General Chemistry: Atoms First
2nd Edition
ISBN: 9780321809261
Author: John E. McMurry, Robert C. Fay
Publisher: Prentice Hall
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Textbook Question
Chapter 0.11, Problem 0.17P
Oxalic acid, found in dark-green leafy vegetables such as spinach and rhubarb, has a reported LD50 of 600 mg/kg in humans. If dry rhubarb leaves (not stalks) contain 0.5% oxalic acid by weight, how many pounds of dry leaves would a 175-pound person have to consume to have a 50% chance of dying? How many pounds of undried leaves, whose mass is about 95% water?
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Chapter 0 Solutions
General Chemistry: Atoms First
Ch. 0.2 - Express the following quantities in scientific...Ch. 0.2 - What units do the following abbreviations...Ch. 0.5 - The normal body temperature of a healthy adult...Ch. 0.5 - Carry out the indicated temperature conversions....Ch. 0.7 - Prob. 0.5PCh. 0.7 - Chloroform, a substance once used as an...Ch. 0.8 - Prob. 0.7PCh. 0.9 - A 1.000 mL sample of acetone, a common solvent...Ch. 0.9 - Prob. 0.9PCh. 0.9 - Characterize each of the following dartboards...
Ch. 0.10 - Prob. 0.11PCh. 0.10 - Carry out the following calculations, expressing...Ch. 0.10 - What is the temperature reading on the following...Ch. 0.11 - Calculate answers to the following problems, and...Ch. 0.11 - Gemstones are weighed in carats, with 1 carat =...Ch. 0.11 - A pure diamond with a mass of 0.1000 g contains...Ch. 0.11 - Oxalic acid, found in dark-green leafy vegetables...Ch. 0 - Which block in each of the following drawings of a...Ch. 0 - How many milliliters of water does the graduated...Ch. 0 - Assume that you have two graduated cylinders, one...Ch. 0 - The following cylinder contains three liquids that...Ch. 0 - What is the difference between mass and weight?Ch. 0 - What is the difference between a derived SI unit...Ch. 0 - What SI units are used for measuring the following...Ch. 0 - What SI prefix corresponds to each of the...Ch. 0 - Prob. 0.26SPCh. 0 - Prob. 0.27SPCh. 0 - Prob. 0.28SPCh. 0 - Prob. 0.29SPCh. 0 - Prob. 0.30SPCh. 0 - Prob. 0.31SPCh. 0 - Prob. 0.32SPCh. 0 - Prob. 0.33SPCh. 0 - Prob. 0.34SPCh. 0 - Prob. 0.35SPCh. 0 - Prob. 0.36SPCh. 0 - Prob. 0.37SPCh. 0 - Prob. 0.38SPCh. 0 - Prob. 0.39SPCh. 0 - How many significant figures are in each of the...Ch. 0 - Prob. 0.41SPCh. 0 - The Vehicle Assembly Building at the John F....Ch. 0 - Prob. 0.43SPCh. 0 - Prob. 0.44SPCh. 0 - Prob. 0.45SPCh. 0 - Prob. 0.46SPCh. 0 - Prob. 0.47SPCh. 0 - Express the results of the following calculations...Ch. 0 - Prob. 0.49SPCh. 0 - Prob. 0.50SPCh. 0 - Prob. 0.51SPCh. 0 - The normal body temperature of a goat is 39.9C,...Ch. 0 - Prob. 0.53SPCh. 0 - Prob. 0.54SPCh. 0 - Prob. 0.55SPCh. 0 - Prob. 0.56SPCh. 0 - Answer parts (a)(d) of Problem 0.56 assuming that...Ch. 0 - The density of silver is 10.5 g/cm3. What is the...Ch. 0 - Prob. 0.59SPCh. 0 - Prob. 0.60SPCh. 0 - Gaseous hydrogen has a density of 0.0899 g/L at...Ch. 0 - Prob. 0.62SPCh. 0 - Prob. 0.63SPCh. 0 - Prob. 0.64SPCh. 0 - Prob. 0.65SPCh. 0 - Prob. 0.66SPCh. 0 - Prob. 0.67SPCh. 0 - Prob. 0.68SPCh. 0 - Prob. 0.69SPCh. 0 - Prob. 0.70SPCh. 0 - Prob. 0.71SPCh. 0 - Prob. 0.72SPCh. 0 - Prob. 0.73SPCh. 0 - Prob. 0.74CHPCh. 0 - Prob. 0.75CHPCh. 0 - Sodium chloride has a melting point of 1074 K and...Ch. 0 - Prob. 0.77CHPCh. 0 - Prob. 0.78CHPCh. 0 - Prob. 0.79CHPCh. 0 - Prob. 0.80CHPCh. 0 - Prob. 0.81CHPCh. 0 - Prob. 0.82CHPCh. 0 - Vinaigrette salad dressing consists mainly of...Ch. 0 - At a certain point, the Celsius and Fahrenheit...Ch. 0 - Prob. 0.85CHPCh. 0 - Prob. 0.86CHPCh. 0 - An Eastern diamondback rattlesnake was milked...Ch. 0 - Prob. 0.88CHPCh. 0 - Prob. 0.89CHPCh. 0 - Prob. 0.90CHPCh. 0 - Ocean currents are measured in sverdrups (Sv)...Ch. 0 - Prob. 0.92CHPCh. 0 - Prob. 0.93CHP
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- Suppose that you are closing a cabin in the north woods for the winter and you do not want the water in the toilet tank to freeze. You know that the temperature might get as low as 30. C, and you want to protect about 4.0 L water in the toilet tank from freezing. Calculate the volume of ethylene glycol (density = 1.113 g/mL; molar mass = 62.1 g/mol) you should add to the 4.0 L water.arrow_forwardPotassium sulfate has a solubility of 15 g/ 100 g water at 40C. A solution is prepared by adding 39.0 g of potassium sulfate to 225 g of water, carefully heating the solution, and cooling it to 40C. A homogeneous solution is obtained. Is this solution saturated, unsaturated, or supersaturated? The beaker is shaken, and precipitation occurs. How many grams of potassium sulfate would you expect to crystallize out?arrow_forwardA soft drink contains an unknown mass of citric acid, C3H5O(COOH)3. It requires 6.42 mL of 9.580 × 10−2-M NaOH to neutralize the citric acid in 10.0 mL of the soft drink. C3H5O(COOH)3(aq) + 3 NaOH(aq) → Na3C3H5O(COO)3(aq) + 3 H2O(ℓ) Determine which step in these calculations for the mass of citric acid in 1 mL soft drink is incorrect? Why? n (NaOH) = (6.42 mL)(1L/1000 mL)(9.580 × 10−2 mol/L) n (citric acid) = (6.15 × 10−4 mol NaOH) × (3 mol citric acid/1 mol NaOH) m (citric acid in sample) = (1.85 × 10−3 mol citric acid) × (192.12 g/mol citric acid) m (citric acid in 1 mL soft drink) = (0.354 g citric acid)/(10 mL soft drink) Determine the correct result.arrow_forward
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