Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Videos
Question
Chapter 5, Problem 56P
(a)
To determine
The frictional force exerted by a
(b)
To determine
The net force and the force
(c)
To determine
The acceleration of the bigger block when the smaller block falls from it keeping the force
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
A contestant in a winter sporting event pushes a 49 kg block of ice at an angle 25∘ below the positive direction across a frozen lake, as shown in the figure. Assume the coefficients of static and kinetic friction are μs=0.1 and μk=0.03Calculate the minimum force Fmin he must exert to get the block sliding across the ice in newtons.
What is its acceleration in meters per second squared once it starts to move, if that minimum force is maintained?
A box of mass 0.8 kg is placed on an inclined surface that makes an angle 30° above
the horizontal, Figure A constant force of 18 N is applied on the box in a direction 10
with the horizontal causing the box to accelerate up the incline. The coefficient of
kinetic friction between the block and the plane is 0.25.
(a) Calculate the block's acceleration as it moves up the incline.
(b) If the block slides down at a constant speed, find the value of force applied.
30
A 0.3 kg book is being pushed by a horizontal force of 1.1 N, where t is the time that the book is experiencing this applied force over 1.1s. Hot fast is the book moving at this time of it started from rest? Assume that the book of sliding over a non uniform surface with the coefficient of kinetic friction that is changing as: 0.4 t.
Chapter 5 Solutions
Physics for Scientists and Engineers
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- In a television commercial, a small, spherical bead of mass 4.00 g is released from rest at t=0in a bottle of liquid shampoo. The terminal speed is observed to be 2.00 cm/s. Find (a) the value of the constant bin the equation v=mgb(1ebt/m), and (b) the value of the resistive force when the bead reaches terminal speed.arrow_forwardIn Example 4.6, we investigated the apparent weight of a fish in an elevator. Now consider a 72.0-kg man standing on a spring scale in an elevator. Starting from rest, the elevator ascends, attaining its maximum speed of 1.20 m/s in 0.800 s. It travels with this constant speed for the next 5.00 s. The elevator then undergoes a uniform acceleration in the negative y direction for 1.50 s and comes to rest. What does the spring scale register (a) before the elevator starts to move, (b) during the first 0.800 s, (c) while the elevator is traveling at constant speed, and (d) during the time interval it is slowing down?arrow_forwardIn a pickup game of dorm shuffleboard, students crazed by final exams use a broom to propel a calculus book along the dorm hallway. If the 3.5 kg book is pushed from rest through a distance of 0.92 m by the horizontal 26 N force from the broom and then has a speed of 1.28 m/s, what is the coefficient of kinetic friction between the book and floor?arrow_forward
- Shown below is a 10.0-kg block being pushed by a horizontal force F → of magnitude 200.0 N. The coefficient of kinetic friction between the two surfaces is 0.50. Find the acceleration of the block.arrow_forwardWrite Newton's laws for a static system (1) EF, = mg sin 0 – µ̟n = 0 in component form. The gravity force has two components. (2) EF, = n - mg cos 0 = 0 Rearrange Equation (2) to get an n = mg cos e expression for the normal force n. Substitute the expression for n into EF, = mg sin 0 – µ̟mgcos 0 = 0 → tan 0 =µ, Equation (1) and solve for tan 0. Apply the inverse tangent function to tan 0 = 0.350 → 0 = tan 1 (0.350) = 19.3° get the answer. LEARN MORE REMARKS It's interesting that the final result depends only on the coefficient of static friction. Notice also how similar Equations (1) and (2) are to the equations developed in previous problems. Recognizing such patterns is key to solving problems successfully. QUESTION A larger static friction constant would result in a: (Select all that apply.) O larger component of normal force at the maximum angle. O larger component of gravitational force along the ramp at the maximum angle. smaller component of gravitational force along the ramp…arrow_forwardThe force Pis applied to the 45-kg block when it is at rest. Determine the magnitude and direction of the friction force exerted by the surface on the block if (o) P-0, (b) P-138 N, and (c) P-217 N. (d) What value of P is required to initiate motion up the incline? The static and kinetic coefficients of friction between the block and the incline are u,-0.19 and -0.13, respectively. The friction force is positive if up the incline, negative if down the incline. Answers (a) F- (b) F (c) F= (d) P. 45 kg 12: -0.19 0.13 N N z z N Narrow_forward
- A homeowner accelerated a 15kg lawnmower uniformly from rest to 1.2m/s in 2.0 s. The coefficient of kinetic friction is 0.25. Calculate the horizontally applied force acting on the lawnmower.arrow_forwardivity 8 zht inelastic string connects two blocks of mass 1,5 kg and 2 kg respectively. A force oplied at an angle of 20° on block A, B. A 200 1,5 kg 2 kg force F of 8,25N is applied on block A, the blocks move at a CONSTANT VELOCITY on the ph surface. Caloulate the horizontal component of the applied force F. (2) Calculate the magnitude the normal force acting on block A. (3) Calculate the coefficient of kinetic frictlon between the blocks and the rough (4) surface. How will the frictional force on block A change if the angle of the force changes to (1) [10] 15°? Write down INCREASES, DECREASES or REMAINS THE SAME. tivity 9 arner constructs a push toy using two blocks with masses 1,5 kg and 3 kg réspectively. blocks are cơnnected by a massless, inextensible cord. The leaner then applies a force of V at en angle of 30° to the 1,5 kg block by means of a light rigid rod, causing the toy to e across a flat, rough, horizontal surface, as shown in the diagram below. 25 N The coeffiolent of…arrow_forwardA 2.17-kg object is situated at rest on a horizontal surface with a static friction coefficient of 0.56. Calculate the maximum force of the static friction.arrow_forward
- Vehicle 1 is traveling down the road with a speed of 75 mph. The driver notices vehicle 2 is not going to stop for the stop sign. Vehicle 1 then applies the brakes and skids for 50 feet before impacting vehicle 2 in the intersection. The two vehicles locktogether and slide a certain distance shown. The weight of vehicle 1 is 4000-lb and the weight of vehicle 2 is 3500-lbs. Assuming the area is flat and the coefficient of friction for all surfaces is 0.75, determine the speed of vehicle 2 at impact and the distance thetwo vehicles travel to rest. (1mph = 1.467 ft/s) g = 32.2 ft/s/sarrow_forwardThe coefficient of friction between blocks is us = 0.4, at what angle will the block start sliding if it is initially at rest? Solution Let us obtain the net force in the axis perpendicular to the inclined plane. By virtue of the first law of motion (equilibrium), the net force is 2 F perpendicular = n - Fgperpendicular = Thus, the normal force is n = m Cos On the axis parallel to the inclined, the net force isarrow_forwardA particle of mass 6 kg is placed on a rough plane inclined at an angle a to the horizontal where sin a = 0.8. The coefficient of friction between the particle and the plane is 0.4. An upward force PN actson the particle along a line of greatest slope of the plane. Find the greatest value of Parrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...PhysicsISBN:9781133939146Author:Katz, Debora M.Publisher:Cengage Learning
University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
Drawing Free-Body Diagrams With Examples; Author: The Physics Classroom;https://www.youtube.com/watch?v=3rZR7FSSidc;License: Standard Youtube License