Concept explainers
A 50-µC/kg (approximately 200 mR) pocket dosimeter with air-equivalent walls has a sensitive volume with the dimensions in. (diameter) and 2.5 in. (length); the volume is filled with air at atmospheric pressure. The capacitance of the dosimeter is 10 pF. If 200 V are required to charge the chamber, what is the voltage across the chamber when it reads
The voltage across the chamber when it reads 50 µC/kg
Answer to Problem 6.1P
The voltage across the chamber when it reads 50 µC/kg is 150.755 V
Explanation of Solution
Given info:
Diameter, D = 0.5 in
Length, L = 2.5 in
Capacitance, C = 10 pF
Initial Voltage,
Formula used:
To calculate volume of the chamber, use the formula as
Calculation:
First convert the unit from ‘in’ to ‘cm’.
We know, 1 in = 2.54 cm
So, L = 2.5 in = 2.5 × 2.54 cm = 6.35 cm
Also, D = 0.5 in,
Substitute the values in equation (1), we get
Also given that,
Or,
To calculate mass (m), use the relation
Or,
Since, volume is filled with air,
Substitute the values in equation (2), we get
Now, to calculate final voltage use the relation
Substitute the values, we get
Conclusion:
Thus, the voltage across the chamber when it reads 50µC/kg is 150.755V
Want to see more full solutions like this?
Chapter 6 Solutions
Introduction To Health Physics
Additional Science Textbook Solutions
The Physical Universe
Conceptual Physical Science (6th Edition)
University Physics Volume 1
Essential University Physics: Volume 1 (3rd Edition)
Physics of Everyday Phenomena
- The resistance of the tungsten filament of an incandescent light bulb at 22 degC is 34 Ohms. If the light bulb is connected to a voltage of 126 V a current of 0.36 A flows through the filament. What will be the temperature of the light bulb filament under working conditions? The temperature coefficient of resistance of tungsten is 4.6E-3 1/degC. Your answer must be in degC, other scales are not accepted.arrow_forwardThe voltage V (volts), current I (amperes), andresistance R (ohms) of an electric circuitare related by the equation V = IR. Suppose that V is increasing atthe rate of 1 volt/sec while I is decreasing at the rate of 1/3 amp/sec. Let t denote time in seconds. What is the value of dV/dt?arrow_forwardAn electron is fired at a speed vi = 3.1 × 106 m/s and at an angle θi = 36.8° between two parallel conducting plates as shown in the figure. If s = 1.8 mm and the voltage difference between the plates is ΔV = 98.8 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitorarrow_forward
- 1.4. The resistance of a doped germanium crystal obeys the equation log R' = 4.697 – 3.917 log T. (a) In a liquid helium cryostat, the resistance is measured to be 218 N. What is the temperature? (b) Make a log-log graph of R' against T from 200 to 30,000 N. 2: i....arrow_forwardAn electron is fired at a speed vi = 4.3 × 106 m/s and at an angle θi = 39.7° between two parallel conducting plates as shown in the figure. If s = 1.7 mm and the voltage difference between the plates is ΔV = 99.8 V, determine how close, w, the electron will get to the bottom plate. Put your answer in meters and include at 6 decimal places in your answer. Do not include units. The x-axis of the coordinate system is in the middle of the parallel plate capacitor. Round your answer to 6 decimal places.arrow_forwardQUESTION 8 Find the uncertainty in a calculated electrical potential difference from the measurements of current and resistance. Electric potential difference depends on current and resistance according to this function V(I,R) = IR. Your measured current and resistance have the following values and uncertainties I = 2.4 Amps, 81 = 0.2 Amps and R = 29.5 Ohms and SR = 0.6 Ohms. What is the uncertainty in %3! %3D the , SV ? Units are not needed in your answer.arrow_forward
- The voltage V (volts), current I (amperes), andresistance R (ohms) of an electric circuitare related by the equation V = IR. Suppose that V is increasing atthe rate of 1 volt/sec while I is decreasing at the rate of 1/3 amp/sec. Let t denote time in seconds. What equation relates dR/dt to dV/dt and dI/dt?arrow_forwardAluminium is a good conductor of electricity. A 100 m aluminium wire of diameter 2.25 mm is to be used in domestic electrical wiring. If a voltage of 250V and a current of 13 amps are needed, answer the following i. What is the conductivity of the aluminium wire?arrow_forwardYou plotted a graph of current vs. voltage and found the slope of the best fit line is m± Am = 4.69 ± 1.79 Amps/Volt. The resistance can be calculated from the slope by knowing: R = 1 m The fractional uncertainty in the slope is equivalent to the fractional uncertainty in the resistance: AR R = Am m Calculate the uncertainty in the resistance, AR in units of (ohms), then enter the raw value (no units) into the box below. Round to two decimal places. AR=arrow_forward
- The resistance R of a conductor of length L and area of cross – section A carrying a current I is given by: a) R=pA/L, where p=specific resistance b) R = VI, where V = potential different c) R = σA, where σ = electrical conductivity d) R = 2mL/ne 2 τA. Where τ = relaxation time, n the electron density e the electronic charge and m is the mass of an electronarrow_forwardDuring an experiment to verify Ohm's law, the current and resistance of a circuit are measured. [Resistance is measured in Ohm (2) and current in Ampere (A)]. www R +. Battery The measured value of the current is I = 2.3±0.2 A and that of the resistance is R = 10±0.3 0. The voltage applied (in Volts) can be calculated using the formula, V = IR. Calculate the, a) Voltage applied in the circuit (in Volts) = %3! b) Fractional uncertainty in the voltage = c) Absolute uncertainty (in Volts) in the voltage %3!arrow_forwardOS. The output power of a solar PV module is 120 Watts. Number of cells in module are 36 Estimate the following: (take insolation value as 1100 W/m' and efficiency as 18% ) Total output voltage Total output current Total area of module iv. Area of one PV cell Calculate number of PV Modules required to generate power of 48OW. V. 益arrow_forward
- College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage LearningUniversity Physics (14th Edition)PhysicsISBN:9780133969290Author:Hugh D. Young, Roger A. FreedmanPublisher:PEARSONIntroduction To Quantum MechanicsPhysicsISBN:9781107189638Author:Griffiths, David J., Schroeter, Darrell F.Publisher:Cambridge University Press
- Physics for Scientists and EngineersPhysicsISBN:9781337553278Author:Raymond A. Serway, John W. JewettPublisher:Cengage LearningLecture- Tutorials for Introductory AstronomyPhysicsISBN:9780321820464Author:Edward E. Prather, Tim P. Slater, Jeff P. Adams, Gina BrissendenPublisher:Addison-WesleyCollege Physics: A Strategic Approach (4th Editio...PhysicsISBN:9780134609034Author:Randall D. Knight (Professor Emeritus), Brian Jones, Stuart FieldPublisher:PEARSON