Assume that a system's memory has 128M bytes. Blocks are 64 bytes in length, and the cache consists of 32K blocks. Show th
Q: You are given Byte-addressable Main Memory (MM) size 8GB, Block size 8KB, Number of Tag bits 10.…
A: Here in this question have given Main memory size = 8GB. Block size = 8 KB. Tag bit = 10 Find =…
Q: Why SRAM is preferred over DRAM for constructing Cache Memory. Justify your answer by mentioning at…
A: The architecture diagram of SRAM is shown in the figure below.
Q: A word-addressable RAM unit has 12 address bits. How many bytes is the RAM unit able to store? Note:…
A: Input Data : Bits used for the RAM = 10 bits Formula Used : RAM Storage in Bytes = 2Bits used…
Q: A word-addressable RAM unit has 16 address bits. How many bytes is the RAM unit able to store? Note:…
A: Input Data : Bits used for the RAM = 10 bits Formula Used : RAM Storage in Bytes = 2Bits used…
Q: A block-set associative cache memory consists of 128 blocks divided into four block sets. The main…
A: To find no. of bits required for addressing the main memory, to represent the TAG, SET AND WORD…
Q: A 4-way set associative cache memory consists of 128 blocks. The main memory consist of 32768 memory…
A: Given 4 way set associative . cache memory 128 bits main memory 32768 blocks each block has 512…
Q: A Processor has a 2-Way Set-associative cache size of 8 MiB, and uses blocks of 64 bytes. It also…
A: Here in this question we have given Cache size =8MiB Block size =64B K way =2. Find - bit used for…
Q: Consider a computer with 4 levels of memory. Calculate the average memory access time, given the…
A: Given that the computer contains 4 levels of memory. That are: Cache 1 Cache 2 RAM HDD If the data…
Q: DMA and cache memory are contrasted.
A: Introduction: DMA is an abbreviation for Direct Memory Access. It is a technology in which I/O…
Q: A computer system has a memory access time of 120 ns. The hit rate is 96% and memory and cache…
A: Given:- Memory Access time(m) = 120 ns. Hit rate(x) = 96%=0.96 EMAT (Effective Memory Access time)…
Q: DMA and cache memory are compared and contrasted.
A: Introduction: DMA is a physical mechanism that allows data to be transferred to and from memory…
Q: Q2: a cache memory consists of 512 blocks, and if the last word in the block is 111111. I the last…
A: Considering the above scenario, Assume that Block size of main memory is 1KB Number of words in…
Q: iss rate of 11.6% and the D-Cache has a miss rate of 16.1%. The miss penalty to L2 cache is 20…
A: consider a computer system with 2 levels of caches L1 and L2.L1 Cache has I cache and a D-cache. The…
Q: A memory system consists of a cache and a main memory. It takes 25ns to access the cache, and 100ns…
A: Answer the above question are as follows
Q: If the RAM has a two byte data word and address bits are grouped for direct mapping with a cache…
A: The memory bits are organized as Tag(14) index(9) offset(5)
Q: If the RAM has a two byte data word and address bits are grouped for direct mapping with a cache…
A: As You Ask Final Answer Number of bits in physical address = 28bits Size of Main Memory = 2 ^ Number…
Q: HOME WORK#2: If memory size = 16 KB. If cache size = 512 B. If block size = 8 B. Show address fields…
A: Here in this question we have given Main memory size =16KB Cache size = 512 B Blocks size = 8B…
Q: 11) Difference between the Cache and Main Memory 12) Virtual Memory 13) Write-policy in memories 14)…
A: 11)main memory is otherwise called Random Access Memory. It is a memory unit that straightforwardly…
Q: Suppose a DRAM memory has 4 K rows in its array of bit cells, its refreshing period is 64 ms and 4…
A: Introduction
Q: 3) Assume a 232 byte memory system a) What are the lowest and highest addresses if memory is byte…
A: Given: 232 byte memory system, we have find the solution for the following What are the lowest and…
Q: State the differences among direct, associative and set associative mapping in terms of performance…
A: 1. Differences among direct, associative and set associative mapping in terms of performance and…
Q: Q10) A block-set associative cache memory consists of 128 blocks divided into four block sets. The…
A: ANSWER:-
Q: A cache memory needs an access time of 30 ns and main memory 150 ns, what is the average access time…
A: Here hit rate = 0.80 = H Miss rate = 0.20 = (1- H) Cache access time = 30 ns = C Memory Access…
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A: Full jackknife computational complexity: The jackknife resampling method provides more accurate…
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A: Cache memory is a smaller size auxiliary memory, located closer to processor which is used to…
Q: A certain computer system is consisting of 32 GB main memory and 32 MB cache memory. The cache uses…
A: Given: A certain computer system is consisting of 32 GB main memory and 32 MB cachememory. The cache…
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A: In 32 kB memory space is equally distributed in EPROM and RAM. so we need 15 address line to be…
Q: Direct Mapping Cache Problem. Given a Windows XP machine (32-bit architecture) that is byte…
A: Cache memory is an intermediatory memory accessed by the CPU(Central Processing Unit) for fast…
Q: Consider a computer with byte-addressable main memory of size 8 GB and page size of 1 KB. Assume a…
A: Byte addressable memory upholds getting to information in units that are smaller than the transport.…
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A: The time required to transfer from main memory to L2 cache (access time of L2): 20 nanoseconds The…
Q: A CPU has 32-bit memory address and a 256 KB cache memory. The cache is organized as a 4-way set…
A: Given data is cpu has 32 bit memory address and 256 cache memory 4 way set associative cache with…
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A: First let's do a brief introduction about the cache memory and magnetic disk memory a little bit.…
Q: Vhat is the Average Access Time for a machine with the Cache rate of 80% and cache ccess time of 5ns…
A: The answer is...
Q: Q12/Assume that the microprocessor can directly address 1M with a and 8 data pins, The maximum RAM…
A: I have answered this question in step 2.
Q: H/W Consider the sequence of events that occur during a memory write bus cycle.
A: Consider the sequence of events that occur during a memory write bus cycle.
Q: Consider a 512 KB cache system used in our laptop. The access time for the cache is 25 ns, and the…
A: Your answer is given below in detail.
Q: If the RAM has a two byte data word and address bits are grouped for direct mapping with a cache…
A: Balance bits = 5 bits so block offset = 5 pieces Limit of square = 2^5 = 32 Bytes Address =…
Q: Explain about TLB, page table, and cache for small memory system ?
A: TLB: A translation lookaside buffer (TLB) is a memory reserve that is utilized to lessen the time…
Q: Assume a system has a Translation Look-aside Buffer (TLB) hit ratio of 95%. It requires 20…
A: Effective Access Time = P x hit time + (1-P) x miss time given, P = 95% = .95 1-P = 5% = .05 hit…
Q: The access time of cache is 100 us, the access time of main memory is 90 us, and hit ratio is 95%,…
A: Cache access time tc=100 Memory access time tm= 90 microsec. Hit ratio h=95%=0.95
Q: Discuss the nature of short-term memory in terms ofits endurance and capacity.
A: Short-term memory Short-term memory stores the information that the human mind is currently thinking…
Q: A 16-way set-associative cache memory unit with a capacity of 32 KB is built using a block size of 8…
A: Introduction :Given , A cache associativity = 16 way cache size = 32 KB Block size = 8 words the…
Q: 15. How many 64 K memories can be placed (without overlapping) in the memory space of a processor…
A: Solution-Total memory to be placed=64k Available address lines=24…
Q: A memory system consists of a cache with a hit time of 5 nsec, if the miss penalty is 100 nsec and…
A: Here we calculate the Cache hit rate by using the given information and correct the answer , so the…
Q: Design a direct mapped cache with 1 MB of data and 6-word block size and assume a 33-bit address.…
A: DIRECT MAPPED CACHE: In this method ,each main memory address maps to exactly one cache block.
Q: Consider a system with 2-level cache, at 0.6 hit ratio in level 1 memory. The L1 memory is 4 times…
A: There is a decrease of ≈ 44%.
Q: Suppose that a cache is 20 times faster than main memory and cache memory can be used 80% of the…
A:
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- Suppose a byte-addressable computer using set associative cache has 224 bytes of main memory and a cache size of 64K bytes, and each cache block contains 32 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache?Suppose a byte-addressable computer using set associative cache has 8M byes of main memory and a cache of 128 blocks, where each cache block contains 64 bytes. a) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 16-way set associative, what is the format of a memory address as seen by the cacheSuppose a byte-addressable computer using set associative cache has 4Mbyes of main memory and a cache of 64 blocks, where each cache block contains 8 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache? Show all work and explain how you got the answers please. Thanks
- Suppose a byte-addressable computer using set associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache, that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache?5. Suppose a byte-addressable computer using set-associate cache has 2^21 bytes of main memory and a cache of 64 blocks, where each cache block contains 16 bytes. a) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields? b) If this cache is 4-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?A cache memory system with capacity of N words and block size of B words is to be designed. If it is designed as a direct mapped cache, the length of the TAG field is 14 bits. If it is designed as a 4-way set associative cache, the length of the TAG field will be ………… bits.
- Suppose a byte-addressable computer using set-associative cache has 216 bytes of main memory and a cache of 32 blocks, and each cache block contains 8 bytes.Q.) If this cache is 2-way set associative, what is the format of a memory address as seen by the cache; that is, what are the sizes of the tag, set, and offset fields?By convention, a cache is named according to the amount of data it contains (i.e., a 4 KiB cache can hold 4 KiB of data); however, caches also require SRAM to store metadata such as tags and valid bits. For this exercise, you will examine how a cache's configuration affects the total amount of SRAM needed to implement it as well as the performance of the cache. For all parts, assume that the caches are byte addressable, and that addresses and words are 64 bits. (a) Calculate the total number of bits required to implement a 32 KiB cache with two-word blocks. (b) Calculate the total number of bits required to implement a 64 KiB cache with 16-word blocks. How much bigger is this cache than the 32 KiB cache described in Part a? (Notice that, by changing the block size, we doubled the amount of data without doubling the total size of the cache.)By convention, a cache is named according to the amount of data it contains (ie., a 4 KiB cache can hold 4 KiB of data); however, caches also require SRAM to store metadata such as tags and valid bits. For this exercise, you will examine how a cache's configuration affects the total amount of SRAM needed to implement it as well as the performance of the cache. For all parts, assume that the caches are byte addressable, and that addresses and words are 64 bits. 1. Calculate the total number of bits required to implement a 32 KiB cache with two-word blocks. 2. Calculate the total number of bits required to implement a 64 KiB cache with 16-word blocks. How much bigger is this cache than the 32 KiB cache described in Exercise (1) above? (Notice that, by changing the block size, we doubled the amount of data without doubling the total size of the cache.) 3. Explain why this 64 KiB cache, despite its larger data size, might provide slower performance than the first cache. 4. Generate a…
- A cache memory has a line size of eight 64-bit words and a capacity of 4K words. The main memory size that is cacheable is 1024 Mbits. Assuming 4-way set associative mapping and that the addressing is done at the byte level. What is the format of the main memory addresses (i.e s-d, d, and w)? For the hexadecimal main memory location 2BFACEDH, find the corresponding 4-way set-associative memory formatSuppose a computer using fully associative cache has 220 words of main memory and a cache of 128 blocks, where each cache block contains 16 words. (a) How many blocks of main memory are there? (b) What is the format of a memory address as seen by the cache, that is, what are the sizes of the tag and word fields? (c) To which cache block will the memory reference 01D872_{16} map?In general, a cache is named according to the amount of data it contains (i.e., a 4 KiB cache can hold 4 KiB of data); however, caches also require SRAM to store metadata such as tags and valid bits. You design this cache memory and will examine how a cache's configuration affects the total amount of SRAM needed to implement it as well as the performance of the cache. For all parts, assume that the that addresses and words are 64 bits. (A) Calculate the total number of bits required to implement a 32 KiB cache with two-word blocks. (B) Calculate the total number of bits required to implement a 96 KiB cache with 16-word blocks. How much bigger is this cache than the 32 KiB cache described in (A) above? (Notice that, by changing the block size, we increased the amount of data without doubling the total size of the cache.) (C) Explain why this 96 KiB cache, despite its larger data size, might provide slower performance than the first cache.