COLLEGE PHYSICS
2nd Edition
ISBN: 9781464196393
Author: Freedman
Publisher: MAC HIGHER
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Chapter 3, Problem 74QAP
To determine
(a)
The football's initial speed.
To determine
(b)
The time taken by the ball to pass through the goal posts.
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Chapter 3 Solutions
COLLEGE PHYSICS
Ch. 3 - Prob. 1QAPCh. 3 - Prob. 2QAPCh. 3 - Prob. 3QAPCh. 3 - Prob. 4QAPCh. 3 - Prob. 5QAPCh. 3 - Prob. 6QAPCh. 3 - Prob. 7QAPCh. 3 - Prob. 8QAPCh. 3 - Prob. 9QAPCh. 3 - Prob. 10QAP
Ch. 3 - Prob. 11QAPCh. 3 - Prob. 12QAPCh. 3 - Prob. 13QAPCh. 3 - Prob. 14QAPCh. 3 - Prob. 15QAPCh. 3 - Prob. 16QAPCh. 3 - Prob. 17QAPCh. 3 - Prob. 18QAPCh. 3 - Prob. 19QAPCh. 3 - Prob. 20QAPCh. 3 - Prob. 21QAPCh. 3 - Prob. 22QAPCh. 3 - Prob. 23QAPCh. 3 - Prob. 24QAPCh. 3 - Prob. 25QAPCh. 3 - Prob. 26QAPCh. 3 - Prob. 27QAPCh. 3 - Prob. 28QAPCh. 3 - Prob. 29QAPCh. 3 - Prob. 30QAPCh. 3 - Prob. 31QAPCh. 3 - Prob. 32QAPCh. 3 - Prob. 33QAPCh. 3 - Prob. 34QAPCh. 3 - Prob. 35QAPCh. 3 - Prob. 36QAPCh. 3 - Prob. 37QAPCh. 3 - Prob. 38QAPCh. 3 - Prob. 39QAPCh. 3 - Prob. 40QAPCh. 3 - Prob. 41QAPCh. 3 - Prob. 42QAPCh. 3 - Prob. 43QAPCh. 3 - Prob. 44QAPCh. 3 - Prob. 45QAPCh. 3 - Prob. 46QAPCh. 3 - Prob. 47QAPCh. 3 - Prob. 48QAPCh. 3 - Prob. 49QAPCh. 3 - Prob. 50QAPCh. 3 - Prob. 51QAPCh. 3 - Prob. 52QAPCh. 3 - Prob. 53QAPCh. 3 - Prob. 54QAPCh. 3 - Prob. 55QAPCh. 3 - Prob. 56QAPCh. 3 - Prob. 57QAPCh. 3 - Prob. 58QAPCh. 3 - Prob. 59QAPCh. 3 - Prob. 60QAPCh. 3 - Prob. 61QAPCh. 3 - Prob. 62QAPCh. 3 - Prob. 63QAPCh. 3 - Prob. 64QAPCh. 3 - Prob. 65QAPCh. 3 - Prob. 66QAPCh. 3 - Prob. 67QAPCh. 3 - Prob. 68QAPCh. 3 - Prob. 69QAPCh. 3 - Prob. 70QAPCh. 3 - Prob. 71QAPCh. 3 - Prob. 72QAPCh. 3 - Prob. 73QAPCh. 3 - Prob. 74QAPCh. 3 - Prob. 75QAPCh. 3 - Prob. 76QAPCh. 3 - Prob. 77QAPCh. 3 - Prob. 78QAPCh. 3 - Prob. 79QAP
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- Suppose you take two steps A and B (that is, two nonzero displacements). Under what circumstances can you end up at your starting point? More generally, under what circumstances can two nonzero vectors add to give zero? Is the maximum distance you can end up from the starting point A+B the sum of the lengths of the two steps?arrow_forwardYou can use any coordinate system you like to solve a projectile motion problem. To demonstrate the truth of this statement, consider a ball thrown off the top of a building with a velocity v at an angle with respect to the horizontal. Let the building be 50.0 m tall, the initial horizontal velocity be 9.00 m/s, and the initial vertical velocity be 12.0 m/s. Choose your coordinates such that the positive y-axis is upward, the x-axis is to the right, and the origin is at the point where the ball is released, (a) With these choices, find the balls maximum height above the ground and the time it takes to reach the maximum height. (b) Repeat your calculations choosing the origin at the base of the building.arrow_forwardYou can use any coordinate system you like to solve a projectile motion problem. To demonstrate the truth of this statement, consider a ball thrown off the top of a building with a velocity v at an angle with respect to the horizontal. Let the building be 50.0 m tall, the initial horizontal velocity be 9.00 m/s, and the initial vertical velocity be 12.0 m/s. Choose your coordinates such that the positive y-axis is upward, the x-axis is to the right, and the origin is at the point where the ball is released, (a) With these choices, find the balls maximum height above the ground and the time it takes to reach the maximum height. (b) Repeat your calculations choosing the origin at the base of the building.arrow_forward
- (a) Repeat the problem two problems prior, but for the second leg you walk 20.0 m in a direction 40.0° north of east (which is equivalent to subtracting B from A that is, to finding R=AB ). (b) Repeat the problem two problems prior, but now you first walk 20.0 m in a direction 40.0° south of west and then 12.0 m in a direction 20.0° east of south (which is equivalent to subtracting A from B that is, to finding R=BA=R ). Show that this is the case.arrow_forwardA projectile is fired from the top of a cliff of height h above the ocean below. The projectile is fired at an angle above the horizontal and with an initial speed vi. (a) Find a symbolic expression in terms of the variables vi, g, and for the time at which the projectile reaches its maximum height. (b) Using the result of part (a), find an expression for the maximum height hmax above the ocean attained by the projectile in terms of h, vi, g, and .arrow_forwardIn 2007, Michael Carter (U.S.) set a world record in the shot put with a throw of 24.77 m. What was the initial speed of the shot if he released it at a height of 2.10 m and threw it at an angle of 38.0° above the horizontal? (Although the maximum distance for a projectile on level ground is achieved at 45° when air resistance is neglected, the actual angle to achieve maximum range is smaller; thus, 38° will give a longer range than 45° in the shot put.)arrow_forward
- Answer the following questions for projectile motion on level ground assuming negligible air resistance (the initial angle being neither 0° nor 90°) (a) Is the velocity ever zero? (b) When is the velocity a minimum? A maximum? (c) Can the velocity ever be the same as the initial velocity at a time other than at t=0 ? (d) Can the speed ever be the same as the initial speed at a time other than at t=0 ?arrow_forward(a) A daredevil is attempting to jump his motorcycle over a line of buses parked end to end by driving up a 32° ramp at a speed of 40.0 m/s (144 km/h). How many buses can he clear if the top of the takeoff ramp is at the same height as the bus tops and the buses are 20.0 m long? (b) Discuss what your answer implies about the margin of error in this act—that is, consider how much greater the range is than the horizontal distance he must travel to miss the end of the last bus. (Neglect air resistance.)arrow_forwardFigure OQ3.3 shows two vectors D 1, and D2. Which of the possibilities (a) through (d) is the vector D2 - 2D1, or (e) is it none of them?arrow_forward
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Kinematics Part 3: Projectile Motion; Author: Professor Dave explains;https://www.youtube.com/watch?v=aY8z2qO44WA;License: Standard YouTube License, CC-BY