COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 2, Problem 17QAP
To determine
At which lettered point is the object moving the fastest
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COLLEGE PHYSICS
Ch. 2 - Prob. 1QAPCh. 2 - Prob. 2QAPCh. 2 - Prob. 3QAPCh. 2 - Prob. 4QAPCh. 2 - Prob. 5QAPCh. 2 - Prob. 6QAPCh. 2 - Prob. 7QAPCh. 2 - Prob. 8QAPCh. 2 - Prob. 9QAPCh. 2 - Prob. 10QAP
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- (a) Explain how you can use the graph of position versus time in Figure 2.54 to describe the change in velocity over time, Identify (b) the time (ta, tb, tc, td, or te) at which the instantaneous velocity is greatest, (c) the time at which it is zero, and (d) the time at which it is negative,arrow_forwardA hiker walks 3.00 km north and then 4.00 km west, all in one hour and forty minutes, (a) Calculate his average speed in km/h. (b) Calculate the magnitude of his average velocity. (See Section 3.2 and 3.3.)arrow_forwardA person takes a trip, driving with a constant speed of 89.5 km/h, except for a 22.0-min rest stop. If the persons average speed is 77.8 km/h, (a) how much time is spent on the trip and (b) how far does the person travel?arrow_forward
- A steam catapult launches a jet aircraft from the aircraft carrier John C. Stennis, giving it a speed of 175 mi/h in 2.50 s. (a) Find the average acceleration of the plane. (b) Modeling the acceleration as constant, find the distance the plane moves in this time interval.arrow_forwardA person lakes a trip, driving with a constant speed of 89.5 km/h, except, for a 22.0-min rest stop. If the persons average speed is 77.8 km/h, (a) how much time is spent on the trip and (b) how far does the person travel?arrow_forwardFind the following for path B in Figure 2.59: (a) The distance traveled. (b) The magnitude of the displacement from start to finish. (c) The displacement from start to finish.arrow_forward
- Compare the distance traveled of an object that undergoes a change in velocity that Is twice its initial velocity with an object that changes its velocity by four times its initial velocity over the same time period. The accelerations of both objects are constant.arrow_forwardThe Acela is an electric train on the Washington-New YorkBoston run, carrying passengers at 170 mi/h. A velocity-time graph for the Acela is shown in Figure P2.69. (a) Describe the train's motion in each successive lime interval, (b) Find the trains peak positive acceleration in the motion graphed, (c) Find the trains displacement in miles between t = 0 and t = 200 s.arrow_forwardA car is traveling east at 25.0 m/s when it turns north and accelerates to 35.0 m/s, all during a time of 6.00 s. Calculate the magnitude of the car's average acceleration. (See Section 3.3.)arrow_forward
- The Acela is an electric train on the WashingtonNew YorkBoston run, carrying passengers at 170 mi/h. A velocitytime graph for the Acela is shown in Figure P2.46. (a) Describe the trains motion in each successive time interval. (b) Find the trains peak positive acceleration in the motion graphed. (c) Find the trains displacement in miles between t = 0 and t = 200 s. Figure P2.46 Velocity versus time graph for the Acela.arrow_forwardAn object moves with constant acceleration 4.00 m/s2 and over a lime interval reaches a final velocity of 12.0 m/s. (a) If its initial velocity is 6.00 m/s, what is its displacement during the time interval? (b) What is the distance it travels during this interval? (c) If its initial velocity is -6.00 m/s, what is its displacement during points, (d) Does the change in speed of the downward-moving rock agree with the magnitude of the speed change of the rock moving upward between the same elevations? (e) Explain physically why it does or does not agree.arrow_forward(a) Calculate the height of a cliff if it takes 2.35 s for a rock to hit the ground when it is thrown straight up from the cliff with an initial velocity of 8.00 m/s. (b) How long would it take to reach the ground if it is thrown straight down with the same speed?arrow_forward
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Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY