COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 4, Problem 44QAP
To determine
The force that would correspond to
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• The first step in determining fault at the crash scene is to determine the coefficient of friction between the tires and the road. Here is what you
know:
• 1. A team was sent to the scene to complete the data collection needed for you to determine the coefficient of friction. To do this, the data
collector drags a 13-265kg tire across the pavement. The force meter shows a force of 100N is needed to drag the tire at constant velocity. We
also know that the coefficient of friction for the truck's tires is only 70% of the value for the car's tires.
The weight of the car is
Newtons (Round to the nearest whole number)
• Analyze the beam shown for reactions, shear and bending moment.
Include the sign (+ or -) for final answers with 2 decimals.
P=15 kN
M=25 kN-m
w=7 kN/m
3 m
4 m
4 m
A
B
C
What is the slope of the shear diagram between D and E?
O-7
O +7
O -7/3
O +7/3
O-3
4 m
D
E
• Part A
A 1500 kg car traveling at an unsafe speed of
140 km/h skids to a halt, leaving 85-m-long skid
marks.
What is the coefficient of kinetic friction between the car's tires and the road?
Express your answer numerically.
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Chapter 4 Solutions
COLLEGE PHYSICS
Ch. 4 - Prob. 1QAPCh. 4 - Prob. 2QAPCh. 4 - Prob. 3QAPCh. 4 - Prob. 4QAPCh. 4 - Prob. 5QAPCh. 4 - Prob. 6QAPCh. 4 - Prob. 7QAPCh. 4 - Prob. 8QAPCh. 4 - Prob. 9QAPCh. 4 - Prob. 10QAP
Ch. 4 - Prob. 11QAPCh. 4 - Prob. 12QAPCh. 4 - Prob. 13QAPCh. 4 - Prob. 14QAPCh. 4 - Prob. 15QAPCh. 4 - Prob. 16QAPCh. 4 - Prob. 17QAPCh. 4 - Prob. 18QAPCh. 4 - Prob. 19QAPCh. 4 - Prob. 20QAPCh. 4 - Prob. 21QAPCh. 4 - Prob. 22QAPCh. 4 - Prob. 23QAPCh. 4 - Prob. 24QAPCh. 4 - Prob. 25QAPCh. 4 - Prob. 26QAPCh. 4 - Prob. 27QAPCh. 4 - Prob. 28QAPCh. 4 - Prob. 29QAPCh. 4 - Prob. 30QAPCh. 4 - Prob. 31QAPCh. 4 - Prob. 32QAPCh. 4 - Prob. 33QAPCh. 4 - Prob. 34QAPCh. 4 - Prob. 35QAPCh. 4 - Prob. 36QAPCh. 4 - Prob. 37QAPCh. 4 - Prob. 38QAPCh. 4 - Prob. 39QAPCh. 4 - Prob. 40QAPCh. 4 - Prob. 41QAPCh. 4 - Prob. 42QAPCh. 4 - Prob. 43QAPCh. 4 - Prob. 44QAPCh. 4 - Prob. 45QAPCh. 4 - Prob. 46QAPCh. 4 - Prob. 47QAPCh. 4 - Prob. 48QAPCh. 4 - Prob. 49QAPCh. 4 - Prob. 50QAPCh. 4 - Prob. 51QAPCh. 4 - Prob. 52QAPCh. 4 - Prob. 53QAPCh. 4 - Prob. 54QAPCh. 4 - Prob. 55QAPCh. 4 - Prob. 56QAPCh. 4 - Prob. 57QAPCh. 4 - Prob. 58QAPCh. 4 - Prob. 59QAPCh. 4 - Prob. 60QAPCh. 4 - Prob. 61QAPCh. 4 - Prob. 62QAPCh. 4 - Prob. 63QAPCh. 4 - Prob. 64QAPCh. 4 - Prob. 65QAPCh. 4 - Prob. 66QAPCh. 4 - Prob. 67QAPCh. 4 - Prob. 68QAPCh. 4 - Prob. 69QAPCh. 4 - Prob. 70QAPCh. 4 - Prob. 71QAPCh. 4 - Prob. 72QAPCh. 4 - Prob. 73QAPCh. 4 - Prob. 74QAPCh. 4 - Prob. 75QAPCh. 4 - Prob. 76QAPCh. 4 - Prob. 77QAPCh. 4 - Prob. 78QAPCh. 4 - Prob. 79QAPCh. 4 - Prob. 80QAPCh. 4 - Prob. 81QAPCh. 4 - Prob. 82QAPCh. 4 - Prob. 83QAPCh. 4 - Prob. 84QAPCh. 4 - Prob. 85QAPCh. 4 - Prob. 86QAPCh. 4 - Prob. 87QAPCh. 4 - Prob. 88QAPCh. 4 - Prob. 89QAPCh. 4 - Prob. 90QAPCh. 4 - Prob. 91QAPCh. 4 - Prob. 92QAPCh. 4 - Prob. 93QAPCh. 4 - Prob. 94QAPCh. 4 - Prob. 95QAPCh. 4 - Prob. 96QAPCh. 4 - Prob. 97QAPCh. 4 - Prob. 98QAPCh. 4 - Prob. 99QAPCh. 4 - Prob. 100QAPCh. 4 - Prob. 101QAPCh. 4 - Prob. 102QAPCh. 4 - Prob. 103QAP
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- Problem The coefficient of friction between blocks is us = 0.4, at what angle will the block start sliding if it is initially at rest? to Solution Let us obtain the net force in the axis perpendicular to the inclined plane. By virtue of the first law of motion (equilibrium), the net force is 2 F perpendicular =n- Fgperpendicular = %3D Thus, the normal force is n = m CoS On the axis parallel to the inclined, the net force is E FI| = Fg|| -fs,max = Substituting the forces, we get the following: mg smgarrow_forwardA stockroom worker pushes a box with mass 11.6 kg on a horizontal surface with a constant speed of 3.40 m/s. The coefficient of kinetic Part A friction between the box and the surface is 0.21. What horizontal force must the worker apply to maintain the motion? Express your answer with the appropriate units. HA ? F = Value Units Submit Request Answerarrow_forwardProblem-solving questions At the back of the leg, two muscles pull on the Achilles tendon to create an upward force. Estimate the nett force if cach muscle has a diameter of about 5.0 mm and exerts a force in a direction of 25° from the vertical. (Use a force per unit area of muscle of 7x10° N/m²). An 18 kg penguin slides down an iceberg at an angle of 15° to the horizontal. Friction between the penguin's body and the ice surface is negligible. Determine the normal force acting on the penguin and its acceleration down the iceberg. A manufacturer of children's slides does some tests and discovers that the slope of a slippery slide must be at least 25° to the horizontal for the slide to work. The child involved in doing the testing weighs 35 kg. What is the coefficient of static friction between the child and the slide? A car drives onto a section of the road which is covered in ice. The driver attempts to stop by hitting the brakes but the wheels lock and the car skids for another 60 m.…arrow_forward
- DI Many physical properties, such as force and mass, cannot be measured directly. Rather, some other physical property is measured and the desired physical property is computed from the results. For example, a bathroom scale does not actually measure mass or "weight," but rather the compression distance of a spring. The numerical values on the scale are calibrated from the compression 11 distance using basic physics principles such as Newton's second law. Coefficients of friction cannot be measured directly. In this problem, we are going to learn how we can indirectly measure the coefficient of kinetic friction between two surfaces by directly measuring the expansion of a spring. Consider a 3.23 kg block that is dragged by a spring on a (relatively) frictionless horizontal surface at constant velocity. Suppose the block reaches a rough patch and the spring stretches by 3.25 cm. Compute the coefficient of kinetic friction u between the block and the rough patch if the spring has a force…arrow_forwardPART A) What is the maximum force that can be applied to a bone whose minimum cross-sectional area is 3.0cm^2? (This is approximately the cross-sectional area of a tibia, or shin bone, at its narrowest point.) Express your answer using two significant figures. PART B) Estimate the maximum height from which a 70kg man could jump and not fracture the tibia. Take the time between when he first touches the floor and when he has stopped to be 0.006s, and assume that the stress is distributed equally between his legs. Express your answer using two significant figures. Thank you!!!arrow_forwardMang Juan connected a spring to a wall, mounted horizontally. Juana his daughter pulls the spring to the right stretching the spring by 30 cm. If the pulling force exerted on the spring is 90 N, calculate the spring constant of the spring.arrow_forward
- Using an everyday example, explain a situation where friction is detrimental. In your answer specify the type of friction involved and how it acts in a detrimental manner.arrow_forwardCategorize The block is pulled by a force and the surface is rough, so the block and the surface are modeled as ---Select-- |system with a nonconservative force. A Block Pulled on a Rough Surface A 5.0 kg block initially at rest is pulled to the right along a horizontal surface by a constant horizontal force of Analyze Figure (a) illustrates this situation. Neither the normal force nor the gravitational force does work on the system because their points of application are displaced horizontally. 21 N. Find the work done on the system by the applied force (Use the following as necessary: F and Ax.): (a) A block pulled to the right on a rough SWother forces- W. surface by a constant horizontal force. Apply the particle in equilibrium model to the block in the vertical direction (Use the following as necessary: F, Ax, m, and g.): ▼ mg Efy =0-n - mg = 0 → n = (b) The applied force is at an angle o to the Find the magnitude of the friction force (in N): horizontal. Substitute the energies…arrow_forwardA horizontal force, F_{1} = 55N and a force, F_{2} = 12.5N acting at an angle of to the horizontalare applied to a block of mass m = 4.5kg The coefficient of kinetic friction between the block and the surface is u_{k} = 0.2 The block is moving to the right Solve numerically for the magnitude if acceleration of yhe block , - in m/s^2 if 0=30 degreesarrow_forward
- Problem The coefficient of friction between blocks is us = 0.4, at what angle will the block start sliding if it is initially at rest? to Solution Let us obtain the net force in the axis perpendicular to the inclined plane. By virtue of the first law of motion (equilibrium), the net force is perpendicular =n- Fgperpendicular= Thus, the normal force is n = m cos On the axis parallel to the inclined, the net force is 2 FI| = Fg||-fs,max= Substituting the forces, we get the following: mg smg By simplifying, we get the following: tan(theta) = mus Thus, the angle that the object will slide is: (rounded of to the ones)arrow_forwardi %AT lI. 团 / مستند بلا عنوان -> Q1/ Replace the force and couple system acting on the member in Fig.by an equivalent resultant force and couple moment acting at point A. 130lb 300lb.ft 1 ft -801b 200Ib II >arrow_forwardSolve numerically for the magnitude of the normal force, FN in Newtons, that acts on the block if θ = 30°. FN = B) solvearrow_forward
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