Concept explainers
Interpretation:
Given an optically active alcohol, A has the molecular formula C11H16O. It does not adsorb any hydrogen during catalytic reduction in the presence of Pd. It gets dehydrated when treated with dilute sulphuric acid to yield an optically inactive
Concept introduction:
The degree of unsaturation in a compound can be calculated by considering the molecular formula of the compound and its parent hydrocarbon. Any compound with a chiral centre will be optically active. Alcohols undergo dehydration when warmed with dilute sulphuric acid. During ozonolysis the double bond is cleaved to yield carbonyl compounds. If the doubly bonded carbon is disubstituted then
To calculate:
The number of degrees of unsaturation in compound A.
To identify:
The structures of compounds A, B and C.
To write:
The reactions given.
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Chapter 8 Solutions
Organic Chemistry
- Compound A has the formula C₂H₁9Cl. B is a C₂H19Br compound. A and B undergo base-promoted E2 elimination to give the same alkene C as the major product as well as different minor products. C reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2,6-dimethylheptane. Addition of HCI to C yields A as the major product. Propose structures for A and B. • Do not use stereobonds in your answer. • In cases where there is more than one possible structure for each molecule, just give one for each. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate structures with + signs from the drop-down menu. ● ▾ *%-85 ChemDoodle Qt Jn [F 116arrow_forwardSharpless epoxidation of allylic alcohol X forms compound Y. Treatment of Y with NaOH and C6H5SH in an alcohol–water mixture forms Z. Identify the structure of Y and draw a mechanism for the conversion of Y to Z. Account for the stereochemistry of the stereogenic centers in Z. Z has been used as an intermediate in the synthesis of chiral carbohydrates.arrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H₂O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data? a. Isomer A is cyclopentene and isomer is 1-pentyne O b. Isomer A is cyclopentene and isomer B is 1-methylcyclobutene c. Isomer A is cyclopentene and isomer B is 3-methylcyclobutene d. Isomer A is 1-methylcyclobutene and isomer B is 3-methylcyclobutenearrow_forward
- Two isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. What is the isometric pair of A and B that corresponds?arrow_forwardTwo isomers, A and B, of molecular formula C5H8 undergo catalytic hydrogenation with hydrogen gas and palladium on carbon to form the same C5H10 product. On ozonolysis followed by treatment with hydrogen peroxide (H2O2), isomer A gave a product of molecular formula C5H8O4 that has two carboxylic acid groups in it whereas isomer B gave a product of molecular formula C5H8O3 that contains a carboxylic acid group and a ketone group. Which of the following isomeric pairs best match this data?arrow_forwardAn optically active monoterpene (compound A) with molecular formula C10H18O undergoes catalytic hydrogenation to form an optically inactive compound with molecular formula C10H20O (compound B). When compound B is heated with acid, followed by reaction with O3 and then with dimethyl sulfide, one of the products obtained is 4-methylcyclohexanone. Give possible structures for compounds A and B.arrow_forward
- Alcohol A (C10H18O) is converted to a mixture of alkenes B and C on being heated with potassium hydrogen sulfate (KHSO4). Catalytic hydrogenation of B and C yields the same product. Assuming that dehydration of alcohol A proceeds without rearrangement, deduce the structures of alcohol A and alkene C.arrow_forwardCompound A has the formula C9H19Cl. B is a C9H19Br compound.A and B undergo base-promoted E2 elimination to give the same alkene C as the major product as well as different minor products.C reacts with one molar equivalent of hydrogen in the presence of a palladium catalyst to form 2,6-dimethylheptane.Addition of HCl to C yields A as the major product.Propose structures for A and B.arrow_forwardCompound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O to give 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3) followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2 SO4 gives E (C10 H16), which decolorizes two equivalents of Br2 to give F (C10H16 Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to give isobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughout.arrow_forward
- Compound A (C7H11Br) is treated with magnesium in ether to give B (C7H11MgBr), which reacts violently with D2O togive 1-methylcyclohexene with a deuterium atom on the methyl group (C). Reaction of B with acetone (CH3COCH3)followed by hydrolysis gives D (C10H18O). Heating D with concentrated H2SO4 gives E (C10H16), which decolorizestwo equivalents of Br2 to give F (C10H16Br4). E undergoes hydrogenation with excess H2 and a Pt catalyst to giveisobutylcyclohexane. Determine the structures of compounds A through F, and show your reasoning throughoutarrow_forwardCompound A has molecular formula C7H15B.. Treatment of compound A with sodium ethoxide yields only one elimination product (compound B) and no substitution products. When compound B is treated with dilute sulfuric acid, compound C is obtained, which has molecular formula C7H160. Draw the structures of compounds A, B, and C.arrow_forwardGrignard reagent is a versatile tool in synthetic organic chemistry. Using bromocyclopentane as a starting material, show how a Grignard reagent, X, is synthesized. Reaction of X with water produces compound Y while treatment in carbon dioxide followed by hydrolysis forms compound Z. 3-methyl-2butanone reacts with X and hydrolyses to yield compound AA. Draw the structural formulae of compounds Y, Z and AA and write the chemical equations respectively.arrow_forward
- Organic ChemistryChemistryISBN:9781305580350Author:William H. Brown, Brent L. Iverson, Eric Anslyn, Christopher S. FootePublisher:Cengage Learning