Concept explainers
The raising height of the pendulum for achieving the fracture of the specimen.
Answer to Problem 44SEP
The raising height of the pendulum for achieving the fracture of the specimen is
Explanation of Solution
Write the expression of height of the hammer when it reached
Here, raised height is
Write the expression for potential energy stored in the hammer is,
Here, potential energy stored in the hammer is
Write the expression of remaining energy after fracture of the specimen is,
Here, remaining energy stored in the hammer is
Write the expression of energy used for lifting is,
Here, mass of hammer is
Conclusion:
Below figure represent the new position of the hammer when hammer is raised to
Figure-(1)
From Figure-(1), when the hammer is rotated to an angle of
Substitute,
Substitute,
Substitute,
This remaining energy is used for lifting of hammer.
Substitute,
Thus, the raising height of the pendulum for achieving the fracture of the specimen is
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Chapter 7 Solutions
Foundations of Materials Science and Engineering
- Example A 13 mm-diameter tensile specimen has a 50 mm gage length. The load corresponding to the 0.2 percent offset is 6800 kg and the maximum load is 1800 kg. Fracture occurs at 7300 kg. The diameter after fracture is 8 mm and the gage length at fracture is 65 mm. calculate the standard properties of the material from the tension test.arrow_forwardA tensile test for a copper specimen has been performed and the following data are obtained. - Percentage of Elongation = 66 % - Percentage of Reduction in Area = 38 % - Final length after fracture = 34.6 mm - Final Diameter after fracture = 4.43 mm & - Ultimate stress = 364 1) Final Area (in mm2) = 2) Initial Area (in mm2) = 3) Ultimate Load (in N) =arrow_forwardA mild steel tensile specimen of initial length 44 mm and initial diameter 6.4 mm is subjected to a tensile test and the following data are obtained. - Yield Strength as 88 MPa - Maximum Strength as 212 MPa - Fracture Strength as 152 MPa - Percentage of Elongation as 63 % - Percentage of Reduction in area as 39% The yield load in N= The Ultimate load in N = The Fracture load in N =arrow_forward
- A tensile test specimen has a starting gage length 50 mm and a cross-sectional area 200 mm2. During the test, the specimen yields under a load of 30,000 N (this is the 0.2% offset) at a gage length of 52 mm.The maximum load of 63,000 N is reached at a gage length of 57 mm just before necking begins. Final fracture occurs at a gage length of 63.5 mm. Determine (a) yield strength, (b) modulus of elasticity, (c) tensile strength, (d) engineering strain at maximum load, and (e) percent elongation.arrow_forwardA tensile test for a copper specimen has been performed and the following data are obtained. - Percentage of Elongation = 65 % - Percentage of Reduction in Area = 39 % - Final length after fracture = 36.1 mm - Final Diameter after fracture = 4.25 mm & - Ultimate stress = 401 MPa SOLUTION: Initial Diameter (in mm) = Ultimate Load (in N) =arrow_forwardA steel plate, which has a fracture toughness in a plane strain state of 83 MPavm, is alternately loaded in tension at 750 MPa and in compression at 20 MPa. The plate must survive 15 years with the stress applied at a frequency of once every 3 min. Calculate the constant C of the material if n=2.8 . Assume that the geometric factor f=1 for all your imperfections. Internal imperfections have a size of 0.0015 mmarrow_forward
- A three-point bending test is conducted on a cylindrical specimen of aluminum oxide (E=400 GPa, Kıc=4 MPavm). This specimen has a surface crack of P um (unit in um) deep at tensile face where the maximum tensile stress occurs. If the specimen radius is 5.0 mm and the support point separation distance is 50.0 mm, predict whether or not you would expect the specimen to fracture when a load of 1000 N is applied?arrow_forwardDraw a typical stress vs strain tensile test curve for the following materials (two seperate graphs) and label the axis. A ductile metallic test specimen that is stretched to failure displaying a characteristic yield point and show the following parts on the curve. 1- Yield point 2- Ultimate Tensile Strength 3- Breaking point 4- Elastic Region 5- Plastic Region 6- Necking regionarrow_forwardA tensile test for a copper specimen has been performed and the following data are obtained. - Percentage of Elongation = 60 % - Percentage of Reduction in Area = 36 % - Final length after fracture = 35.2 mm - Final Diameter after fracture = 3.54 mm & - Ultimate stress = 439 MPa iv) Initial Diameter (in mm) = v) Ultimate Load (in N) =arrow_forward
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