Concept explainers
Interpretation: Methyl carbocation and ordinary primary carbocation in below figure should be identified and do not form should be written next to them.
Concept introduction: Organic compounds are covalent in nature that undergoes a reaction by heterolytic cleavage or homolytic cleavage.
In heterolytic cleavage, shared pair of electrons is taken away by one of the atoms which result in charged species. In homolytic cleavage, shared pair of electrons are equally distributed between two atom that results in free radicals.
Carbocation is a general term employed for a postively charged carbon irrespective of valency of carbon. In carbocation, carbon is bonded to 3 atoms or groups and has only sextet of electrons so it behaves as an electron-deficient species. It is
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Organic Chemistry: A Guided Inquiry
- Draw both resonance structures of the most stable carbocation ntermediate in the reaction shown. +HBr • You do not have to consider stereochemistry. Do not include anionic counter-1ons, e.g., I, in your answer. Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate resonance structures using the → symbol from the drop-down menu, P. opy aste C. 000▼[片 vate Windowsarrow_forwardFor each of the following, write the major product(s) and then draw out each step in the mechanism using curved arrows. Show ALL lone pair electrons and formal charges. Redraw ALL molecules as to show explicitly ALL bonds being broken or formed. Identify the molecular orbital (HOMO) of the nucleophile and the molecular orbital (LUMO) of electrophile involved in the nucleophilic attack. MO diagrams are not necessary..arrow_forwardDraw both resonance structures of the most stable carbocation intermediate in the reaction shown. • You do not have to consider stereochemistry. • Do not include anionic counter-ions, e.g., I, in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. Separate resonance structures using the symbol from the drop-down menu. ☺. re HBr ChemDoodle Sn 11arrow_forward
- Why does Hammett Equation only apply to meta and para substituted rings and not others? Explainarrow_forwardDraw both resonance structures of the most stable carbocation intermediate in the reaction shown. + HBr • You do not have to consider stereochemistry. • Do not include anionic counter-ions, e.g., I, in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. -> Separate resonance structures using the symbol from the drop-down menu. / ? ChemDoodlearrow_forward[Review Topics] [References) Draw a structural formula for the major product of the acid-base reaction shown. H2N. HCI (1 mole) (1 mole) You do not have to consider stereochemistry. • Do not include counter-ions, e.g., Na", I, in your answer. • In those cases in which there are two reactants, draw only the product from the compound that reacts. C P. opy eatearrow_forward
- The carbocation intermediate formed in the first step is resonance-stabilized. Draw the other resonance structure (by modifying the provided drawing) and add curved arrow(s) to convert the first resonance structure into the second one. Use the +/- tools to add/remove charges, and use the single bond tool to interconvert between double and single bonds. ÇH3 CH3 H3C. H,C. CH3 CH3 ČH3 ČH3 ČH3 ČH3 Edit Drawingarrow_forwardReview Topics) [References] Draw the products of the reaction shown. Electron flow is indicated with curved arrows. H.C. H :Br: CH₂ :OCH3 Include all valence lone pairs in your answer. ■Include counter-ions, e.g., Nat. I, in your submission, but draw them in their own separate s Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the right corner. Separate multiple products using the + sign from the drop-down menu. 85arrow_forwardDraw both resonance structures of the most stable carbocation intermediate in the reaction shown. HCI • You do not have to consider stereochemistry. • Do not include anionic counter-ions, e.g., I', in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate resonance structures using the + symbol from the drop-down menu.arrow_forward
- Honor Gross ma's Rule. A) For this question draw a curved arrow mechanism, start converting the Start matenal to Product A Only you Make Sure Pairs, and heteroatoms. also show the relevant resonance- Structure, and the conservation of Charge & mass B.) Then explain why product A. is a good major product. Then explain Product B is the minor product is H₂CO why and AIC137 CY why at all. draw all lone H3CO 4.5 A + not observed HCOarrow_forwardDraw both resonance structures of the most stable carbocation intermediate in the reaction shown. + HCI • You do not have to consider stereochemistry. • Do not include anionic counter-ions, e.g., I, in your answer. • Draw one structure per sketcher. Add additional sketchers using the drop-down menu in the bottom right corner. • Separate resonance structures using the → symbol from the drop-down menu. H₂ H₁₂ C C HECH H₂ C H2Cl H ? ▾ n CH₂ H₁₂ C HE HC CH H₂ H2 ChemDoodle H₁₂ CH2 HC C Cl H ? ChemDoodle F n [Farrow_forwardI am studying so much but I am not sure if these are correct. Can you go over it plsss? A Hoffmann product is O the result of the fastest mechanistic process. the most highly substituted alkene possible. the same as the Zaitsev's product, but the term "Hoffmann" is used for E2. the most stable alkene. What does Zaitsev's rule state? As the degree of substitution around the C=C of an alkene decreases, the stability of alkene increases. None of the statements is correct. O As the degree of substitution around the C=C of an alkene decreases, the stability of alkene decreases. As the degree of substitution around the C=C of an alkene increases, the stability of alkene decreases.arrow_forward
- Organic Chemistry: A Guided InquiryChemistryISBN:9780618974122Author:Andrei StraumanisPublisher:Cengage Learning