Organic Chemistry - Standalone book
Organic Chemistry - Standalone book
10th Edition
ISBN: 9780073511214
Author: Francis A Carey Dr., Robert M. Giuliano
Publisher: McGraw-Hill Education
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Chapter 13.18, Problem 26P
Interpretation Introduction

Interpretation:

A suitable mechanism of the given reactions is to be determined.

Concept Introduction:

A reaction usually proceeds through two different transition states, then the state that is associated with lower energy undergoes for the formation of the desired product.

A transition state is highly unstable than that of its reactants and products but determining its stability with respect to the other transition state is important for analyzing the type of reaction mechanism follows by the respective reaction.

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Cyclopropane decomposes fairly rapidly at moderate temperatures whereas cyclohexane is quite stable. Why is this the case?
Ethane reacts with chlorine (Cl2) in the presence of ultra-violet (UV) light, to produce 1-chloropropane (CH3CH2Cl) and hydrogen bromide (HCl). As shown in the equation below.CH3CH3+ Cl2→ CH3CH2Cl+ HClDescribe the reaction mechanism of the reaction between ethane and chlorine to produce 1-chloroethane. The description should be detailed and must include the type of bond fission that takes place. You may sketch and insert suitable diagrams to aid your description if you wish.
(a) Which of the following represents the equation for the reaction between ethane and chlorine in the presence of UV radiation? A C₂H + Cl₂ → C₂H₂Cl₂ + H₂ B C₂H₂ + Cl₂ → C₂H₂Cl + HCI C C₂H₂ + Cl₂ → 2CH₂CI D C₂H₂ + 2Cl₂ → 2CH₂Cl + 2HCI (b) The UV radiation initially causes the formation of A CI-ions. B CI+ ions. C Cl free radicals. D C₂H, free radicals. (c) Once it has started, the reaction can proceed for a time without UV light because A a chain reaction is occurring. B initiation is occurring. C a substitution reaction is occurring. D termination steps cannot occur without UV light.

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Organic Chemistry - Standalone book

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