Operations Management
13th Edition
ISBN: 9781259667473
Author: William J Stevenson
Publisher: McGraw-Hill Education
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Chapter 10, Problem 2P
a)
Summary Introduction
To determine: The upper and lower control limits.
Introduction:
Control chart:
It is a graph used to analyze the process change over a time period. A control chart has a upper control limit, and lower control which are used plot the time order.
b)
Summary Introduction
To determine: Whether the process is in a controlled state.
Introduction:
Control chart:
It is a graph used to analyze the process change over a time period. A control chart has a upper control limit, and lower control which are used plot the time order.
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An automatic filling machine is used to fill 1-liter bottles of cola. The machine’s output is approximately normal with a mean of 1.0 liter and standard deviation of .01 liter. Output is monitored using means of samples of 25 observations.
Determine upper and lower control limits that will include roughly 97% of the sample means when the process is in control. Using Appendix B, Table A to find the value of Z corresponding to the mean control limits.
An automatic filling machine is used to fill 1-liter bottles of cola. The machine’s output is approximately normal with a mean of 1.0 liter and a standard deviation of .01 liter. Output is monitoredusing means of samples of 25 observations.a. Determine upper and lower control limits that will include roughly 97 percent of the samplemeans when the process is in control.b. Given these sample means: 1.005, 1.001, .998, 1.002, .995, and .999, is the process in control?
An automatic filling machine is used to fill 1-liter bottles of cola. The machine’s output is approximately normal with a mean of 1.0 liter and a standard deviation of .01 liter. Output is monitoredusing means of samples of 25 observations.a. Determine upper and lower control limits that will include roughly 97 percent of the samplemeans when the process is in control.
Chapter 10 Solutions
Operations Management
Ch. 10.2 - A potato chip is a delicate thing Fragile A pound...Ch. 10.2 - A potato chip is a delicate thing Fragile A pound...Ch. 10.5 - It's estimated that more than 7 000 hospital...Ch. 10.5 - It's estimated that more than 7 000 hospital...Ch. 10 - Prob. 1DRQCh. 10 - Prob. 2DRQCh. 10 - Prob. 3DRQCh. 10 - Prob. 4DRQCh. 10 - Prob. 5DRQCh. 10 - Prob. 6DRQ
Ch. 10 - Prob. 7DRQCh. 10 - Prob. 8DRQCh. 10 - Prob. 9DRQCh. 10 - Prob. 10DRQCh. 10 - Prob. 11DRQCh. 10 - Prob. 12DRQCh. 10 - Prob. 13DRQCh. 10 - Prob. 14DRQCh. 10 - Prob. 15DRQCh. 10 - Prob. 16DRQCh. 10 - Prob. 1TSCh. 10 - Prob. 2TSCh. 10 - Prob. 3TSCh. 10 - Prob. 1CTECh. 10 - Prob. 2CTECh. 10 - Prob. 3CTECh. 10 - Prob. 4CTECh. 10 - Prob. 1PCh. 10 - Prob. 2PCh. 10 - Prob. 3PCh. 10 - Prob. 4PCh. 10 - Prob. 5PCh. 10 - Prob. 6PCh. 10 - Prob. 7PCh. 10 - Prob. 8PCh. 10 - Prob. 9PCh. 10 - Prob. 10PCh. 10 - Prob. 11PCh. 10 - Prob. 12PCh. 10 - Prob. 13PCh. 10 - Prob. 14PCh. 10 - Prob. 15PCh. 10 - Prob. 16PCh. 10 - Prob. 17PCh. 10 - A production process consists of a three-step...Ch. 10 - Prob. 19PCh. 10 - Prob. 20PCh. 10 - Prob. 21PCh. 10 - Prob. 22PCh. 10 - Prob. 23PCh. 10 - Prob. 24PCh. 10 - Prob. 25PCh. 10 - Prob. 26PCh. 10 - Prob. 27PCh. 10 - Prob. 28PCh. 10 - Prob. 29PCh. 10 - Prob. 1.1CQCh. 10 - Prob. 2.1CQCh. 10 - Prob. 2.2CQCh. 10 - Prob. 2.3CQCh. 10 - Prob. 2.4CQ
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- Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: a) What is the value of x? = x= 155.56 mm (round your response to two decimal places). b) What is the value of R? R 4.48 mm (round your response to two decimal places). c) What are the UCL; and LCL; using 3-sigma? Day 1 2 3 4 5 Upper Control Limit (UCL) = 156.94 mm (round your response to two decimal places). Lower Control Limit (LCL-) = 154.18 mm (round your response to two decimal places). d) What are the UCLR and LCLR using 3-sigma? Upper Control Limit (UCL) = 7.96 mm (round your response to two decimal places). Mean x (mm) 154.9 153.2 155.6 155.5 158.6 Range R (mm) 4.0 4.8 3.9 5.0 4.7 Lower Control Limit (LCL) = 1.00 mm (round your response to two decimal places). e) If the true diameter mean should be 155 mm and you want…arrow_forward1. The overall average on a process you are attempting to monitor is 55.0 units. The process population standard deviation is 1.84. Sample size is given to be 16. a) Determine the 3-sigma x-chart control limits. Upper Control Limit (UCLx)=56.3856.38 units (round your response to two decimal places). Lower Control Limit (LCLx)=53.6253.62 units (round your response to two decimal places). b) Now determine the 2-sigma x-chart control limits. Upper Control Limit (UCLx)=? units (round your response to two decimal places). 2. Sample Size, n Mean Factor, A2 Upper Range, D4 Lower Range, D3 2 1.880 3.268 0 3 1.023 2.574 0 4 0.729 2.282 0 5 0.577 2.115 0 6 0.483 2.004 0 7 0.419 1.924 0.076 8 0.373 1.864 0.136 9 0.337 1.816 0.184 10 0.308 1.777 0.223 12 0.266 1.716 0.284 Thirty-five samples of size 7 each were taken from a…arrow_forwardFactors for Computing Control Chart Limits (3 sigma) Auto pistons at Wemming Chung's plant in Shanghai are produced in a forging process, and the diameter is a critical factor that must be controlled. From sample sizes of 10 pistons produced each day, the mean and the range of this diameter have been as follows: Day Mean x (mm) Range R (mm) 1 156.9 4.2 2 153.2 4.6 3 153.6 4.1 4 155.5 5.0 5 156.6 4.5 Part 4 c) What are the (UCLx) and (LCLx) using 3-sigma? (UCLx) = mm (round your response to two decimal places). (LCLx) = mmarrow_forward
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