A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm² lies along the x-axis between z = 0 and z = L. The material obeys Ohm's law, and its resistivity varies along the rod according to p = Po (1 where po = 5 x 10 4N · m. The end of the rod at a = 0 is at a potential Vo = 30 V greater than the end at a = L. B) What is the current, in units of miliamperes in the rod? Answer:

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(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE.
A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm2 lies along
the x-axis between e = 0 and z = L. The material obeys Ohm's law, and its resistivity varies along the rod
~(1 -).
where po = 5 x 10 4N · m. The end of the rod at z = 0 is at a potential
L²
according to p = Po
Vo = 30 V greater than the end at z = L.
B) What is the current, in units of miliamperes in the rod?
Answer:
Transcribed Image Text:(1) THE FOLLOWING QUESTIONS ARE BASED ON THE INFORMATION GIVEN HERE. A rod of semiconducting material of length L = 10 m and cross-sectional area A = 4.5 mm2 lies along the x-axis between e = 0 and z = L. The material obeys Ohm's law, and its resistivity varies along the rod ~(1 -). where po = 5 x 10 4N · m. The end of the rod at z = 0 is at a potential L² according to p = Po Vo = 30 V greater than the end at z = L. B) What is the current, in units of miliamperes in the rod? Answer:
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