangement of 34 in....Ch. 19 - Calculate the allowable tensile load for the...Ch. 19 - In the connection shown, 14 in. side and end...Ch. 19 - Design the fillet welds parallel to the applied...
Ch. 19 - A fillet weld between two steel plates...Ch. 19 - Design an end connection using longitudinal welds...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Calculate the allowable tensile load for the lap...Ch. 19 - Calculate the allowable tensile load for the butt...Ch. 19 - Rework Problem 19.10 assuming that both plates are...Ch. 19 - Rework Problem 19.12 assuming that the angle is an...Ch. 19 - Two ASTM A36 steel plates, each 12 in. by 12 in. ,...Ch. 19 - Rework Problem 19.20 changing the fasteners to 34...Ch. 19 - Calculate the minimum main plate thickness for the...Ch. 19 - A roof truss tension member is made up of 2L6412...Ch. 19 - Rework Problem 19.23 changing the fasteners to six...Ch. 19 - Determine the allowable tensile load that can be...Ch. 19 - The welded connection shown is subjected to an...Ch. 19 - In Problem 19.26, use a 38 in. fillet weld, change...
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- 4) Determine the maximum stress. in the welds an if the joint.is. Safe for T=90.N/c. for figurea te h= {mm ム=6mm Ans: て 300N 15cm 5cm 20 Cm 18Cmarrow_forward8. Design the length of weld (L) in the connection below to develop the full tensile capacity of the plate. Use E70 electrodes and 1/4" side fillet welds. The material is ASTM A36 Steel and the allowable axial tensile stress is 22,000 psi. (show all your work) "L" PL 1/2" PL 3/8" x 6" Parrow_forward15 What is the weight of the weldment shown? (MS) Plate= .2835 lbs. per cubic inch. S 58" x 21 x 21" M.S. plate both ends 5/8=-625 W16 x 26 x 14 12' a 26 lbs/ft a. 241.90 lbs b. 533.28 lbs. C. 206.45 lbs d. 455.14 lbs 7arrow_forward
- 3.) The diagram below shows a 5.5m long double angle brace which is connected by 6mm welding connection. The length of weld shown in the picture is 300 mm on the top and 100 mm on the bottom. The 2-L127x 89x6.4 are 300W steel and long leg back-to-back. The braces are to be welded to a 12 mm 350W steel gusset plate. Determine the factored tensile capacity of the angles. Any intermediate connections that are required should also be specified. 740 kN -12 mm Gusset Platearrow_forwardSituation 2: The lap splice shown will develop a full strength as shown in the figure. Using E70 electrodes. The width of the plate is 150 mm and the thickness is 10 mm. Use Fy = 248 MPa T4 46 mm 48 mm 1. Which of the following nearly gives the diameter of the slot weld using the LRFD method. O 45 mm T O 47 mm T Warrow_forwardFind the information from the following weld symbol. 20 2.arrow_forward
- Question: a) A plate 100 mm wide and 10 mm thick is to be welded to another plate by means of double parallel fillets. The plates are subjected to a static load of 80 kN. Find the length of weld if the permissible shear stress in the weld does not exceed 55MPa. Determine the increase in load carrying capacity if a combination of single transverse double parallel fillet is used the permissible tensile strength of material is 80MPa. b) Draw a neat sketch of double riveted double cover but joint. If 8mm plates with 20 mm diameter rivets having a pitch of 50 mm are joint using double riveted lap joint. The permissible stresses are permissible tensile stress = 120 MPa;Permissible crushing stress= 100 MPa; Permissble shear stess= 150 MPa. Find the strengths and efficiency of joint, taking the strength of the rivet in double shear acoording to the indian boiler standards.arrow_forwardJoin two pieces of metal that are .045 and .045 thick. The joint is made with a triple row of MS20426 rivets. Use minimum edge distance and spacing. The Joint is 7 inches. Diameter of rivets = Length of rivets = Rivet Part Number = Number of rivets =arrow_forwardQUESTION 6 What is the safety factor for this weld? F=671 Ibf, b=1 in; d=2.2 in; h=1/4 in. The weld metal is E7018, and the member is 10 in long. y F harrow_forward
- Q4) The plate is supported by a 1.5-in. diameter steel bar and is subjected to two forces as shown. The steel rod is welded to a horizontal support. Determine the weld size. Any conclusions based on your result? 6 ft 3 ft 9 ft s kips 3 kips 3 ft 3 ft 8ftarrow_forwardDetermine the rivet diameter to join the plate with thickness 20 mm?arrow_forwardA wire of length 50 is to be cut into two pieces , one being bent to form a square and the other to form a circle . How should the wire be cut if the sum of the areas enclosed by the two * ? pieces is to be minimumarrow_forward
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Differences between Temporary Joining and Permanent Joining.; Author: Academic Gain Tutorials;https://www.youtube.com/watch?v=PTr8QZhgXyg;License: Standard Youtube License