Volume of dye solution added (mL) 9.80 mL Concentration of bleach solution used (M) 0.090 M Volume of bleach solution added (mL) 0,20 mL. Total Volume of solution (mL) 10.0 mL O5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 ABS Ln Abs = -4.860e-2 t + 1.35e-1 0.0 INABS -0.2 -0.4 1/ABS -0.6 -0.8 -1.0 -1.2 -1.4 Time (s) -1.6 b) From the data above, what are the initial molar concentrations of [dye] and [bleach] for your experiment? (NOTE: The concentration of the stock yellow dye solution is 3.40x10 M) [dye)o (M) [bleach]o (M) In Absorbance

Volume of dye solution added (mL) 9.80 mL Concentration of bleach solution used (M) 0.090 M Volume of bleach solution added (mL) 0,20 mL. Total Volume of solution (mL) 10.0 mL O5 10 15 20 25 30 35 40 45 50 55 60 65 70 75 ABS Ln Abs = -4.860e-2 t + 1.35e-1 0.0 INABS -0.2 -0.4 1/ABS -0.6 -0.8 -1.0 -1.2 -1.4 Time (s) -1.6 b) From the data above, what are the initial molar concentrations of [dye] and [bleach] for your experiment? (NOTE: The concentration of the stock yellow dye solution is 3.40x10 M) [dye)o (M) [bleach]o (M) In Absorbance

Fundamentals Of Analytical Chemistry

9th Edition

ISBN:9781285640686

Author:Skoog

Publisher:Skoog

Chapter7: Statistical Data Treatment And Evaluation

Section: Chapter Questions

Problem 7.21QAP

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C. Electrolytes in Body Fluids 1. Type of IV Solution 5% Isolute P (mEa/L) Plasnalyte (mEg/L) Lactated Ringer's (mEg/L) Nal+ = 130 Klt = 4 Ca2+ = 3 Nal+ = 25 K+ = 20 Nal+ = 140 Kl+ = 5 2. Cations %3D %3D Mg+ = 3 Mg2+ = 3 CI- = 22 HPO- =3 Acl- = 23 CI- = 98 Glu'-= 23 Acl- = 27 3. Anions CI'- = 109 %3D HPO = 28 %3D %3D 4. Total Charge of Cations (+) 137 137 5. Total Charge of Anions (-) 6. Sum of the Charges Copyright 2014 Pearson Education, Inc.
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