Modern Physics
2nd Edition
ISBN: 9780805303087
Author: Randy Harris
Publisher: Addison Wesley
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Chapter 3, Problem 46E
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Could an experiment involving electron diffraction be conducted with three or four slits? Employing a grating with several slits? What type of outcomes might you anticipate with a grating? Would this violate the uncertainty principle? Explain.
This question is modern physics from the waves and particles chapter:
An electron beam strikes a barrier with a single narrow slit, and the electron flux – number of electrons per unit time per unit area – detected at the very center of the resulting intensity pattern is F_1. Next, two more identical slits are opened equidistant on either side of the first and equally “illuminated” by the beam. What wil be the flux at the very center now? Does your answer imply that ore than three times as many electrons pass through three slits than through one? Why or why not?
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Chapter 3 Solutions
Modern Physics
Ch. 3 - Prob. 1CQCh. 3 - Prob. 2CQCh. 3 - Prob. 3CQCh. 3 - Prob. 4CQCh. 3 - Prob. 5CQCh. 3 - Prob. 6CQCh. 3 - Prob. 7CQCh. 3 - A ball rebounds elastically from the floor. What...Ch. 3 - Prob. 9CQCh. 3 - Prob. 10CQ
Ch. 3 - Prob. 11ECh. 3 - Prob. 12ECh. 3 - Prob. 13ECh. 3 - Prob. 14ECh. 3 - Prob. 15ECh. 3 - Prob. 16ECh. 3 - Prob. 17ECh. 3 - What is the stopping potential when 250 nm...Ch. 3 - Prob. 19ECh. 3 - Prob. 20ECh. 3 - Prob. 21ECh. 3 - Prob. 22ECh. 3 - Prob. 23ECh. 3 - Prob. 24ECh. 3 - Prob. 25ECh. 3 - Prob. 26ECh. 3 - Prob. 27ECh. 3 - Prob. 28ECh. 3 - Prob. 29ECh. 3 - Prob. 30ECh. 3 - Prob. 31ECh. 3 - Prob. 32ECh. 3 - Prob. 33ECh. 3 - Prob. 34ECh. 3 - Prob. 35ECh. 3 - Prob. 36ECh. 3 - Verify that the Chapter 2 formula KE=mc2 applies...Ch. 3 - Prob. 38ECh. 3 - Prob. 39ECh. 3 - Prob. 40ECh. 3 - Prob. 41ECh. 3 - Prob. 42ECh. 3 - Prob. 43ECh. 3 - Prob. 44ECh. 3 - Prob. 45ECh. 3 - Prob. 46ECh. 3 - Prob. 47CECh. 3 - Prob. 49CECh. 3 - Prob. 50CECh. 3 - Prob. 51CECh. 3 - Prob. 52CECh. 3 - Prob. 53CECh. 3 - Prob. 54CECh. 3 - Prob. 55CE
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- How fast should an electron move such that its kinetic energy is equal to the energy of a red photon (λ = 722 nm). For simplicity, express your answer as v x 105 m/s and type in just the value of v. Use three significant figures in your answer.arrow_forwardDetermine the de Broglie wavelength for i. an electron (mass = 9.1 x 10-31 kg) moving at a speed of 6.0 × 10 m/s and ii. a baseball (mass = 0.15 kg) moving at a speed of 13 m/s. iii. Can you explain why does the baseball not show any diffraction pattern if it passes through the window of width ~ 1m?arrow_forwardA linear particle accelerator using beta particles collides electrons with their anti-matter counterparts, positrons. The accelerated electron hits the stationary positron with a velocity of 77 x 10° m/s, causing the two particles to annihilate. If two gamma photons are created as a result, calculate the energy of each of these two photons, giving your answer in MeV (mega electron volts), accurate to 1 decimal place. Take the mass of the electron to be 5.486 x 104 u, or 9.109 x 1031 kg. Note: Assume that the kinetic energy is also converted into the gamma rays, and is included in the two photons.arrow_forward
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