Design the memory mapping between the Cache memory of 128MB to the main memory of 4 GB using 16 way set associative method where the block or page or frame size is of 8KB. Consider each memory location is byte addressable. Write the number of bits required for memory address, tag address, block address and block location. In above memory mapping show the final Cache memory for block number 78 in the main memory which contains tag, block and block location fields.

Q: Design the memory mapping between the Cache memory of 2 MB to the main memory of 4 GB using 4 way…

A: Cache memory: It is a memory which optimized the gap between RAM and CPU means it stores the content…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Direct mapping in cache is a method used to map each memory block of the main memory to a particular…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Given: Goal:We have to check in which cache block does the address 253 value maps to.

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Given: Goal: We have to check in which bin of cache the word address 253 mapped to in the given…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Given: Goal: Find out which cache block number does the memory address 253 will map.

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: (a)Number of blocks cache has = 16 Block size = 2 words = 4 bytes Block address = 88/4 = 22 Tag =…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Given: Goal: We have to find out memory address 253 value maps to which cache block number or cache…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Given: Goal: We have to check that in which cache block address 253 values maps to.

Q: A cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory…

A: A 64-bit word means 8 byte.Line size: 8 words in a line, means 8 x 8 bytes = 64 bytes in a line = 26…

Q: We are given a list of 64-bit memory address references, given as word addresses. Ox03, Oxb4, Ox2b,…

A:

Q: Assume a memory subsystem with a cache of 8 blocks and a main memory of 64 blocks, where each block…

A: Given: Goal: We have to solve the above parts/questions given.

Q: Question 1 Consider the size of main memory as 32 Bytes and the size of cache memory as 8 Bytes.…

A: NOTE: Since there are multiple Bits and it is not mentioned which  bit to answer so i would prefer…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Given: Goal: Find the cache block number to which memory address 253 maps to.

Q: Design the memory mapping between the Cache memory of 512 MB to the main memory of 4 GB using 4 way…

A: Given question has asked to design memory mapping between Cache memory of 512 MB to the main memory…

Q: Design the memory mapping between the Cache memory of 512 MB to the main memory of 4 GB using 4 way…

A: Cache memory: It is a memory which optimized the gap between RAM and CPU means it stores the content…

Q: Design the memory mapping between the Cache memory of 64MB to the main memory of 4 GB using 8 way…

A: For a 8-Way associative cache allows placement in any block of a set with 8 elements• 8 is the…

Q: Consider a main memory with size 512MB with cache size 64KB  and memory block is 4 bytes. Assume…

A: We are given main memory as 512 MB with 64KB cache. And block offset is 4 bytes. We are going to…

Q: For a system, assume, RAM- 64KB, block size - 4 bytes, cache size - 64 bytes, 2-way set associative…

A: Given : RAM= 64KB, block size = 4 bytes, cache size = 64 bytes, and the mapping is 2-way set…

Q: For a system, RAM - 64KB, Block size - 4 bytes, Cache size - 128 bytes, Direct mapped cache.…

A: Solution:

Q: Consider a cache with 32KIB data, 16-word blocks, and 24-bit addresses, answer the following…

A: cache size C=32KiB(215 Bytes) block size=16 words(25 Bytes) size of main memory =224 number of lines…

Q: Consider a main memory with size 128 Mbytes with cache size 64 Kbytes and memory block is 4 bytes.…

A: In this question, we are given main memory size, cache size, block size. We have to split the…

Q: For a direct-mapped cache design with a 64-bit address, the following bits of the address are used…

A:

Q: For a system, assume, RAM= 64KB, block size = 4 bytes, cache size = 64 bytes, 2-way set associative…

A: Given : RAM= 64KB, block size = 4 bytes, cache size = 64 bytes, and the mapping is 2-way set…

Q: Consider a two level cache system. For 100 memory references, 20 misses in the first lyel cache and…

A: Introduction : given ,  2 level cache system. Total memory reference = 100. 20 miss in level 1. 6…

Q: For a direct-mapped cache design with a 64-bit address, the following bits of the address are used…

A: 5.1) We know that the block size can be determined by looking into the offset bits. In this question…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Below is the answer to the above question. I hope this will be helpful for you...

Q: Assume a cache of 1 MB organized as 32 bytes each line. The main memory is 256 MB. a. Determine the…

A: Cache is =1MB; and main memory=256MB;  and the line size is =32bytes The number of…

Q: Assume a cache of 1 MB organized as 32 bytes each line. The main memory is 256 MB. a. Determine the…

A: (a) number of blocks = 2^20 / 32 = 2^15 =32*1024=32768so there are 32768 blocks in main memory . (b)…

Q: For a direct-mapped cache design with 64-bit addresses, the following bits of the address are used…

A: As per our guidelines we are supposed to answer first 3 parts of the question. please re upload 4th…

Q: Part(c) : Assume a hypothetical system with eight 32-bit words cache and small Main memory of 1 KB…

A: the solution of part c is given below :

Q: Assume a cache of 1 MB organized as 32 bytes each line. The main memory is 256 MB. a. Determine the…

A: Actually, cache memory is a fast access memory.

Q: For a processor with a 32-bit address bus and a 64-bit data bus, 32 bytes of "line size" and a total…

A: Total # of cache blocks = cache  size/ cache blocks size = 2MB/32 B = 2^21/2^5 = 2^16 Block offset =…

Q: 4. For a system, assume, RAM- 64KB, block size -4 bytes, cache size - 64 bytes, 2-way set…

A: Given : RAM= 64KB, block size = 4 bytes, cache size = 64 bytes, and the mapping is 2-way set…

Q: For a system, RAM = 64KB, Block size = 4 bytes, Cache size = 128 bytes, Direct mapped cache.…

A: As the following information is available, Size of RAM= 64 KB Size of the block = 4 bytes Size of…

Q: Consider a system with 4-way set associative cache of 256 KB. The cache line size is 8 words (32…

A: Introductions : Given , 4- way set associative cachecache size = 256 KB Block size = 8 word we have…

Q: Consider a single-level cache with an access time of 2.5 ns, a line size of 64 bytes, and a hit…

A: Introduction :Given , Single level cache cache access time = 2.5 ns line size = 64 Byte Hit ratio =…

Q: Content of cach addressable location is 1 byte; block size of 16 bytes; and cache size of 64 Kbytes.…

A: Memory: It is provided that. Main memory address F0010 Calculation of Word offset, Cache line/Slot,…

Q: . Which has the lower average memory access time for both split and unified cache? Consider the…

A: Actually, cache is a fast access memory. It measured in terms of  quality called as hit ratio.

Q: Please explain this 1,2, and 3 Consider following cache elements Cache can hold 64 kB Data are…

A: GIVEN: Please explain this 1,2, and 3 Consider following cache elements Cache can hold 64 kB Data…

Q: Given: A MIPS computer system with 1 GB of main memory. It has a 4K-Byte direct-mapped cache with a…

A: Given: *) computer system with 1 GB of main memory  *) 4K-Byte direct-mapped cache . *) block size…

Q: Consider an L1 cache with an access time of 1 ns and a hit ratio of Suppose that we can change the…

A: Ans: i) Given, access time =1 ns Hit ratio =0.95, new access time=1.5ns, new hit ratio=0.97 It…

Q: Consider a Direct Mapped cache with 32-bit memory address reference word addressable. Assume a 2…

A: Introduction: The correct answer is option a. HIT Below is the Explanation

Q: Consider a small 2-way set associative cache memory, consisting of 4 blocks. For choosing the block…

A: Introduction  Given,  2 way set associative cache , block are 4 ,LRU scheme is being used.block…

Q: Assume a cache of 64 Kbytes organized as 4 K lines of 8 bytes each. The main memory is 32 MB…

A: Solution:

Q: Assume a cache of 64 Kbytes organized as 4 K lines of 8 bytes each. The main memory is 32 MB…

A: First some notes : As already mentioned, each cache block consists of 4 (= 2^2) words. Thus, lowest…

Q: Problem 2. Convert the following virtual addresses to physical addresses, and indicate whether the…

A: Answer: Our instruction is answer the first three part from the first part and . I have given…

Q: Consider a computer with the following characteristics: total of 1Mbyte of main memory; Content of…

A: Tag The tags are defined as providing security for the computer system. and these tags help to…

Q: Consider a byte-addressable computer with 32-bit addresses, a cache capable of storing a total of…

A: Answer to the above question is in step2.

Q: 4. Assume a cache of 32 Kbytes organized as 4 K lines of 8 bytes each. The main memory is 64 MB…

A: Solution: Given Cache_Size = 32KBNo_of_Lines = 4K1 Line Size = Block_Size = 8B Memory_Size =…

Q: When considering a direct mapped cache with memory that is byte addressable, how would you calculate…

A: Cache Memory: A cache memory is the quickest memory other than the register from which the CPU…