A certain computer system is consisting of 32 GB main memory and 32 MB cache memory. The cache uses 8 bytes word. a. Using cache direct mapping, determine the size of the tag, line and word. b. Using cache associative mapping, show the main memory address format. c. The computer uses a 2-way set associative mapping cache structure. Show the main memory address format.

Q: Suppose a computer using direct mapped cache has 2^32 bytes of byte-addressable main memory and a…

A: A)  Total number of blocks in main memory = main memory size /block size = 232 / 26 = 226  = 64M…

Q: A certain computer system is consisting of 32 GB main memory and 32 MB cache memory. The cache uses…

A:

Q: Function NSU-1 For a system, RAM-64KB, Block size-4 bytes, Cache sine- 128 bytes, Direct mapped…

A: RAM -64 KB Block size -4 byte Cache size 128 byte Hit ratio while using direct mapped cache: To…

Q: For a system, RAM - 64KB, Block size - 4 bytes, Cache size - 128 bytes, Direct mapped cache.…

A: Given: RAM size = 64 KB Block size = 4 bytes Cache size = 128 bytes

Q: Show work and type answer please. Suppose a computer using fully associate cache has 2G Bytes of…

A: In this question, we are given a fully associative cache with main memory and block size. We are…

Q: For a system, RAM - 64KB, Block size - 4 bytes, Cache size - 128 bytes, Direct mapped cache.…

A: Step 1 Firstly, No.of blocks are replaced in cache memory assuming the cache is empty at the…

Q: Assume your 32-bit computer (memory address 32-bits) has 16-KB (only L1-data) direct mapped cache.…

A: Explanation: Given cache block size is 16 bytes, so block or word offset is 4 bits. Fully…

Q: Consider the cache memory which is 30 times faster than main memory and it can be uses 90% of the…

A: Introduction  Given cache is 30 times faster than main memory. We have asked to find the speed up…

Q: For a system, RAM - 64KB, Block size - 4 bytes, Cache size - 128 bytes, Direct mapped cache.…

A: RAM-64 KB Block size-4 byte Cache size-128 byte Hit ratio: To calculate hit ratio, divide the number…

Q: a) Explain what data is written to cache memory, on basis of what two factors does the cache memory…

A: As per guidlines we are suppose to answer first question :  Answer: a. Cache Memory is a unique…

Q: For a system, RAM - 64KB, Block size - 4 bytes, Cache size - 128 bytes, Direct mapped cache.…

A: Firstly, No.of blocks are replaced in cache memory assuming the cache is empty at the beginning,…

Q: Suppose a computer using fully associative cache has 216 bytes of byte-addressable main memory and a…

A: Fully-associative cache: A fully associative cache is more flexible mapping than direct mapping. In…

Q: Assume that a system's memory has 128M bytes. Blocks are 64 bytes in length, and the cache consists…

A: The memory has 128M words = 27M = 27.220 = 27+20 = 227words. Hence it needs 27 bits for address…

Q: Assume that a system's memory has 128M bytes. Blocks are 64 bytes in length, and the cache consists…

A: The answer is

Q: Assume that a system’s memory has 128M bytes. Blocks are 64 bytes in length, and the cache consists…

A: The memory has 128 words. 128 = 227 words. Therefore, 27 bits are needed for address space.   A…

Q: Assume that a system's memory has 128M bytes. Blocks are 64 bytes in length, and the cache consists…

A: The ANswer is in Below steps

Q: A block-set associative cache memory consists of 128 blocks divided into four block sets. The main…

A: To find no. of bits required for addressing the main memory, to represent the TAG, SET AND WORD…

Q: A digital computer has a memory unit of 64K X 16 and a cache memory of 1K words. The cache uses…

A: Given : A digital computer has a memory unit of 64K X 16 and a cachememory of 1K words. The cache…

Q: Suppose a computer using set associative cache has 221 words of main memory and a cache of 64…

A: I have answered this question in step 2.

Q: Suppose a computer using set associative cache has 221 words of main memory and a cache of 64…

A: Given Associative cache 221 words of main memory cache 64 blocks(each cache block contains 4 words)

Q: Suppose a computer using fully associative cache has 224 bytes of byte-addressable main memory and a…

A: Offset bits = log (2^6) = 6 bits.

Q: For a system, RAM - 64KB, Block size - 4 bytes, Cache size - 128 bytes, Direct mapped cache.…

A: Given: RAM size = 64 KB Block size = 4 bytes Cache size = 128 bytes

Q: Design and draw for each of the followings A- The cache organization B- The cache directory SET…

A: This type of mapping has an improved and  enhanced form of direct mapping which helps us to remove…

Q: Question 1 A memory cache using a 41-bits address with 9 bits for index and 10 bits for offset. How…

A: Answer: This question based on memory management so we have answered question in next steps.

Q: How would you compute the number of tag bits in a direct mapped cache with byte addressable memory…

A: Introduction: The fastest memory, other than the register from which the CPU fetches data and…

Q: Please do a,b,c,d, and e  Consider a machine with a byte addressable main memory of Bytes and block…

A: Answer in step2

Q: Consider a computer with a cache memory of 1024 blocks and a total size of 512K bits. This computer…

A: GIVEN:

Q: Design the memory mapping between the Cache memory of 2 MB to the main memory of 4 GB using 4 way…

A: Cache memory: It is a memory which optimized the gap between RAM and CPU means it stores the content…

Q: Q10) A block-set associative cache memory consists of 128 blocks divided into four block sets. The…

A: ANSWER:-

Q: Assume that a system’s memory has 128M bytes. Blocks are64 bytes in length, and the cache consists…

A: Ans:)  Given, Memory = 128M bytes, Block size = 64 bytes, cache size = 32K blocks

Q: If memory size 16 KB. If cache size = 512 B. If block size = 8 B. Show address fields for the cache…

A: Memory size = 16KB So memory size in bits = 14 bits Block size=8 B So block offset bit=3 bit.

Q: If memory read cycle takes 100 ns and a cache read cycle takes 20 ns, then for four continuous…

A: Memory Read cycle : 100nsCache Read cycle : 20ns Four continuous reference is done - one reference…

Q: Problem 2. Convert the following virtual addresses to physical addresses, and indicate whether the…

A: Answer: Our instruction is answer the first three part from the first part and . I have given…

Q: Design the memory mapping between the Cache memory of 128MB to the main memory of 4 GB using 16 way…

A: Dear Student, As size of main memory is 4GB = 235 in bits. So, Bits required for memory address =…

Q: Suppose a computer using direct-mapped cache has 2 bytes of byte-addressable main memory and a cache…

A: Given: The computer is using direct-mapped cache.   Size of the main memory = 220 bytes  Size of the…

Q: For a system, RAM = 64KB, Block size = 4 bytes, Cache size = 128 bytes, Direct mapped cache.…

A: As the following information is available, Size of RAM= 64 KB Size of the block = 4 bytes Size of…

Q: Design the memory mapping between the Cache memory of 64MB to the main memory of 4 GB using 8 way…

A: For a 8-Way associative cache allows placement in any block of a set with 8 elements• 8 is the…

Q: For a system, assume, RAM- 64KB, block size - 4 bytes, cache size - 64 bytes, 2-way set associative…

A: Given : RAM= 64KB, block size = 4 bytes, cache size = 64 bytes, and the mapping is 2-way set…

Q: microprocessor with 32-bit address bus has an on-chip 16-KByte four-way set-associative cache…

A: It is defined as a controlling unit of a micro-computer, fabricated on a small chip capable of…

Q: Suppose that a cache is 20 times faster than main memory and cache memory can be used 80% of the…

A: Given data, The cache in the system is 20 times faster than main memory. Cache memory can be used…

Q: C1. Consider a main memory with size 4GB with cache size 16 KB and memory block is 8 bytes. Assume…

A: We are given main memory size as 4GB and cache as 16KB. Memory block is 8B. Each word is 1 byte .  I…

Q: For a processor with a 32-bit address bus and a 64-bit data bus, 32 bytes of "line size" and a total…

A: A)  For fully associative cache,  Index bits is 0 So block offset bits = log (block size) = log 32B…

Q: Suppose 93% of the memory accesses found in cache then what is average time to access a byte if…

A: Memory: The computer contains memory space, similar to humans where humans contain memory where they…

Q: "Hadley cache" and "unified cache" need to be described in terms of what they mean.

A: Some applications spend the majority of their time processing large amounts of data in a tiny…

Q: How a physically addressed cache might beintegrated with virtual memory

A: Here have to determine about physically addressed cache might be integrated with virtual memory.

Q: Data are transferred between main memory and the cache in blocks of 8 bytes each Main memory…

A: Block size = 8B =>  Block offset = log 8 = 3 bit Memory size = 256MB => memory bits = 28 bits…

Q: A CPU has 32-bit memory address and a 256 KB cache memory. The cache is organized as a 4-way set…

A: Given data is  cpu has 32 bit memory address and 256 cache memory  4 way set associative cache with…

Q: Suppose a computer using direct-mapped cache has 232 bytes of byte-addressable main memory and a…

A: Given: The computer is using direct mapped cache. Size of main memory = 232 Size of block = 1024…

Q: Assume you have a 8-way set associative cache having 16K lines each having capacity of 8 Bytes. A…

A: A.  Block size = 8 bytes So # of data bytes brought= size of block = 8

Q: If T1 is L1 cache access time, T2 is L2 cache access time Tm is memory access time, h1 is hit rate…

A: Derivation: In cache memory, the average access time for single level cache organization is given…