Concept explainers
Plot
(a)
To plot: The graph of
Answer to Problem 1.30P
The graph of
Explanation of Solution
Given:
Reverse saturation current
Diode Voltage range,
Concept Used:
Calculation:
For
For
For
For
For
For
For
For
Figure 1
(b)
To plot: The graph of
Answer to Problem 1.30P
The graph of
Explanation of Solution
Given:
Reverse saturation current
Concept Used:
Formulae;
Calculation:
For
For
For
For
For
For
For
For
Figure 2
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Chapter 1 Solutions
Microelectronics: Circuit Analysis and Design
- Discussion Use the obtained results to: Discuss in details, how the obtained results may prove the validity of Thevenin's and Norton's Theorems. 100N 150 2 2202 3302 20 V 8202 4602 Readings from the original circuit Rah and Readings from the equivalent circuits Vth IN Thevenin Norton V1502 I1502 RN V15052 I1502 V15052 I1502 3V 20mA 9.7V| 29.25mA 330.6Q 3V 20mA 3V 20mAarrow_forwardDiscussion Use the obtained results to: Discuss in details, how the obtained results may prove the validity of Thevenin's and Norton's Theorems. 100N 150 2 220º 330n 20V 8202 4602 Readings from the original circuit Rah Readings from the equivalent circuits Vth IN and Thevenin Norton V1502 I1502 RN V1502 I15052 V1502 I15052 3V 20mA 9.7V| 29.25mA| 330.6Q 3V 20mA 3V 20mAarrow_forwardProb. 2.. Convolve the following two functions y(n) = x(n) * h(n) using the graphical and analytical methods. h(n7) 0 1 x(n7) 2 3 4 5 -1 -1 9 10 fettlagret -1 10 n "arrow_forward
- The 3-pt DFT of the sequence is defined as X (k) for k = 0, 1, and 2 If X (1) = 1 + jv3 and the energy of the sequence is 3 sq unit Also, the DC value of the sequence is greater than zero. Determine the elements of the sequence defined as follows: x [n] = ao + a18 [n – 1] + azd [n - 2] ao = a = a2 =arrow_forwardix V₁(t) = ix(t) ≤R₁ Problem is related to Problem x.xx in the text (for ECE331). R₁ = 82, C₁ = 0.45µF and v₁(t) = = 5cos(210³ t) V C₁ Calculate the energy stored at -0.12 ms: A help (formulas) μJ help (numbers)arrow_forwarde The Constraint equation for VA is 0.003 v 20 V + 100 (2 Va250 2 Select one: Oa. VA-Va O b. None of these OC. O d. VA-V3 Oe. VA-V4 200 mA VA V3/500 Ref 0.4 Va + "Δ Σ 500 Ω 200 Ωarrow_forward
- Find v(0) and dv(0)/dt for the following circuit. 2u(-t) A ... 0.04 F 1H + v 4Ω 2Ω (+ – 50u(t) V (0) = 50 V dv(0)/dt = 38 V/s (0) = -12 V B dv(0)/dt = 0 V/s (0) = -12 V dv(0)/dt = 38 V/s v(0) = 50 V dv(0)/dt = 0 V/s %3Darrow_forwardFind the characteristic roots, s1 and s2, of the circuit below. 2u(-1) А ... 0.04 F 1 H ll H + v - 4Ω 2Ω (+ - 50u(t) V S1 = -3 + j5 A S2 = -3 - j5 S1 = 1 S2 = -7 S1 = -7 S2 = 1 S1 = -3 + j4 D S2 = -3 - j4 B.arrow_forwardfor the circuit below what is (Vp). if (Vp)in is 120V, R = 10 k2 and c = 40 uF and f= 60 hz? R (Vp)o (a) (Vp) i R www C (Vp). (b) Ⓒ Cengage 2017arrow_forward
- Determine the range of K for stability of the following systems [7] C(s) (a) R(s) k s4 + 3s3 + 3s² + 2s + karrow_forward3. Find the vo(t) for the circuit shown in Figure assuming that all initial conditions are zero. R1 ww 2092 Solution 5Vu(t) V1 2 L1 m 5H 3 R2 E 1092 0 C1 1F vo(t)arrow_forwardThe voltage V of the following circuit is j20 Ω γγγ 120/15° V Select one: O a. O 99242° 40 Ω www b. -56.332-72° Ο c. 107.222154° Ο d. 124.082-154° e. 77.542-102° 6/30° A V -j30 Ω 50 Ωarrow_forward
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