Introduction To Health Physics
5th Edition
ISBN: 9780071835275
Author: Johnson, Thomas E. (thomas Edward), Cember, Herman.
Publisher: Mcgraw-hill Education,
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Concept explainers
Question
Chapter 4, Problem 4.1P
To determine
The kinetic energy of the beta particle.
Expert Solution & Answer
Answer to Problem 4.1P
Kinetic energy of beta particle =
Explanation of Solution
Given Information:
Atomic mass of daughter beta particle =
Energy of beta particle is equivalent to a change in masses of the atomic element.
Conclusion:
Most energetic Beta particles have a kinetic energy of
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Students have asked these similar questions
Copper-63 has a nucleus mass of 62.92959 u. Its atomic number is 29, and its atomic mass number is 63.
The mass of a proton is 1.007276 u and the mass of a neutron is 1.008664 u
What is the total binding energy of the nucleus? Express your answer in MeV and keep 4 significant digits.
The isotope cobalt-60 has a nuclear mass of 59.933820 u. Calculate the mass defect of cobalt-60 using the following information:
Mass of Proton: 1.007825 u
Mass of Neutron: 1.008665 u
1 u = 931.5 MeV
The nucleus of a fictitious element consists of 15 protons and 16 neutrons. The mass of the respective atom is
31.021 u. Calculate the nuclear binding energy per nucleon, in MeV. The mass of the hydrogen atom is
1.007825 u, the mass of the neutron is 1.008665 u.
Chapter 4 Solutions
Introduction To Health Physics
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