Universe: Stars And Galaxies
6th Edition
ISBN: 9781319115098
Author: Roger Freedman, Robert Geller, William J. Kaufmann
Publisher: W. H. Freeman
expand_more
expand_more
format_list_bulleted
Concept explainers
Question
Chapter 5, Problem 12Q
To determine
The reason why astronomer prefer to work on Kelvin scale in their work rather than Celsius or Fahrenheit.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
How many watts will be radiated from a spherical black body 25 cm in diameter at a temperature of 900 degrees Celsius?
Calculate the amount of radiation emitted for a unit surface (1 m2) for a white ball at 53°C and £≈0.12. Express your Answer SI units (in W).
The amount of radiant energy emitted by a
surface is given by
q = ɛ0 AT+
where
q represents the rate of thermal energy
(per unit time) emitted by the surface in watts;
e = the emissivity of the surface 0<ɛ<1
and is unitless
o = Stefan-Boltzman constant
(o = 5.67×10% )
A represents the area of the surface in m²
Ty = surface temperature of the object
expressed in kelvin
What are the appropriate units for o if the
equation is to be homogeneous in units?
Chapter 5 Solutions
Universe: Stars And Galaxies
Ch. 5 - Prob. 1QCh. 5 - Prob. 2QCh. 5 - Prob. 3QCh. 5 - Prob. 4QCh. 5 - Prob. 5QCh. 5 - Prob. 6QCh. 5 - Prob. 7QCh. 5 - Prob. 8QCh. 5 - Prob. 9QCh. 5 - Prob. 10Q
Ch. 5 - Prob. 11QCh. 5 - Prob. 12QCh. 5 - Prob. 13QCh. 5 - Prob. 14QCh. 5 - Prob. 15QCh. 5 - Prob. 16QCh. 5 - Prob. 17QCh. 5 - Prob. 18QCh. 5 - Prob. 19QCh. 5 - Prob. 20QCh. 5 - Prob. 21QCh. 5 - Prob. 22QCh. 5 - Prob. 23QCh. 5 - Prob. 24QCh. 5 - Prob. 25QCh. 5 - Prob. 26QCh. 5 - Prob. 27QCh. 5 - Prob. 28QCh. 5 - Prob. 29QCh. 5 - Prob. 30QCh. 5 - Prob. 31QCh. 5 - Prob. 32QCh. 5 - Prob. 33QCh. 5 - Prob. 34QCh. 5 - Prob. 35QCh. 5 - Prob. 36QCh. 5 - Prob. 37QCh. 5 - Prob. 38QCh. 5 - Prob. 39QCh. 5 - Prob. 40QCh. 5 - Prob. 41QCh. 5 - Prob. 42QCh. 5 - Prob. 43QCh. 5 - Prob. 44QCh. 5 - Prob. 45QCh. 5 - Prob. 46QCh. 5 - Prob. 47QCh. 5 - Prob. 48QCh. 5 - Prob. 49QCh. 5 - Prob. 50QCh. 5 - Prob. 51Q
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- If an incandescent light bulb has a luminosity L= 60W and a filament temperature of T= 2900K, what must be the surface area of its filament? If the filament consists of a cylindrical wire with diameter d= 4.6×10^−5m (as in a standard incandescent 60 watt, 120 voltbulb), what is the length of the wire?arrow_forwardThe following heat transfer formula quantifies the radiation emitted from the Sun: P = eoA(T4 – T?) Equation 5 where: P= radiated power (Watts) e = emissivity (=1 for ideal radiator; unitless) o = Stefan-Boltzmann constant = 5.67x10-8 W/m2-K+ A = radiating area (m²) T= temperature of radiator (Kelvin) Tc = temperature of surroundings (Kelvin) Q3 Using the following values, together with equation 5, calculate the power emitted by the Sun. sun's surface temperature = 5780 K temperature of the environment that the Sun is located in = 4 K emissivity of the Sun = 1 radius of the Sun = 695,700,000 m Stephen-Boltzmann constant o = 5.67 x 10-8 W/m2-K4 Show your work below-you may use the equation editor or insert a picture of your handwritten work.arrow_forwardWhat is the vrms of hydrogen on the surface of the sun if its temperature is 5.36E3 degC? What is the vrms of hydrogen on the surface of the earth if its temperature is 21.2 degC?arrow_forward
- Give proper explanation The surface temperature of the Sun is about 5750 K. What is this temperature on the Fahrenheit scale?arrow_forwardYou are trying to measure the outside temperature at a particular time. If you use three thermometers and place all three in direct sunlight, the sunlight is likely to cause your measurements to suffer from what kind of error? Group of answer choices A) Your measurements will suffer from systematic errors because the sunlight affects all measurements in the same way by making them too high by the same amount. B) Your measurements will suffer from a decrease in precision because the thermometer only uses whole numbers. C) Your measurements will suffer from random errors because they will be expressed as a percentage. D) Your measurements will suffer from random errors because of the randomness of cloud movements. Sometimes the clouds block sunlight. E) Your measurements will suffer from systematic errors because they will never quite match the true temperature. F) Your measurements will suffer from a decrease in precision because at the same time of day tomorrow the amount…arrow_forwardwe were given the answer of 60mJ but I'm not sure how that came about.arrow_forward
- (W/m), in Santa solar radiation into energy- solar radiation (w/m?) 400 300 200 100 time (hrs past midnight) 4 8 12 16 20 ot dengndi loarrow_forwardNear the martian equator, temperatures at the same spot can vary from an average of 135 °C at night to an average of 30 °C during the day. How can you explain such a wide difference in temperature compared to that on Earth?arrow_forwardProxima Centauri, the nearest star to our Sun, has a surface temperature of 2,768.85 °C. What is its total intensity emitted? O 4.3 MW per square meter. O 4.9 MW per square meter. O 5.2 MW per square meter. O 5.7 MW per square meter. O 6.4 MW per square meter.arrow_forward
- (1a). Figure shows a copper rod AB being heated at one end. Explain how the heat transfers from A to B. What is the name of this method? copper rod B Bunsen burner (1b). The Earth can be considered to be a perfect black body radiator at a temperature of 112 F. Radius of Earth is 6390 km. Calculate the total power radiated from the Earth in Watts (W)arrow_forwardIf the temperature of an object goes from 500 K to 9500 K,(c) By what factor is its energy emitted per second increased?If the temperature of an object goes from 900 K to 9000 K,(d) By what factor is its energy emitted per second increased?arrow_forwardA window has heavy curtains in front of it. At night the curtains are closed to minimise heat loss. During the day the curtains are pulled aside exposing the glass window. How much heat is lost through the 1.0 m x 1.0 m square glass window pane that is 4mm thick when the inside temperature is 20 degree C and the outside temperature is -6 C (negative 6.0) in 12 hrs? ( 1m = 100 cm) (1m = 1000mm) %3Darrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
AstronomyPhysicsISBN:9781938168284Author:Andrew Fraknoi; David Morrison; Sidney C. WolffPublisher:OpenStax
Stars and Galaxies (MindTap Course List)PhysicsISBN:9781337399944Author:Michael A. SeedsPublisher:Cengage Learning
Astronomy
Physics
ISBN:9781938168284
Author:Andrew Fraknoi; David Morrison; Sidney C. Wolff
Publisher:OpenStax
Stars and Galaxies (MindTap Course List)
Physics
ISBN:9781337399944
Author:Michael A. Seeds
Publisher:Cengage Learning