Loose Leaf For Explorations:  Introduction To Astronomy
Loose Leaf For Explorations: Introduction To Astronomy
9th Edition
ISBN: 9781260432145
Author: Thomas T Arny, Stephen E Schneider Professor
Publisher: McGraw-Hill Education
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Chapter 4, Problem 3EP
To determine

The how much slowly does the time runs in the given two places.

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Suppose that a planet were discovered between the Sun and Mercury, with a circular orbit of radius equal to 2/3 of the average orbit radius of Mercury. What would be the orbital period of such a planet? (Such a planet was once postulated, in part to explain the precession of Mercury's orbit. It was even given the name Vulcan, although we now have no evidence that it actually exists. Mercury's precession has been explained by general relativity.)
The mass of Mars is M = 6,42 · 1023 kg, and its radius is R = 3396 km.a) Determine the gravitational acceleration on the surface of Mars.b) How high can an astronaut jump on Mars and how high on Earth if in both caseshe leaves the ground with a starting speed v0 = 1 m/s?The value of the gravitational constant is G = 6,67 · 10−11 m3 kg−1s−2.
So let's consider a person with a mass of 51.0 kg standing on the Earth. To find the gravitational force on the person, we'll again use Newton's law of universal gravitation with the Earth as  m2  and the radius of the Earth for the distance F =  GmME RE2 . Now all we need to do is substitute values and calculate. We already said  m = 51.0 kg,  and we know  G = 6.67 ✕ 10−11 N · m2/kg2.  The Earth is not a perfect sphere, but, its average radius is  RE = 6.37 ✕ 106 m.  The mass of the Earth is  ME = 5.97 ✕ 10−24 kg.  We can then substitute these values in the following formula. (Enter your answer in N.) F =  (6.67 ✕ 10−11 N · m2/kg2)(51.0 kg)(5.97 ✕ 1024 kg) (6.37 ✕ 106 m)2 (A) = _______ N Now let's compare this result to the person's weight (in N) found by multiplying the person's mass by g (or, that is,  w = mg)  where  g = 9.80 m/s2. w = (51.0 kg)(9.80 m/s2) =(b) __________________ N   You should have found that these two methods give about the same result!…
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