Convert the following to appropriate SI units:
- (a) A length, l = 5 ft.
- (b) A stress, σ = 90 kpsi.
- (c) A pressure, p = 25 psi.
- (d) A section modulus. Z = 12 in3.
- (e) A unit weight, w = 0.208 Ibf/in.
- (f) A deflection. δ = 0.001 89 in.
- (g) A velocity, v = 1 200 ft/min.
- (h) A unit strain. ∈ = 0.002 15 in/in.
- (i) A volume. V = 1830 in3.
(a)
The length in
Answer to Problem 30P
The length in
Explanation of Solution
Write the expression for length.
Here, the length in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the length in
(b)
The stress in
Answer to Problem 30P
The stress in
Explanation of Solution
Write the expression for stress.
Here, the stress in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the stress in
(c)
The pressure in
Answer to Problem 30P
The pressure in
Explanation of Solution
Write the expression for pressure.
Here, the pressure in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, pressure in
(d)
The section modulus in
Answer to Problem 30P
The section modulus in
Explanation of Solution
Write the expression for section modulus.
Here, the section modulus in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the section modulus in
(e)
The unit weight in
Answer to Problem 30P
The unit weight in
Explanation of Solution
Write the expression for unit weight.
Here, the unit weight in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the unit weight in
(f)
The deflection in
Answer to Problem 30P
The deflection in
Explanation of Solution
Write the expression for deflection.
Here, the deflection in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the deflection in
(g)
The velocity in
Answer to Problem 30P
The velocity in
Explanation of Solution
Write the expression for velocity.
Here, the velocity in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the velocity in
(h)
The unit strain in
Answer to Problem 30P
The unit strain in
Explanation of Solution
Write the expression for unit strain.
Here, the unit strain in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the unit strain in
(i)
The volume in
Answer to Problem 30P
The volume in
Explanation of Solution
Write the expression for volume.
Here, the volume in
Write the expression for conversion factor.
Conclusion:
Substitute
Substitute
Thus, the volume in
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Chapter 1 Solutions
Shigley's Mechanical Engineering Design (McGraw-Hill Series in Mechanical Engineering)
- At a temperature of 60°F, a 0.05-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; a = = 12.5 x 10-6/°F] bar with a width of 3.0 in. and a thickness of 0.65 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; a = 9.6 x 10-6/°F] bar with a width of 1.6 in. and a thickness of 0.65 in. The supports at A and C are rigid. Assume h₁=3.0 in., h₂=1.6 in., L₁=32 in., L₂=46 in., and A = 0.05 in. Determine (a) the lowest temperature at which the two bars contact each other. (b) the normal stress in the two bars at a temperature of 265°F. (c) the normal strain in the two bars at 265°F. (d) the change in width of the aluminum bar at a temperature of 265°F. (1) h₂ B L₁ h₁ L2arrow_forwardA 200 kN В 30 kN D Soil Surface 1 mm settlement An axially loaded column made up of different segments AB, BC, and CD has a fixed support at A and a footing at D. The footing at D is rigid but is supported by soil that settles (moves downward) a maximum of 1mm before offering any resistance. Determine the stresses in segments AB, BC, and CD. Note, neglect the weights of the members.arrow_forwardAt a temperature of 60°F, a 0.03-in. gap exists between the ends of the two bars shown. Bar (1) is an aluminum alloy [E = 10,000 ksi; v = 0.32; α=α=12.5 x 10-6/°F] bar with a width of 3.0 in. and a thickness of 0.70 in. Bar (2) is a stainless steel [E = 28,000 ksi; v = 0.12; α=α=9.6 x 10-6/°F] bar with a width of 1.9 in. and a thickness of 0.70 in. The supports at A and C are rigid. Assume h1=3.0 in., h2=1.9 in., L1=27 in., L2=47 in., and Δ=Δ= 0.03 in. Determine(a) the lowest temperature at which the two bars contact each other.(b) the normal stress in the two bars at a temperature of 260°F.(c) the normal strain in the two bars at 260°F.(d) the change in width of the aluminum bar at a temperature of 260°F.arrow_forward
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