COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 2, Problem 37QAP
To determine
The average speed of a jogger in order to travel
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= 4.5 km
1-5 km
Avera
(a) Average velocity
= 2-25 km/h
(40/60) h
4.5 km
(b) Average speed =
= 6-75 km/h
%3D
(40/60) h
Example 6 On a 80 km track, a train
travels 40 km with a uniform speed of 30 km h-l.
How fast must the train travel the next 40 km so
as to have average speed 40 km h-l for the entire
trip ?
Ex
at 8.00 a
University Physics 1 - Kinematics;
Can an object have a velocity with zero acceleration? Can an object have acceleration with zero velocity? Explain why or why not.
2. Is it possible for an object to be zero speed when its acceleration is not zero? Explain
with an example.
Chapter 2 Solutions
COLLEGE PHYSICS
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- A hiker walks 3.00 km north and then 4.00 km west, all in one hour and forty minutes, (a) Calculate his average speed in km/h. (b) Calculate the magnitude of his average velocity. (See Section 3.2 and 3.3.)arrow_forwardA student drives the 100-mi trip back to campus after spring break and travels with an average speed of 52 mi/h for 1 hour and 30 minutes for the first part of the trip. (a) What distance was traveled during this time? (b) Traffic gets heavier, and the last part of the trip takes another half-hour. What was the average speed during this leg of the trip? (c) Find the average speed for the total trip.arrow_forwardIs it possible for velocity to be constant while acceleration is not zero? Explain.arrow_forward
- A jogger jogs from one end to the other of a straight track in 2.50 min and then back to the starting point in 3.20 min. What is the joggers average speed (a) in jogging to the far end of the track, (b) coming back to the starting point, and (c) for the total jog?arrow_forwardProfessional Application: A woodpecker's brain is specially protected from large decelerations by tendon-like attachments inside the skull. While pecking on a tree, the woodpecker's head comes to a stop from an initial velocity of 0.600 m/s in a distance of only 2.00 mm. (a) Find the acceleration in m/s2 and in multiples of g(g=9.80m/s2). (b) Calculate the stopping time. (c) The tendons cradling the brain stretch, making its stopping distance 4.50 mm (greater than the head and, hence, less deceleration of the brain). What is the brain's deceleration, expressed in multiples of g?arrow_forwardThere is a distinction between average speed and the magnitude of average velocity. Give an example fiat illustrates the difference between these two quantities.arrow_forward
- An apple is falling from an apple tree. Which of the following statements is true? O a. Speed and acceleration of the apple remains constant O b. Speed of the apple decreases and its acceleration remains constant O c. Speed of the apple remains constant and its acceleration increases O d. Speed of the apple increases and its acceleration remains constant Which of the following l-V graph represents ohmic conductors? O a. Ob. IA Oc. O d.arrow_forwardAn athlete runs some distance before taking a jump. Explain?arrow_forwardCan an object have an acceleration of zero and a velocity that is not zero? Explain why or give an example. Can an object have a velocity of zero and an acceleration that is not zero? Explain why or give an example.arrow_forward
- a person travels by car from city to another with a different constant speeds between pairs of cities. She drives for 40.0 min at 85.0km/h, 8.0min at 50.0km/h, 50.0min at 30.0km/h and dpends 50min eating lunch and buying gas. A)determine the average speed for the trip in km/h B)determine the distance between the initial and final cities along the route in km.arrow_forwardCan an object be increasing in speed as its acceleration decreases? If so, give an example. If not, explain.arrow_forward4- Chapter 4- questn-24 The position of an ion at the first is given by = 5.01 -6.0J +2.0k, the position of the ion after 10 s is --2.01 + 8.0) - 2.0k, where the positions are in meters. What is the average velocity of the ion in this process. Option 1 -0.71+ 1.4] -0.4k -0.71 + 14J +0.4k 0.71 + 14 -04k Option 2 Option 3 Option 4 -0.71 - 14 -0.4k Option 5 1.71- L0J - 0.4karrow_forward
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