The zero−bias capacitance of a silicon pn junction diode is C j o = 0.02 pF and the built−in potential is V b i = 0.80 V . The diode is reverse biased through a 47 − k Ω resistor and a voltage source. (a) For t < 0 , the applied voltage is 5 V and, at t = 0 , the applied voltage drops to zero volts. Estimate the time it takes for the diode voltage to change from 5 V to 1.5 V. (As an approximation, use the average diode capacitance between the two voltage levels.) (b) Repeat part (a) for an input voltage change from 0 V to 5 V and a diode voltage change from 0 V to 3.5 V. (Use the average diode capacitance between these two voltage levels.)
The zero−bias capacitance of a silicon pn junction diode is C j o = 0.02 pF and the built−in potential is V b i = 0.80 V . The diode is reverse biased through a 47 − k Ω resistor and a voltage source. (a) For t < 0 , the applied voltage is 5 V and, at t = 0 , the applied voltage drops to zero volts. Estimate the time it takes for the diode voltage to change from 5 V to 1.5 V. (As an approximation, use the average diode capacitance between the two voltage levels.) (b) Repeat part (a) for an input voltage change from 0 V to 5 V and a diode voltage change from 0 V to 3.5 V. (Use the average diode capacitance between these two voltage levels.)
Solution Summary: The author explains the value of the zero capacitance and the built-in potential of a pn junction diode.
The zero−bias capacitance of a silicon pn junction diode is
C
j
o
=
0.02
pF
and the built−in potential is
V
b
i
=
0.80
V
. The diode is reverse biased through a
47
−
k
Ω
resistor and a voltage source. (a) For
t
<
0
, the applied voltage is 5 V and, at
t
=
0
, the applied voltage drops to zero volts. Estimate the time it takes for the diode voltage to change from 5 V to 1.5 V. (As an approximation, use the average diode capacitance between the two voltage levels.) (b) Repeat part (a) for an input voltage change from 0 V to 5 V and a diode voltage change from 0 V to 3.5 V. (Use the average diode capacitance between these two voltage levels.)
Full-wave rectified sine wave circuit is used to measure the RMS value of a half square wave with the help of PMMC meter. The meter was actually calibrated for sine wave. The circuit uses a meter movement with a full scale deflection current of 200uA and internal meter resistance of 5kΩ. Assuming Non-ideal diodes having resistance 1kΩ, Analyze the circuit to determine the value of series multiplier resister and the corrected RMS voltage, if meter is to read 225V RMS full-scale.
A forward voltage of 1.75V shifts to the left at a rate 2.65mV per degree
centigrade in temperature from 25°C to -35°C. What is the new forward voltage
of the diode? *
Your answer
Find the reverse saturation current of a Silicon diode that displays a forward
current of 20 mA at 0.75 V when the Thermal Voltage is 0.038 V. ( Express your
answer in 3 decimal places. Your answer can be in p (pico) or n (nano) unit. e.g.
only 5 nV. Upload your solution in the file upload question but type Final Answer
here. *
Your answer
Question 1:
In the circuit shown below, the output (Vo = 10V Max.) Unipolar. The frequency of Primary is 60 Hz. The
diodes are Silicon with VD = 0.7V.
a. Sketch the output without a Capacitor.
b. Determine Voc without a Capacitor.
c. Sketch Vs (at the Secondary).
d. Determine Voc with a Capacitor of 10 uF across RL.
e. Determine the RMS Value of Vp (at the Primary).
f. PIV (Peak Inverse Voltage).
10:1
Output
C.
22 k1
All diodes are IN4001.
|
00000
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