Modern Physics For Scientists And Engineers
2nd Edition
ISBN: 9781938787751
Author: Taylor, John R. (john Robert), Zafiratos, Chris D., Dubson, Michael Andrew
Publisher: University Science Books,
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Chapter 3, Problem 3.44P
To determine
The derivation for the expression of
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A 2.50 MeV electron moves perpendicularly to a magnetic field in a path with a 3.0 cm radius of curvature.What is the magnetic field B?
J. J. Thomson is best known for his discoveries about the
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A limitation on how many spectra per second can be recorded by a time-of-flight mass spectrometer is the time it takes the slowest ion to go from the source to the detector. Suppose we want to scan up to m/z 500 for ions with z = 1. Calculate the speed of this heaviest ion if it is accelerated through 5.00 kV in the source. How long would it take to drift 2.00 m through a spectrometer? At what frequency could you record spectra if a new extraction cycle were begun each time the heaviest ion reached the detector? What would be the frequency if you wanted to scan up to m/z 1000?
Chapter 3 Solutions
Modern Physics For Scientists And Engineers
Ch. 3 - Prob. 3.1PCh. 3 - Prob. 3.2PCh. 3 - Prob. 3.3PCh. 3 - Prob. 3.4PCh. 3 - Prob. 3.5PCh. 3 - Prob. 3.6PCh. 3 - Prob. 3.7PCh. 3 - Prob. 3.8PCh. 3 - Prob. 3.9PCh. 3 - Prob. 3.10P
Ch. 3 - Prob. 3.11PCh. 3 - Prob. 3.12PCh. 3 - Prob. 3.13PCh. 3 - Prob. 3.14PCh. 3 - Prob. 3.15PCh. 3 - Prob. 3.16PCh. 3 - Prob. 3.17PCh. 3 - Prob. 3.18PCh. 3 - Prob. 3.19PCh. 3 - Prob. 3.20PCh. 3 - Prob. 3.21PCh. 3 - Prob. 3.22PCh. 3 - Prob. 3.23PCh. 3 - Prob. 3.24PCh. 3 - Prob. 3.25PCh. 3 - Prob. 3.26PCh. 3 - Prob. 3.27PCh. 3 - Prob. 3.28PCh. 3 - Prob. 3.29PCh. 3 - Prob. 3.30PCh. 3 - Prob. 3.31PCh. 3 - Prob. 3.32PCh. 3 - Prob. 3.33PCh. 3 - Prob. 3.34PCh. 3 - Prob. 3.35PCh. 3 - Prob. 3.36PCh. 3 - Prob. 3.37PCh. 3 - Prob. 3.38PCh. 3 - Prob. 3.39PCh. 3 - Prob. 3.40PCh. 3 - Prob. 3.41PCh. 3 - Prob. 3.42PCh. 3 - Prob. 3.43PCh. 3 - Prob. 3.44PCh. 3 - Prob. 3.45PCh. 3 - Prob. 3.46PCh. 3 - Prob. 3.47PCh. 3 - Prob. 3.48PCh. 3 - Prob. 3.49PCh. 3 - Prob. 3.50PCh. 3 - Prob. 3.51P
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- The velocity of electron in the first Bohr orbit of radius 0.5 A.U. is 2.24 x 106 m/s. Calculate the period of revolution of the electron in the same orbit.arrow_forwardAssuming that the radius of the circular path of the electron is 4.9cm when voltage is 100v and coil current is 1A and The Helmholtz coils have 130 turns and a radius of 15 cm. With N=130 and R=0.15 What is the velocity of the electrons at 100 V, assuming the known charge and mass of the electron from the accepted universal constants that are the basis of SI units? Hints: Do a classical calculation of the kinetic of the electon assuming you know its mass (in kg) and its charge (in coulomb). That will be 1/2 mv2. Equate that to the energy of the electron gained by accelerating in the electric field, that is, eV where "e" is the charge and "V" is the difference potential in volts. Solve for "v", the velocity. Enter your answer in km/s, 103 m/s, without units. It is best to enter only a number, without an "e". For example, if you found 2000 m/s you would enter "2" for the velocity in km/s. Electrons have low mass and achieve high velocity in modest fields.arrow_forwardWhat is the velocity of a beam of electrons that go undeflected when passing through crossed (perpendicular) electric and magnetic fields of magnitude 1.93×104 V/m and 2.50×10-3T, respectively? me=9.11×10-31kg, e=1.60×10-19 C.arrow_forward
- The deflector plates of a Thomson appliance are 6.0 cm long and separated by 1.2 cm. The distance between the front edge of the plate and the tube is 30.0 cm. The energy assigned to the electrons of the beam is 2.8 keV (can make an illustration for a good understanding) (a) If the potential of 25 V is applied to the deflector plates, what will be the deviation of the beam on the screen? (b) Find the module of the crossed magnetic field that would allow the beam to pass through the plates, without suffering any deviation. Answer a) 7.36 mm b) 6.64 x 10^ - 5 Tarrow_forwardAn electron is fired through a region of crossed electric and magnetic field (0.05 T). The electric field is formed between two plates separated by a distance of 2 mm having a P.D. of 125 V. The speed of the electron isarrow_forwardSilver contains 5.8 * 1028 free electrons per cubic meter. At absolute zero, what is the speed of an electron with this energy?arrow_forward
- The beam of electrons goes undeflected when passing through crossed electric and magnetic fields of magnitude 6x104 V/m and 1x10-3 T, respectively. What is the radius of the electron orbit, in mm, if the electric field is turned off? Give your answer to 2 decimals.arrow_forwarda) Suppose we have an electron moving perpendicular to a B-field along a circular path of radius 18 cm. If imposition of an E-field of 17.1 kV/m makes the path straight, what is the value of B? b) Suppose our E-field measurement has an uncertainty of 0.75 kV/m and our radius of curvature measurement has an uncertainty of 0.2 cm. What is the total uncertainty associated with the magnetic field we just calculated?arrow_forwardIn the Millikan oil drop experiment tiny charged oil droplets generated by a spray are allowed to fall under gravity through a hole in a top electrode, T, towards a bottom electrode B separated from T by 1 cm. When a holding voltage Vh = +0.25V is applied between T and B the droplets are seen to be suspended motionless between the electrodes. What is the specific charge of the droplet q/m? Select one: a. 0.16 C/kg b. 0.392 C/kg с. 2.7 С/kg O d. 1.5 C/kgarrow_forward
- Determine the distance between the electron and proton in an atom if the potential energy ?U of the electron is 13 eV (electronvolt, 1 eV =1.6×10−19=1.6×10−19 J). Give your answer in Angstrom (1 A = 10-10 m).arrow_forwardIn 1897 J.J Thomson ”discovered” the electron by measuring the charge-to-mass ratio of ”cathode rays” (actually, streams of electrons, with charge q and mass m) as follows : (a) First he passed the beam through uniform crossed electric and magnetic fields E and B (mutually perpendicular, and both of them perpendicular to the beam), and adjusted the electric field until he got zero deflection. Derive the speed of the particles (in terms of E and B).(b) Then he turned off the electric field, and measured the radius of curvature, R, of the beam as deflected by the magnetic field alone. In terms of E, B, and R, what is the charge to mass ratio (q/m) of the particles ? (See pictures for original)arrow_forwardIn a laboratory experiment designed to duplicate Thomson’s determination of qe / me , a beam of electrons having a velocity of 6.00×107 m/s enters a 5.00×10−3 T magnetic field. The beam moves perpendicular to the field ina path having a 6.80-cm radius of curvature. Determine qe / me from these observations, and compare the result with the known value.arrow_forward
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