A tensile test was performed on a metal specimen having a circular cross section with a diameter of
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- A brass alloy rod having a cross sectional area of 0.24 in.2and a modulus of 16 * 106 psi is subjected to a tensile load. Plastic deformation was observed to begin at a load of 8,944 lb.a. Determine the maximum stress that can be applied without plastic deformation.b. If the maximum length to which a specimen may be stretched without causing plastic deformation is 3.28 in., what is the original specimen length?arrow_forwardA tension test performed on a metal specimen to fracture produced the stress- strain relationship shown in Figure P1.14. Graphically determine the following (show units and all work): a. Modulus of elasticity within the linear portion. b. Yield stress at an offset strain of 0.002 in./in. c. Yield stress at an extension strain of 0.005 in/in. d. Secant modulus at a stress of 525MPA.arrow_forward1.5-7 The data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2 in.² in area and a gage length (the length over which the elongation is measured) of 2.000 inches. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. Load (kips) 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 5.5 50 6.0 6.5 Elongation × 10³ (in.) 0 0.160 0.352 0.706 1.012 1.434 1.712 1.986 2.286 2.612 2.938 3.274 3.632 3.976 Load (kips) 7.0 7.5 8.0 8.5 9.0 9.5 10.0 10.5 11.0 11.5 12.0 12.5 13 Elongation × 10³ (in.) 4.386 4.640 4.988 5.432 5.862 6.362 7.304 8.072 9.044 11.310 14.120 20.044 29.106arrow_forward
- A tension test performed on a metal specimen to fracture produced the stress– strain relationship shown in Figure P1.14. Graphically determine the following (show units and all work): a. Modulus of elasticity within the linear portion. b. Yield stress at an offset strain of 0.002 m/m. c. Yield stress at an extension strain of 0.005 m/m. d. Secant modulus at a stress of 525 MPa. e. Tangent modulus at a stress of 525 MPa.arrow_forwardA steel alloy specimen having a rectangular cross section of dimensions 19.1 mm x 3.1 mm (0.7520 in. × 0.1220 in.) has the stress-strain behavior shown in the Animated Figure 6.22b. If this specimen is subjected to a tensile force of 98290 N (22100 Ib;) then (a) Determine the amount of elastic strain induced. (b) Determine the amount of plastic strain induced. (c) If its original length is 610 mm, what will be its final length after this force is applied and then released? The elastic modulus for steel is 207 GPa. (a) i (b) i (c) i mmarrow_forwardThe strain rosette shown in the figure was used to obtain the following normal strain data on a piece of aluminum. The plate has a modulus of elasticity of 10,000 ksi and a Poisson’s Ratio of 0.35. The strain readings were εa = 600 με, εb = 900 με, and εc = 120 με. Note: 1 με = 1 X 10-6 in/in. a) Calculate the normal strain in the x- and y- directions (εx and εy) and the shear strain (γxy) using a system of equations. b) Calculate the normal stress σx in ksi. Clearly indicate Tension (T) or Compression (C). Note: even though the normal stress in the z-direction is zero, but the normal strain in the z-direction is NOT zero. [Ans. to Check σx = 7.18 ksi (T)] c) Calculate the normal stress σy in ksi. Clearly indicate Tension (T) or Compression (C). d) Calculate the shear stress τxy in ksi.arrow_forward
- Consider a cylindrical specimen of a steel alloy (Please see the figure) 0.33 in. in diameter and 3.15 inches long that is pulled in tension. given:-Elongation is 0.018 in-Tensile stress = 200 ksi -Tensile strain = 6.83*10^-3 -Ultimate stress = 281.82 ksi -Ultimate strain = 0.05solve: Fracture point (stress and strain values)arrow_forwardThe data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross-section of 0.2 in.? in area and a gage length (the length over which the elongation is measured) of 2.000 inches. a. Generate a table of stress and strain values. b. Plot these values and draw a best-fit line to obtain a stress-strain curve. c. Determine the modulus of elasticity from the slope of the linear portion of the curve. d. Estimate the value of the proportional limit. e. Use the 0.2% offset method to determine the yield stress.arrow_forward1.5-7 The data shown in the table were obtained from a tensile test of a metal specimen with a rectangular cross section of 0.2 in.² in area and a gage length (the length over which the elongation is measured) of 2.000 inches. d. Estimate the value of the proportional limit. e. Use the 0.2% offset method to determine the yield stress. Load (kips) 0 0.5 1.0 1.5 2.0 2.5 3.0 3.5 4.0 4.5 5.0 ܩܙ ܘ 5.5 6.0 6.5 Elongation × 10³ (in.) 0 0.160 0.352 0.706 1.012 1.434 1.712 1.986 2.286 2.612 2.938 3.274 3.632 3.976 Load (kips) 7.0 7.5 8.0 8.5 9.0 9.5 10.0 10.5 11.0 11.5 12.0 12.5 13 Elongation × 10³ (in.) 4.386 4.640 4.988 5.432 5.862 6.362 7.304 8.072 9.044 11.310 14.120 20.044 29.106arrow_forward
- A tension test performed on a metal specimen to fracture produced the stress-strain relationship shown in Figure. Graphically determine the following (show units and all work):a. Modulus of elasticity within the linear portion.b. Yield stress at an offset strain of 0.002 in./in.c. Yield stress at an extension strain of 0.005 in/in.d. Secant modulus at a stress of 62 ksi.e. Tangent modulus at a stress of 65 ksi.arrow_forwardStress-strain plot for a metal is given below. Determine the following: a) Modulus of elasticity. b) Yield strength by 0.2% off-set method. c) Tensile and fracture strengths. d) Maximum load that can be sustained by a cylindrical specimen having an original diameter of 15.3 mm. e) If a specimen having an original length of 320 mm and elongation is measured as 2.56 mm, determine the applied stress. 450 400 350 300 250 200 150 100 50 0.002 0.004 0.006 0.008 0.01 0.012 0.014 0.016 Strain Stress (MPa)arrow_forward1.16 The stress-strain relationship shown in Figure P1.16 was obtained during the tensile test of an aluminum alloy specimen. 60,000 H Stress, psi 40,000 20,000 0 Figure P1.16 0.002 0.004 0.006 0.008 Strain, in./in. Determine the following: a. Young's modulus within the linear portion. b. Tangent modulus at a stress of 45,000 psi c. Yield stress using an offset of 0.002 strain d. If the yield stress in part c is considered failure stress, what is the maximum working stress to be applied to this material if a factor of safety of 1.5 is used? 4arrow_forward
- Steel Design (Activate Learning with these NEW ti...Civil EngineeringISBN:9781337094740Author:Segui, William T.Publisher:Cengage Learning