A rod of semiconducting material of Length L=2 m and cross-sectional area A=4 mm2 lies along the x-axis between x=0 and x=L. The material obeys ohm’s Law, and its resistivity varies along the rod according to ρ = ρ0*( 1 - x2/L2) where ρ0=3 x 10-4 Ω.m. The end of the rod at x=0 is at potential V0=25 V greater than the end at x=L. What is the electric potential, in units of volt, in the rod at x=L/2?

A rod of semiconducting material of Length L=2 m and cross-sectional area A=4 mm2 lies along the x-axis between x=0 and x=L. The material obeys ohm’s Law, and its resistivity varies along the rod according to ρ = ρ0*( 1 - x2/L2) where ρ0=3 x 10-4 Ω.m. The end of the rod at x=0 is at potential V0=25 V greater than the end at x=L. What is the electric potential, in units of volt, in the rod at x=L/2?

Physics for Scientists and Engineers, Technology Update (No access codes included)

9th Edition

ISBN:9781305116399

Author:Raymond A. Serway, John W. Jewett

Publisher:Raymond A. Serway, John W. Jewett

Chapter27: Current And Resistance

Section: Chapter Questions

Problem 27.11OQ: Two conducting wires A and B of the same length and radius are connected across the same potential...

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