A rod of semiconducting material of Length L=5 m and cross-sectional area A=3 mm2 lies along the x-axis between x=0 and x=L. The material obeys ohm’s Law, and its resistivity varies along the rod according to ρ = ρ0*( 1 - x2/L2) where ρ0=4.5 x 10-4 Ω.m. The end of the rod at x=0 is at potential V0=25 V greater than the end at x=L. What is the total resistance, in units of Ω, of the rod? What is the current, in units of miliamperes, in the rod? What is the electric potential, in units of volt, in the rod at x=L/2? What is the electric-field magnitude E, in units of V/m, in the rod at x=L/2?
A rod of semiconducting material of Length L=5 m and cross-sectional area A=3 mm2 lies along the x-axis between x=0 and x=L. The material obeys ohm’s Law, and its resistivity varies along the rod according to ρ = ρ0*( 1 - x2/L2) where ρ0=4.5 x 10-4 Ω.m. The end of the rod at x=0 is at potential V0=25 V greater than the end at x=L. What is the total resistance, in units of Ω, of the rod? What is the current, in units of miliamperes, in the rod? What is the electric potential, in units of volt, in the rod at x=L/2? What is the electric-field magnitude E, in units of V/m, in the rod at x=L/2?
Physics for Scientists and Engineers: Foundations and Connections
1st Edition
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Katz, Debora M.
Chapter28: Current And Resistance
Section: Chapter Questions
Problem 68PQ
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A rod of semiconducting material of Length L=5 m and cross-sectional area A=3 mm2 lies along the x-axis between x=0 and x=L. The material obeys ohm’s Law, and its resistivity varies along the rod according to ρ = ρ0*( 1 - x2/L2) where ρ0=4.5 x 10-4 Ω.m. The end of the rod at x=0 is at potential V0=25 V greater than the end at x=L.
What is the total resistance, in units of Ω, of the rod?
What is the current, in units of miliamperes, in the rod?
What is the electric potential, in units of volt, in the rod at x=L/2?
What is the electric-field magnitude E, in units of V/m, in the rod at x=L/2?
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