Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
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Chapter 5, Problem 43P
To determine
To Calculate:The speed of the second block.
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Chapter 5 Solutions
Physics for Scientists and Engineers
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- A 2.20 kg block is initially at rest on a horizontal surface. A horizontal force of magnitude 4.83 N and a vertical force are then applied to the block (Fig. 6-17). The coefficients of friction for the block and surface are µs = 0.4 and µk = 0.25. Determine the magnitude of the frictional force acting on the block if the magnitude of is (a) 8.00 N and (b) 12.0 N. (The upward pull is insufficient to move the block vertically.)arrow_forwardIn Fig. 6-59, block 1 of mass m1 ? 2.0 kg and block 2 of mass m2 ? 1.0 kg are connected by a string of negligible mass. Block 2 is pushed by force F of magnitude 20 N and angle u ? 35°. The coefficient of kinetic friction between each block and the horizontal surface is 0.20. What is the tension in the string? (please don't copy-paste solution)arrow_forwardOn a horizontal plane a block of mass m = 0.30 kg is placed and initially held at rest. To this block a massless string is attached and it initially keeps another block of mass M = 0.50 kg vertically at rest via a fixed pulley as shown in Figure. The coefficient of kinetic friction between the block m and the plane is Pk -0.25, but the friction between the block M and the vertical wall is zero. Calculate the tension T by string in N. (Hint: First calculate the acceleration of m or M. And set up the equation of motion for M to find the tension T.) T m Marrow_forward
- The figure shows an overhead view of a 0.026 kg lemon half and two of the three horizontal forces that act on it as it is on a frictionless table. Force F has a magnitude of 3N and is at e, - 31. Force F2 has a magnitude of 10 N and is at 02- 33". In unit-vector notation, what is t third force if the lemon half (a) is stationary, (b) has the constant velocity V (137-14) m (12h- 14) m/s?, where t is time? %3D and (c) has the V = %3Darrow_forwardTHREE 5-KG PACKAGES A, B, AND C ARE PLACED ON A CONVEYOR BELT THAT IS AT REST. BETWEEN THE BELT AND BOTH PACKAGES A AND C THE COEFFICIENTS OF FRICTION ARE us = BETWEEN PACKAGE B AND THE BELT THE COEFFICIENTS ARE us = 0.30 AND uK = 0.20%3; 0.15 AND H = 0.10. THE PACKAGES ARE PLACED ON THE BELT SO THAT THEY ARE IN CONTACT WITH EACH OTHER AND AT REST. DETERMINE WHICH, IF ANY, OF THE PACKAGES WILL MOVE AND THE FRICTION FORCE ACTING ON EACH PACKAGE. %3D 5 kg skg 5 kgarrow_forwardA force F acting 30° from the horizontal is pulling the 1500 N-block along the horizontal plane. After traveling at a distance of 6 meters from rest, the force F is then removed. If F = 800 N, compute the velocity of the of the block after it has moved a total distance of 8.5 meters. Coeff. of friction is 0.20. If F = 800 N, compute the velocity of the of the block after it has moved a total distance of 8.5 meters. Coeff. of friction is 0.20. a. 5.22 m/s b. 3.96 m/s c. 6.78 m/s d. 4.68 m/sarrow_forward
- A box of mass m is initially at rest at the top of an inclined plane, which has aheight of 4.4 m and has an angle of 0 = 24° with respect to the horizontal. After letting go of theobject, you perceive it to be traveling at v = 1 m/s a distance d after the end of the inclined plane asshown. The coefficient of kinetic friction between the box and the plane is Up= 0.1, and the coefficient of friction on the horizontal surface is Ur, = 0.2. please, (a) What is the speed of the box, in meters per second, just after it leaves the inclined plane? (b) What is the distance, d, in meters.arrow_forwardNEWTON'S LAWS WITH FRICTION PH 421 5 0 A 2.5 kg block is initially at rest on a horizontal surface. A horizontal force F of magnitude 6.0 N and a vertical force P are then applied to the block (Fig. 6-17). The coefficients of friction for the block and surface are M, magnitude of the frictional force acting on the block if the magni- tude of P is (a) 8.0 N, (b) 10 N, and (c) 12 N. = 0.40 and H = 0.25. Determine the %3D N. F. Flg. 6-17 Problem 5.arrow_forward*55 SSM ILW www Two blocks are in contact on a frictionless table. A horizon- tal force is applied to the larger block, as shown in Fig. 5-50. (a) If m = 2.3 kg, 1.2 kg, and F=3.2 N, find the mag- m2 nitude of the force between the two blocks (b) Show that if a force of the same magnitude F is applied to the smaller block but in the opposite direction, the magnitude of the force be- tween the blocks is 2.1 N, which is not the same value calculated in (a). (c) Explain the difference. Fig. 5-50 Problem 55.arrow_forward
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