Concept explainers
(a)
To determine: The reactions of the given compounds with water.
Interpretation: The reactions of the given compounds with water are to be stated.
Concept introduction: When an acid donates a proton, the species formed is known as conjugate base and when the base accepts a proton, the species formed is known as conjugate acid.
(b)
To determine: The corresponding
Interpretation: The
Concept introduction: The equilibrium constant of an acid dissociation reaction depends on the strength of an acid involved in the reaction. The
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Organic Chemistry (9th Edition)
- Using pKa Values to Determine Relative Acidity and Basicity Rank the following compounds in order of increasing acidity, and then rank their conjugate bases in order of increasing basicity.arrow_forwardTrifluoroethanol (CF3CH2OH, pKa = 12.5) is more acidic than ethanol (CH3CH2OH, pKa = 16). Provide a three-dimensional structure for each conjugate base and draw the orbitals for all lone pairs. Provide a succinct explanation for the greater acidity of trifluoroethanol.arrow_forward4. The pk, of vanillin is about 9, which is much more acidic than a normal alcohol. Draw a reaction showing the deprotonation of vanillin with NaOH, and then draw six resonance structures of the conjugate base. Draw the hybrid structure and clearly indicate how the negative charge is distributed in the compound.arrow_forward
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- Rank the following organic molecules in order of decreasing acidity. That is, select '1' in the second column for the most acidic molecule, '2' for the next most acidic molecule, and so on. HO HO Jl. CI OH OH (Choose one) (Choose one) (Choose one) ▼ (Choose one) ▼ Xarrow_forwardThe pKa of ascorbic acid (vitamin C, page 55) is 4.17, showing that it is slightly more acidic than acetic acid (CH3COOH, pKa 4.74).Compare the stabilities of these four conjugate bases, and predict which OH group of ascorbic acid is the most acidicarrow_forwardFrom each pair, select the stronger base. Then draw the conjugate acid of the stronger base below. CICH,CH,0¯ or CH;CH,0- • You do not have to consider stereochemistry. • You do not have to explicitly draw H atoms. • You do not have to include lone pairs in your answer. opy aste [Farrow_forward
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