Astronomy Today (9th Edition)
9th Edition
ISBN: 9780134450278
Author: Eric Chaisson, Steve McMillan
Publisher: PEARSON
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Chapter 2, Problem 4D
To determine
The great contribution of Copernicus to our knowledge of the solar system, and also to determine the reason that his model was still flawed.
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The mass of Jupiter is 1/1047 of the Sun's mass (that's 0.000955). We want to confirm this using Newton's version of Kepler's Third Law, following the examples in Lecture 7. We'll use the approximate data for two different moons of Jupiter to see how close the results are. Pick the closest answer in each case:
(a) Ganymede is the third moon from the inside. It has an orbital period around Jupiter of approximately 0.0194 Earth years. Its semimajor axis is 0.0071 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data?
(b) Europa is the second moon from the inside. It has an orbital period around Jupiter of approximately 0.0096 Earth years. Its semimajor axis is 0.0045 AU. Which of these comes closest to the mass of Jupiter (in solar masses) when using these data?
On the evening of an autumnal equinox day Siddhant noticed that Mars was
exactly along the north-south meridian in his sky at the exact moment when the sun was
setting. In other words, the Sun and Mars subtended an angle of exactly 90° as measured
from the Earth. If the orbital radius of Mars is 1.52 au, What will be the approximate rise
time of the mars on the next autumnal equinox day?
A)At what altitude would a geostationary sattelite need to be above the surface of Mars? Assume the mass of Mars is 6.39 x 1023 kg, the length of a martian solar day is 24 hours 39minutes 35seconds, the length of the sidereal day is 24hours 37minutes 22seconds, and the equatorial radius is 3396 km. The answer can be calculated using Newton's verison of Kepler's third law.
Chapter 2 Solutions
Astronomy Today (9th Edition)
Ch. 2 - Prob. 1DCh. 2 - Prob. 2DCh. 2 - Prob. 3DCh. 2 - Prob. 4DCh. 2 - Prob. 5DCh. 2 - Prob. 6DCh. 2 - Prob. 7DCh. 2 - Prob. 8DCh. 2 - Prob. 9DCh. 2 - Prob. 10D
Ch. 2 - Prob. 11DCh. 2 - Prob. 12DCh. 2 - Prob. 13DCh. 2 - Prob. 14DCh. 2 - Prob. 15DCh. 2 - Prob. 1MCCh. 2 - Prob. 2MCCh. 2 - Prob. 3MCCh. 2 - Prob. 4MCCh. 2 - Prob. 5MCCh. 2 - Prob. 6MCCh. 2 - Prob. 7MCCh. 2 - Prob. 8MCCh. 2 - Prob. 9MCCh. 2 - Prob. 10MCCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8P
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Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Why did Kepler need Tycho Brahe’s data to formulate his laws?arrow_forwardKepler’s third law says that the orbital period (in years) is proportional to the square root of the cube of the mean distance (in AU) from the Sun (Pa1.5) . For mean distances from 0.1 to 32 AU, calculate and plot a curve showing the expected Keplerian period. For each planet in our solar system, look up the mean distance from the Sun in AU and the orbital period in years and overplot these data on the theoretical Keplerian curve.arrow_forwardWhy was Brahe reluctant to provide Kepler with all his data at one time?arrow_forward
- List some reasons that the study of the planets has progressed more in the past few decades than any other branch of astronomy.arrow_forwardWhy did Copernicus want to develop a completely new system for predicting planetary positions? Provide two reasons.arrow_forwardIn Ptolemys model, how do the epicycles of Mercury and Venus differ from those of Mars, Jupiter, and Saturn?arrow_forward
- Comet Halley (Fig. P11.21) approaches the Sun to within 0.570 AU, and its orbital period is 75.6 yr. (AU is the symbol for astronomical unit, where 1 AU = 1.50 1011 m is the mean EarthSun distance.) How far from the Sun will Halleys comet travel before it starts its return journey?arrow_forwardWhich of Keplers laws gives the most direct indication of the shape of the orbit of a planet? (16.1) (a) law of elliptical orbits (b) law of equal areas (c) harmonic lawarrow_forwardSaturn has an angular size of 16”, and an observed Synodic Period of 1.035yrs. Saturn’s moon, Titan orbits the planet with an angular separation of 192”, with a period of 15.9days. From these observations we can determine Saturn’s mass. Use the Sidereal Period of Saturn above to find the distance to Saturn from the Sun.arrow_forward
- Comet Halley has a semi-major axis of 17.7 AU. (The AU, or Astronomical Unit, is the distance from the Sun to the Earth. 1 AU = 1.50x1011 m.) The eccentricity of Comet Halley is 0.967. a. How far is Comet Halley from the sun at Aphelion, the farthest position from the sun? (Give your answer in AU.)? b. What is comet Halley's orbital time? (Give your answer in years.) Note: Using Kepler's third law in the form: P2 = a3 is convenient. This equation works for any object orbiting the sun when the orbital period is in years and the semi major axis is in AU. The reason this works is because this equation is normalized to earth. The AU and year are both 1 for Earth. c. In what year will Comet Halley start to move back toward the sun?arrow_forwardIf the satellite was placed in an orbit three times farther away, about how long would it take to orbit the Earth once? Answer in days, rounding to one significant figure.days Mars rotates on its axis once every 1.02 days (almost the same as Earth does). (a) Find the distance from Mars at which a satellite would remain in one spot over the Martian surface. (Use 6.42 1023 kg for the mass of Mars.)m(b) Find the speed of the satellite.m/sarrow_forwardSaturn's mass is M= 5.69 x 1026 kg and its radius R=60,300 km. If a moon orbits Saturn at a distance equal to 5 times its planetary radius, what is its period of orbit? (Hint, use Newton's version of Kepler's 3rd law, and you can neglect the mass of the moon) Express your answer in days to three significant figures.arrow_forward
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