Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 29P
To determine
The minimum coefficient of static friction needed between a car’s tires and the pavement to complete a turn with the given speed limit.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
The maximum static coefficient of friction between the tires of a 2000 kg car and the
road is lsmax
0.25. What is the maximum speed with which the car can make a turn
of radius 50 m without skidding?
A 1335 kg sports car rounds a flat curve of radius 40 m. Given that the coefficient of static friction betweeen the tires and road is 0.5, calculate what maximum speed the car can round the road without slidding.
A car's maximum velocity speed of 4√10 m/s can turn safely on a cruved path that 40 meters radius and 0.4 coeffcient of static friction between tire and road. What must be the curved path radius if the maximum velocity speed of the car must be 10 m/s, with 0.5 as the coefficient of static friction so that the car can still turn safely without skidding out of a curved road?
Chapter 5 Solutions
Physics for Scientists and Engineers
Ch. 5 - Prob. 1PCh. 5 - Prob. 2PCh. 5 - Prob. 3PCh. 5 - Prob. 4PCh. 5 - Prob. 5PCh. 5 - Prob. 6PCh. 5 - Prob. 7PCh. 5 - Prob. 8PCh. 5 - Prob. 9PCh. 5 - Prob. 10P
Ch. 5 - Prob. 11PCh. 5 - Prob. 12PCh. 5 - Prob. 13PCh. 5 - Prob. 14PCh. 5 - Prob. 15PCh. 5 - Prob. 16PCh. 5 - Prob. 17PCh. 5 - Prob. 18PCh. 5 - Prob. 19PCh. 5 - Prob. 20PCh. 5 - Prob. 21PCh. 5 - Prob. 22PCh. 5 - Prob. 23PCh. 5 - Prob. 24PCh. 5 - Prob. 25PCh. 5 - Prob. 26PCh. 5 - Prob. 27PCh. 5 - Prob. 28PCh. 5 - Prob. 29PCh. 5 - Prob. 30PCh. 5 - Prob. 31PCh. 5 - Prob. 32PCh. 5 - Prob. 33PCh. 5 - Prob. 34PCh. 5 - Prob. 35PCh. 5 - Prob. 36PCh. 5 - Prob. 37PCh. 5 - Prob. 38PCh. 5 - Prob. 39PCh. 5 - Prob. 40PCh. 5 - Prob. 41PCh. 5 - Prob. 42PCh. 5 - Prob. 43PCh. 5 - Prob. 44PCh. 5 - Prob. 45PCh. 5 - Prob. 46PCh. 5 - Prob. 47PCh. 5 - Prob. 48PCh. 5 - Prob. 49PCh. 5 - Prob. 50PCh. 5 - Prob. 51PCh. 5 - Prob. 52PCh. 5 - Prob. 53PCh. 5 - Prob. 54PCh. 5 - Prob. 55PCh. 5 - Prob. 56PCh. 5 - Prob. 57PCh. 5 - Prob. 58PCh. 5 - Prob. 59PCh. 5 - Prob. 60PCh. 5 - Prob. 61PCh. 5 - Prob. 62PCh. 5 - Prob. 63PCh. 5 - Prob. 65PCh. 5 - Prob. 67PCh. 5 - Prob. 68PCh. 5 - Prob. 69PCh. 5 - Prob. 70PCh. 5 - Prob. 71PCh. 5 - Prob. 72PCh. 5 - Prob. 73PCh. 5 - Prob. 74PCh. 5 - Prob. 75PCh. 5 - Prob. 76PCh. 5 - Prob. 77PCh. 5 - Prob. 78PCh. 5 - Prob. 79PCh. 5 - Prob. 80PCh. 5 - Prob. 82PCh. 5 - Prob. 83PCh. 5 - Prob. 84PCh. 5 - Prob. 85PCh. 5 - Prob. 86PCh. 5 - Prob. 87PCh. 5 - Prob. 88PCh. 5 - Prob. 89PCh. 5 - Prob. 90PCh. 5 - Prob. 91PCh. 5 - Prob. 92PCh. 5 - Prob. 93PCh. 5 - Prob. 94PCh. 5 - Prob. 95PCh. 5 - Prob. 96PCh. 5 - Prob. 97PCh. 5 - Prob. 101PCh. 5 - Prob. 102PCh. 5 - Prob. 103PCh. 5 - Prob. 104PCh. 5 - Prob. 105PCh. 5 - Prob. 106PCh. 5 - Prob. 107PCh. 5 - Prob. 108PCh. 5 - Prob. 109PCh. 5 - Prob. 110PCh. 5 - Prob. 111PCh. 5 - Prob. 112PCh. 5 - Prob. 113PCh. 5 - Prob. 114PCh. 5 - Prob. 115PCh. 5 - Prob. 116PCh. 5 - Prob. 117PCh. 5 - Prob. 118PCh. 5 - Prob. 119PCh. 5 - Prob. 120PCh. 5 - Prob. 121PCh. 5 - Prob. 122PCh. 5 - Prob. 123PCh. 5 - Prob. 124PCh. 5 - Prob. 125PCh. 5 - Prob. 126PCh. 5 - Prob. 127PCh. 5 - Prob. 128PCh. 5 - Prob. 129PCh. 5 - Prob. 130PCh. 5 - Prob. 131PCh. 5 - Prob. 132PCh. 5 - Prob. 133PCh. 5 - Prob. 134PCh. 5 - Prob. 135PCh. 5 - Prob. 136PCh. 5 - Prob. 137PCh. 5 - Prob. 138PCh. 5 - Prob. 139P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- What Is the ideal banking angle for a gentle turn of 1.20-km radius on a highway with a 105 km/h speed limit (about 65 mi/h), assuming everyone travels at the limit?arrow_forwardHow large must the coefficient of static friction be between the tires and the road if a car is to round a level curve of radius 150 mm at a speed of 130 km/hkm/h ?arrow_forwardA car rounds a level turn with an 85-m radius. Suppose it is an icy day when the coefficients of static and kinetic friction between the car's tires and road are .15 and .13, respectively. What is the largest speed the car can take the turn withoit slipping?arrow_forward
- (a) Calculate the centripetal force exerted on a 900.0-kg car that negotiates a 500.0-m radius curve at 25.00 m/s. (b) Assuming àn unbanked curve, find the minimum static coefficient of friction between the tires and the road, static friction being the reason that keeps the car from slipping.arrow_forwardIf a car takes a banked curve at less than the ideal speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). (a) Calculate the ideal speed to take a 110 m radius curve banked at 15°. m/s (b) What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 25.0 km/h?arrow_forwardA car is driving around a banked curve, with the road surface at an angle of 10.0º. If the radius ofcurvature of the road is 30.0 m and the coefficient of static friction between the tires of the carand the road is 0.65, what is the maximum speed (in km/hr) the car can go without skidding?arrow_forward
- A highway curve has 200-ft radius and is designed to accommodate vehicles at a maximum speed of 100-mphwith the coefficient of friction between the tires and the road of 0.6. Determine (a) the banking angle of theroad, (b) the minimum speed that the road can accommodate and (c) the ideal speed for this road?arrow_forwardA bus’ maximum velocity speed of 410m/s can turn safely on a curved path that has 40 meters radius and 0.4 coefficient of static friction between tire and road. What must be the curved path radius if the maximum velocity speed of the bus must be 10 m/s, with 0.5 as the coefficient of static friction so that the bus can still turn safely without skidding out of a curved road?arrow_forwardIt was a dark and stormy night in Winona, Minnesota. A driver advances alongan icy road - assume there is no friction between the tires and the road - must ne-gotiate a turn for which the road traces out an arc of a circle of radius 321 m. Theroad is banked at an angle of 5.2 . What is the speed with which she must take the curve to avoid sliding?arrow_forward
- If a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads).Calculate the minimum speed, in meters per second, required to take a 84 m radius curve banked at 13° so that you don't slide inwards, assuming there is no friction. What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 19 km/h?arrow_forwardIf a car takes a banked curve at less than a given speed, friction is needed to keep it from sliding toward the inside of the curve (a real problem on icy mountain roads). Calculate the minimum speed, in meters per second, required to take a 108 m radius curve banked at 13° so that you don't slide inwards, assuming there is no friction. What is the minimum coefficient of friction needed for a frightened driver to take the same curve at 15 km/h?arrow_forwardA car is on a banked curve of radius 400-meters and a bank angle of 15°. If the car is about to lose traction on the curve, determine the coefficient of static friction compatible with that scenario, if the car is traveling at 50 m/s.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- University Physics Volume 1PhysicsISBN:9781938168277Author:William Moebs, Samuel J. Ling, Jeff SannyPublisher:OpenStax - Rice University
University Physics Volume 1
Physics
ISBN:9781938168277
Author:William Moebs, Samuel J. Ling, Jeff Sanny
Publisher:OpenStax - Rice University
What Is Circular Motion? | Physics in Motion; Author: GPB Education;https://www.youtube.com/watch?v=1cL6pHmbQ2c;License: Standard YouTube License, CC-BY