Life in the Universe (4th Edition)
4th Edition
ISBN: 9780134089089
Author: Jeffrey O. Bennett, Seth Shostak
Publisher: PEARSON
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Textbook Question
Chapter 3, Problem 33TYU
A television advertisement claiming that a product is “light-years ahead of its time” does not make sense because (a) it doesn’t specify the number of light-years; (b) it uses “light-years” to talk about time, but a light-year is a unit of distance; (c) light-years can only be used to talk about light.
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A light-year is the distance that light can travel in one year. Similarly, we can define a light-second, light-day, etc. as the distance that light can travel in other time intervals. Calculate the distance represented by each of the following: (Assume that the speed of light is 3 x 10^8m/s)
5 light-minutes
6 light-days
6 light-days, but this time answer in miles (enter just the number with no units)
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Listed below are some distances from Earth to other objects in the Milky Way galaxy. Convert each
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The distance from Earth to the Moon is about 384,400 km. How many light-years is this?
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The distance from Earth to Mars is about 784,000,000 km. How many light-years is this?
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The distance from Earth to Pluto is about 5,750,000,000 km. How many light-years is this?
Recall that Hubble’s Law is given by V=HR; this means that H has units of inverse seconds (1/sec). A convenient laboratory set of units is to give H in km per sec per megaparsec. A parsec is 3.26 light years and the speed of light is 3 X 105 km/sec. Use 3.156 X 107 sec/yr. The first data off the then new Hubble Space telescope suggested a value of H equal to 108 km per sec per megaparsec. What is H in inverse seconds? Hint divide by the number of km in a megaparsec.
Chapter 3 Solutions
Life in the Universe (4th Edition)
Ch. 3 - List three major ideas of astronomy that help...Ch. 3 - Briefly define and describe each of the various...Ch. 3 - Describe the solar system as it looks on the...Ch. 3 - Prob. 4RQCh. 3 - Prob. 5RQCh. 3 - Prob. 6RQCh. 3 - Prob. 7RQCh. 3 - What do we mean when we say that Earth and life...Ch. 3 - Imagine describing the cosmic calendar to a...Ch. 3 - Prob. 10RQ
Ch. 3 - Prob. 11RQCh. 3 - Prob. 12RQCh. 3 - What is the difference between matter in the...Ch. 3 - Define and give examples of kinetic energy,...Ch. 3 - Prob. 15RQCh. 3 - Prob. 16RQCh. 3 - Briefly describe the four major features of our...Ch. 3 - Briefly describe the nebular theory and how it...Ch. 3 - What was the close encounter hypothesis for our...Ch. 3 - How have recent discoveries led scientists to...Ch. 3 - Prob. 21TYUCh. 3 - At a middle school talent show, 14-year-old Sam...Ch. 3 - SETI researchers announced today that if they...Ch. 3 - A noted physicist today announced that he has...Ch. 3 - Prob. 25TYUCh. 3 - Astronomers have discovered a galaxy in the far...Ch. 3 - Inventor John Johnson has patented a device that...Ch. 3 - Prob. 28TYUCh. 3 - Prob. 29TYUCh. 3 - Using new, powerful telescopes, biologists today...Ch. 3 - Prob. 31TYUCh. 3 - Prob. 32TYUCh. 3 - A television advertisement claiming that a product...Ch. 3 - When we say the universe is expanding, we mean...Ch. 3 - Prob. 35TYUCh. 3 - The age of our solar system is about (a) one-third...Ch. 3 - Prob. 37TYUCh. 3 - How many of the planets orbit the Sun in the same...Ch. 3 - Prob. 39TYUCh. 3 - Prob. 40TYUCh. 3 - Explaining the Past. Is it really possible for...Ch. 3 - A Strange Star System. Suppose that we discovered...Ch. 3 - Prob. 44IFCh. 3 - Alien Technology. Some people believe that Earth...Ch. 3 - Atomic Terminology Practice. a. The most common...Ch. 3 - Prob. 49IFCh. 3 - Prob. 50IFCh. 3 - Patterns of Motion. In one or two paragraphs,...Ch. 3 - Two Kinds of Planets. The jovian planets differ...Ch. 3 - Pluto and Eris. How does the nebular theory...Ch. 3 - Rocks from Other Solar Systems. Many leftovers...Ch. 3 - Prob. 55IFCh. 3 - Prob. 56IFCh. 3 - Scale of the Solar System. The real diameters of...Ch. 3 - Prob. 58IFCh. 3 - Prob. 59IFCh. 3 - Prob. 60IFCh. 3 - Prob. 61IFCh. 3 - Prob. 62IFCh. 3 - Prob. 63IFCh. 3 - Prob. 67WPCh. 3 - Tour of the Solar System. Visit one of the many...
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Thats the same answer I got before, and it is wrong. whether it is 0.722 or 7.22 x 10^-1 wrong answer.arrow_forwardSuppose we find an Earth-like planet around one of our nearest stellar neighbors, Alpha Centauri (located only 4.4 light-years away). If we launched a "generation ship" at a constant speed of 1500.00 km/s from Earth with a group of people whose descendants will explore and colonize this planet, how many years before the generation ship reached Alpha Centauri? (Note there are 9.46 ××1012 km in a light-year and 31.6 million seconds in a year.arrow_forwardIf Jim could drive a Jetson's flying car at a constant speed of 330 km/hr across oceans and space, approximately how long (in millions of years, in 106 years) would he take to drive to a nearby star that is 8.7 light-years away? Use 9.461 × 1012 km/light-year and 8766 hours per year (365.25 days).arrow_forward
- Use the equation E = mc^2 where E is energy in Joules (J), m is mass in kilograms (kg) and c is the speed of light 3 x 10^8 m/s to answer the following: a) One ton of TNT releases 4.18 gigajoules of energy. The metric prefix giga means billion. a) How much mass would be required to release an equivalent amount of energy? b) How much energy (J) is equivalent to 1 kilogram of mass?arrow_forwardThe Apollo program (not the lunar missions with astronauts) being conducted at the Apache Point Observatory uses a 3.5 - m telescope to direct lasers at retro-reflectors left on the Moon by the Apollo astronauts. the Moon is 384, 472 km away approximately how long do the operators need to wait to see the laser light return to Earth? (Hint: The speed of light is 300,000 km/s.]arrow_forwardThe Planck time is the unique interval of time that can be built out of G, c, and h. Some physicists think that time intervals shorter than the Planck time have no meaning. Using G = 6.7 x 10-11 kg-1 m3 s-2, c = 3 x 108 m s-1, and h = 6.6 x 10-34 kg m2 s-1, calculate the Planck time, in units of 10-43 s.arrow_forward
- A light year (LY) is the distance that light travels in one year. 1 LY = 9.46x1015 m. Suppose we have detected a planet that orbits a star that is 104 light years away. How many millions of years would it take us to get there if we used a modern rocket with a maximum speed of 20.0 km/s (about 45,000 mph)? Assume 3 sig figs.arrow_forwardCalculate the number of miles in a light-year, using 1.86 105 mi/s as the speed of light. (Hint: The number of seconds in a year, 365 days, will be useful.)arrow_forward
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