Modern Physics
3rd Edition
ISBN: 9781111794378
Author: Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher: Cengage Learning
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 4, Problem 32P
(a)
To determine
The corrected wavelength of hydrogen for the first Balmer line taking the nuclear motion into account.
(b)
To determine
The corrected wavelength of deuterium for the first Balmer line taking the nuclear motion into account.
(c)
To determine
The corrected wavelength of tritium for the first Balmer line taking the nuclear motion into account.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solutionStudents have asked these similar questions
A particle has γ=2,865.
a) Calculate c-v in m/s.
If your calculator gives problems, you might want to solve the appropriate equation for c-v or c(1 - v/c) and use an approximation.
b) In the previous problem, in a race to the moon, by 3/4ths the distance, light is one or ten meters ahead of the particle. We routinely approximate mass as zero, gamma as infinite, and speed as the speed of light. ("Massless particles" -- gamma and m have to be eliminated from the expressions. Light is a true massless particle.)
If a massless particle has momentum 2,910 MeV/c, calculate its energy in MeV.
A linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 19 x 106 m/s, causing the two particles to annihilate.If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 10-4 u, or 9.109 x 10-31 kg.Note: Assume that the kinetic energy is also converted into the gamma rays, and is included in the two photons.
A linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 29 x 106 m/s, causing the two particles to annihilate.If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 10-4 u, or 9.109 x 10-31 kg.
Chapter 4 Solutions
Modern Physics
Ch. 4.2 - Exercise 1 Find the horizontal speed vx for this...Ch. 4.2 - Prob. 2ECh. 4.3 - Prob. 3ECh. 4.3 - Prob. 4ECh. 4.3 - Prob. 5ECh. 4 - Prob. 1QCh. 4 - Prob. 2QCh. 4 - Prob. 3QCh. 4 - Prob. 4QCh. 4 - Prob. 5Q
Ch. 4 - Prob. 6QCh. 4 - Prob. 7QCh. 4 - Prob. 8QCh. 4 - Prob. 9QCh. 4 - Prob. 10QCh. 4 - Prob. 11QCh. 4 - Prob. 1PCh. 4 - Prob. 2PCh. 4 - A mystery particle enters the region between the...Ch. 4 - Prob. 4PCh. 4 - A Thomson-type experiment with relativistic...Ch. 4 - Prob. 6PCh. 4 - Prob. 8PCh. 4 - Prob. 9PCh. 4 - Prob. 10PCh. 4 - Prob. 11PCh. 4 - Prob. 12PCh. 4 - Prob. 13PCh. 4 - Prob. 14PCh. 4 - Prob. 15PCh. 4 - Prob. 16PCh. 4 - Prob. 17PCh. 4 - Prob. 18PCh. 4 - Prob. 19PCh. 4 - Prob. 20PCh. 4 - Prob. 21PCh. 4 - Prob. 22PCh. 4 - Prob. 23PCh. 4 - Prob. 24PCh. 4 - Prob. 25PCh. 4 - Prob. 26PCh. 4 - Prob. 27PCh. 4 - Prob. 28PCh. 4 - Prob. 29PCh. 4 - Prob. 30PCh. 4 - Prob. 31PCh. 4 - Prob. 32PCh. 4 - Prob. 33PCh. 4 - Prob. 34PCh. 4 - Prob. 35PCh. 4 - Prob. 36PCh. 4 - Prob. 37PCh. 4 - Prob. 38PCh. 4 - Prob. 39PCh. 4 - Prob. 40PCh. 4 - Prob. 41PCh. 4 - Prob. 42PCh. 4 - Prob. 43PCh. 4 - Prob. 44P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- Electron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (You will make life much easier for yourself if you recognize that practically all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forwardElectron capture is a variant on beta-radiation. The lightest nucleus to decay by electron capture is 7Be -- beryllium-7. The daughter nucleus is 7Li -- lithium-7. The electron is transformed into a massless particle (a neutrino): e − + 7 B e + ⟶ 7 L i + ν The initial electron is bound in the atom, so the beryllium mass includes the electron. In fact, since the electron starts bound in the atom, a more-accurate statement of the nuclear reaction is probably: 7 B e ⟶ 7 L i + ν The masses are beryllium: 7.016929 u, and lithium: 7.016003 u, and refer to the neutral atom as a whole. (Use uc and uc2 as your momentum and energy units -- but carry them along in your calculation.) The initial beryllium atom is stationary. Calculate the speed of the final lithium nucleus in km/s. (all the energy released goes into the lighter particle. c = 300,000 km/s)arrow_forwardThe very high speeds of alpha particles make them suitable for experiments that probe the nature of matter. A nucleus ejects an alpha particle with a kinetic energy of 8.3 MeV, a typical energy. How fast is the alpha particle moving?arrow_forward
- A Carbon-14 nucleus is initially at rest but emits two particles of radiation; one with momentum 5.8x10-21kgm/s[E], and another with momentum 4.5x10-21kgm/s[S]. If the residual Carbon-14 mass is 2.3x10-26kg; a. Determine the residual Carbon 14 momentum magnitude b. Determine the residual Carbon 14 momentum direction c. determine the residual Carbon 14 velocity.arrow_forwardAn iron nail has a mass of 15.0 g. What is the energy (in Joules) that would be required to break all the iron nuclei into their constituent protons and neutrons? Ignore the energy that binds the electrons to the nucleus and the energy that binds one atom to another in the structure of the metal. For simplicity, assume that all the iron nuclei are 56 Fe (atomic mass = 55.934 939 u).arrow_forwardIn solid helium the spacing between atoms is about 3Å . Helium contains 2 protons and 2 neutrons, so the mass of a helium atom is 6.6×10−27 kg. What is the smallest possible energy of a helium atom in solid helium? What temperature (in Kelvin) does this energy correspond with? (Boltzmann's constant is kb=1.38×10−23 J/Karrow_forward
- Quarks and gluons are fundamental particles. A proton, which is a bound state of two up quarks and a down quark, has a rest mass of mp = 1.67 x 10-27 kg. This is significantly greater than the sum of the rest mass of the up quarks, which is mu = 4.12 x 10-30 kg each, and the rest mass of the down quark, which is md = 8.59 x 10-30 kg. Suppose we (incorrectly) model the rest energy of the proton mpc2 as derived from the kinetic energy of the three quarks, and we split that energy equally among them. (a) Estimate the Lorentz factor γ = (1 - v2/c2) -1/2 for each of the up quarks using Eq. (as given). (b) Similarly estimate the Lorentz factor g for the down quark. (c) Are the corresponding speeds vu and vd greater than 99% of the speed of light? (d) More realistically, the quarks are held together by massless gluons, which mediate the strong nuclear interaction. Suppose we model the proton as the three quarks, each with a speed of 0.90c, with the remainder of the proton rest energy supplied…arrow_forwardTask 3 a. If the Pressure produced by the gas cylinder of the motor of the rocket is governed by the below equation: P = sin*(V)cos³ (V) And the energy is given by: V2 w - ["nar W = PdV V1 i. If V2=2V1, Find W. ii. What will be W if V2=4V1. iii. Use Matlab or excel to plot the Energy in the interval [0,2n]arrow_forwardA triply ionised beryllium atom (Be+++, Z = 4) has only one electron in orbit about the nucleus. If the electron decays from the n = 3 level to the first excited state (n = 2), calculate the wavelength of the photon emitted. give your answer in units of nm, rounded to one decimal place.arrow_forward
- A neutron with a speed of 1.2 x 106 ms collides with a stationary deuterium nucleus. What percentag of energy is lost? A deuterium nucleus has twice the mass of a neutronarrow_forwardA neutron with a kinetic energy of 6.0 eV collides with a stationary hydrogen atom in its ground state. Explain why the collision must be elastic—that is, why kinetic energy must be conserved. (Hint: Show that the hydrogen atom cannot be excited as a result of the collision.)arrow_forwardAn atom of mass m₁ = m moves in the positive x direc- tion with speed v₁ = v. It collides with and sticks to an atom of mass m₂ = 2m moving in the positive y direction with speed v₂ = 2v/3. Find the resultant speed and direc- tion of motion of the combination, and find the kinetic energy lost in this inelastic collision.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
- Modern PhysicsPhysicsISBN:9781111794378Author:Raymond A. Serway, Clement J. Moses, Curt A. MoyerPublisher:Cengage LearningPrinciples of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
Modern Physics
Physics
ISBN:9781111794378
Author:Raymond A. Serway, Clement J. Moses, Curt A. Moyer
Publisher:Cengage Learning
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning