Concept explainers
6-35 Describe how we would prepare the following solutions:
(a) 280. mL of a 27% v/v solution of ethanol C2H6O, in water
(b) 435 mL of a 1.8% v/v solution of ethyl acetate, C4H8O2 in water
(c) 1.65 L of an 8.00% v/v solution of benzene C6H6, in chloroform, CHCI3
(a)
Interpretation:
The formation of following solutions should be explained:
280.0 mL of a 27% v/v solution of ethanol,
Concept Introduction:
Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In volume of solute per unit volume of solvent, or v/v, the total volume of the solute, solvent and solution must be known.
The formula for v/v is as follows:
Here,
When solving for the required volume of solute, the following formula is used:
Answer to Problem 21P
Explanation of Solution
Given:
The formula for v/v is as follows:
Here,
When solving for the required volume of solute, the following formula is used:
Substitute known data and solve for mass of solute.
Thus, add
(b)
Interpretation:
The formation of following solutions should be explained:
435 mL of a 1.8 % v/v solution of ethyl acetate
Concept Introduction:
Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In volume of solute per unit volume of solvent, or v/v, the total volume of the solute, solvent and solution must be known.
The formula for v/v is as follows:
Here,
When solving for the required volume of solute, the following formula is used:
Answer to Problem 21P
Explanation of Solution
Given:
The formula for v/v is as follows:
Here,
When solving for the required volume of solute, the following formula is used:
Substitute known data and solve for mass of solute.
Then, add
(b)
Interpretation:
The formation of following solutions should be explained:
1.65 L of a 8.00 % v/v solution of benzene,
Concept Introduction:
Concentration has several ways to be calculated. It typically relates an amount of solute and the solution. In volume of solute per unit volume of solvent, or v/v, the total volume of the solute, solvent and solution must be known.
The formula for v/v is as follows:
Here,
When solving for the required volume of solute, the following formula is used:
Answer to Problem 21P
Explanation of Solution
Given:
The formula for v/v is as follows:
Here,
When solving for the required volume of solute, the following formula is used:
Substitute known data and solve for mass of solute.
Then, add
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Chapter 6 Solutions
Introduction To General, Organic, And Biochemistry
- 6-39 Assuming that the appropriate volumetric flasks are available, describe how we would make these solutions: (a) 175 mL of a 1.14 M solution of NH4Br in water (b) 1.35 L of a 0.825 M solution of Nal in water (c) 330 mL of a 0.16 M solution of ethanol, C2H6O, in waterarrow_forward6-67 Calculate the freezing points of solutions made by dissolving 1.00 mole of each of the following ionic solutes in 1000. g of H2O. (a) NaCI (b) MgCI2 (c) (NH4)2CO3 (d) AI(HCO3)3arrow_forward6-38 Describe how we would prepare 250 mL of 0.10 M NaOH from solid NaOH and water.arrow_forward
- 6-54 An industrial wastewater contains 3.60 ppb cadmium Cd2+. How many mg of Cd2+ could be recovered from a ton (1016 kg) of this wastewater?arrow_forward6-53 Dioxin is considered to be poisonous in concentrations above 2 ppb. If a lake containing L has been contaminated by 0.1 g of dioxin, did the concentration reach a dangerous level?arrow_forward6-74 An osmotic semipermeable membrane that allows only water to pass separates two compartments, A and B. Compartment A contains 0.9% NaCI, and compartment B contains 3% glycerol C3H8O3. (a) In which compartment will the level of solution rise? (b) Which compartment (if either) has the higher osmotic pressure?arrow_forward
- 6-16 Answer true or false. (a) Solubility is a physical property like melting point and boiling point. (b) All solutions are transparent—that is, you can see through them. (c) Most solutions can be separated into their components by physical methods such as distillation and chromatography.arrow_forward6-48 How many grams of solute are present in each of the following aqueous solutions? (a) 575 mL of a 2.00 M solution of nitric acid, HNO3 (b) 1.65 L of a 0.286 M solution of alanine, C3H7NO2 (c) 320 mL of a 0.0081 M solution of calcium sulfate, CaSO4arrow_forward6-112 List the following aqueous solutions in order of increasing boiling point: 0.060 M glucose (C6H12O6), 0.025 M LiBr, and 0.025 M Zn(NO3)2.Assume complete dissociation of any salts.arrow_forward
- 6-37 Calculate the w/v percentage of each of these solutes: (a) 623 mg of casein in 15.0 mL of milk (b) 74 mg of vitamin C in 250 mL of orange juice (c) 3.25 g of sucrose in 186 mL of coffeearrow_forward6-70 In winter, after a snowstorm, salt (NaCI) is spread to melt the ice on roads. How many grams of salt per 1000. g of ice is needed to make it liquid at-5°C?arrow_forward6-49 A student has a stock solution of 30.0% w/v H2O2 (hydrogen peroxide). Describe how the student should prepare 250 mL of a 0.25% w/v H2O2 solution.arrow_forward
- Introduction to General, Organic and BiochemistryChemistryISBN:9781285869759Author:Frederick A. Bettelheim, William H. Brown, Mary K. Campbell, Shawn O. Farrell, Omar TorresPublisher:Cengage LearningGeneral, Organic, and Biological ChemistryChemistryISBN:9781285853918Author:H. Stephen StokerPublisher:Cengage Learning