Concept explainers
(a)
Interpretation:
The first and second ionization equations of the malonic acid are to be stated with the
Concept introduction:
The
(b)
Interpretation:
The ionization state of the malonic acid is to be stated at
Concept introduction:
The
(c)
Interpretation:
The number of moles of base per mole of malonic acid required to adjust the
Concept introduction:
The
(d)
Interpretation:
The reason as to why the first
Concept introduction:
The
(e)
Interpretation:
An explanation as to how the difference between the first and second
Concept introduction:
The
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Organic Chemistry
- Low-molecular-weight dicarboxylic acids normally exhibit two different pKa values. Ionization of the first carboxyl group is easier than the second. This effect diminishes with molecular size, and for adipic acid and longer chain dicarboxylic acids, the two acid ionization constants differ by about one pK unit. Why do the two pKa values differ more for the shorter chain dicarboxylic acids than for the longer chain dicarboxylic acids?arrow_forwardAcid-Base Equilibria Many factors contribute to the acidity of organic compounds. Electronegativity, resonance, induction, hybridization, aromaticity, and atomic size, all play a role. In the following comparisons, you are asked to identify the factor(s) that would be most important to analyze when predicting relative acidity, and then to predict the trend in acidity and pKa values. For each of the following pairs of compounds answer the following two multiple-choice questions. 1. What factor(s) are the most important to consider when predicting the relative acidity of the two compounds? a. Electronegativity of the atom possessing the hydrogen. b. Resonance stabilization of the anionic conjugate base. c. Inductive stabilization of the anionic conjugate base. d. Hybridization of the atom possessing the hydrogen. e. The atomic size of the atom possessing the hydrogen.arrow_forward18-28 Arrange these compounds in order of increasing acidity: benzoic acid, benzyl alcohol, phenol.arrow_forward
- When the conjugate acid of aniline, C6H5NH3+, reacts with the acetate ion, the following reaction takes place: C6H5NH3+(aq)+CH3COO(aq)C6H5NH2(aq)+CH3COOH(aq) If Kafor C6H5NH3+ is 1.35105 and Kafor CH3COOH is 1.86105 , what is K for the reaction?arrow_forwardThe following pKa values have been measured. Explain why a hydroxyl group in the para position decreases the acidity while a hydroxyl group in the meta position increases the acidity.arrow_forwardThe pKa of phenol is 10.0 and the pKa of para-nitrophenol is 7.2. Given this information, one knows that The conjugate base of para-nitrophenol must be less stable than the conjugate base of phenol The conjugate acid of para-nitrophenol must be more stable than the conjugate base of phenol The conjugate base of para-nitrophenol must be more stable than the conjugate base of phenol Both acids are basesarrow_forward
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