Concept explainers
Videos
(a)
To identify an action-reaction pair of forces.
(a)
Answer to Problem 1Q
The force the person exerts on the wall and the force the wall exerts on the person is an action-reaction pair.
Explanation of Solution
Action – reaction pair of forces always acts on separate object.
When a person pushes on a wall, the wall pushes back on the person. Here the person exerts force on the wall and wall in turn exerts force on the person. The force exerted by the person on the wall is equal in magnitude and opposite in direction to the force exerted by the wall on the person and they acts on different objects.
Conclusion:
Therefore, the force the person exerts on the wall and the force the wall exerts on the person is an action-reaction pair.
(b)
To identify an action-reaction pair of forces, book resting on the table.
(b)
Answer to Problem 1Q
The gravitational force exerted the book on the table and the normal force exerted by the table on the book is action-reaction pair force.
Explanation of Solution
The gravitational force exerted by the book on the table and the normal force exerted by the table on the book is action-reaction pair force and they acts on different objects. The gravitational force exerted by the book on the table is equal in magnitude and opposite in direction to the force exerted by the table on the book.
Conclusion:
Therefore, the gravitational force exerted the book on the table and the normal force exerted by the table on the book is action-reaction pair force.
(c)
To identify an action-reaction pair of forces, a hockey puck sliding across an icy surface.
(c)
Answer to Problem 1Q
The
Explanation of Solution
The frictional force exerted by the moving hockey puck on the ice and the frictional force exerted by the ice on the hockey puck is action-reaction pair force and they acts on different objects. The frictional force exerted by the moving hockey puck on the ice is equal in magnitude and opposite in direction to the frictional force exerted by the ice on the hockey puck.
Conclusion:
Therefore, the frictional force exerted by the moving hockey puck on the ice and the frictional force exerted by the ice on the hockey puck is action-reaction pair force.
(d)
To identify an action-reaction pair of forces, a car accelerating from rest.
(d)
Answer to Problem 1Q
The frictional force exerted by the tire on the road and the force exerted by the road on the tire is action-reaction pair force.
Explanation of Solution
The frictional force exerted by the tire on the road and the force exerted by the road on the tire is action-reaction pair force and they acts on different objects. The frictional force exerted by the rotating tire on the road is equal in magnitude and opposite in direction to the frictional force exerted by the road on the tire.
Conclusion:
Therefore, the frictional force exerted by the tire on the road and the force exerted by the road on the tire is action-reaction pair force.
(e)
To identify an action-reaction pair of forces, an object undergoing free fall in a vacuum.
(e)
Answer to Problem 1Q
The gravitational force exerted on the object by the object on which the object is falling and gravitational force on the falling object on which the object is falling is an action-reaction pair.
Explanation of Solution
The gravitational force exerted on the object by the object on which the object is falling is equal in magnitude and opposite in direction to gravitational force on the falling object on which the object is falling is an action-reaction pair and they acts on different objects.
Conclusion:
Therefore, the gravitational force exerted on the object by the object on which the object is falling and gravitational force on the falling object on which the object is falling is an action-reaction pair.
(f)
To identify an action-reaction pair of forces, a basketball player jumping to dunk a basketball.
(f)
Answer to Problem 1Q
The force exerted by the basketball player against the floor and the force the floor exerts on the basket ball are action-reaction pairs.
Explanation of Solution
The force exerted by the basketball player against the floor while he dunks the ball and the force the floor exerts on the basket ball are equal in magnitude and opposite in direction and they acts on different objects. The force exerted by the basketball player against the floor while and the force the floor exerts on the basket ball are action-reaction pairs.
Conclusion:
Therefore, the force exerted by the basketball player against the floor while and the force the floor exerts on the basket ball are action-reaction pairs.
(g)
To identify an action-reaction pair of forces, a person throwing a baseball.
(g)
Answer to Problem 1Q
The force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is action-reaction pair.
Explanation of Solution
The force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is equal in magnitude and opposite in direction and they acts on different objects. The force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is action-reaction pair.
Conclusion:
Therefore, the force the person exerts against the basket ball to accelerate it and the force the basketball exerts on the person is action-reaction pair.
Want to see more full solutions like this?
Chapter 3 Solutions
College Physics, Volume 1
- Which of the following statements is most correct? (a) It is possible for an object to have motion in the absence of forces on the object. (b) It is possible to have forces on an object in the absence of motion of the object. (c) Neither statement (a) nor statement (b) is correct. (d) Both statements (a) and (b) are correct.arrow_forwardA large crate of mass m is placed on the flatbed of a truck but not tied down. As the truck accelerates forward with acceleration a, the crate remains at rest relative to the truck. What force causes the crate to accelerate? (a) the normal force (b) the gravitational force (c) the friction force (d) the ma force exerted by the crate (e) No force is required.arrow_forwardA crate remains stationary after it has been placed on a ramp inclined at an angle with the horizontal. Which of the following statements must be true about the magnitude of the frictional force that acts on the crate? (a) It is larger than the weight of the crate. (b) It is at least equal to the weight of the crate. (c) It is equal to sn. (d) It is greater than the component of the gravitational force acting down the ramp. (e) It is equal to the component of the gravitational force acting down the ramp.arrow_forward
- A horse pulls a cart along a flat road. Consider the following four forces that arise in this situation. (1) the force of the horse pulling on the cart (3) the force of the horse pushing on the road (2) the force of the cart pulling on the horse (4) the force of the road pushing on the horse Which two forces form an "action-reaction" pair that obeys Newton's third law? A) 1 and 2 B) 1 and 3 C) 1 and 4 D) 2 and 4 E) 2 and 3arrow_forwardBlocks with masses of 1.2 kg, 2.4 kg, and 3.0 kg are lined up in a row on a frictionless table. All three are pushed forward by a 14 N force applied to the 1.2 kg block. How much force does the 2.4 kg block exert on (a) the 3.0 kg block and (b) the 1.2 kg block?arrow_forwardA person pushes a shopping cart with a force of 15 N and the cart starts moving away from the person. Which of the following is most likely to be the force exerted by the shopping cart back on the person? Your answer: O ON O 10 N O 15 N O 20 Narrow_forward
- A 50 kg box is initially at rest on the ground. Which of the following forces forms a force pair with the force of gravity of the Earth acting on the box? The force of gravity of the box acting on the Earth The force of friction from the surface acting on the box The normal force of the surface pushing on the box The normal force of the box pushing on the surfacearrow_forwardTwo crates, one with mass 4.00 kg and the other with mass 6.00 kg, sit on the frictionless surface of a frozen pond, connected by a light rope . A woman wearing golf shoes (for traction) pulls horizontally on the 6.00 kg crate with a force F that gives the crate an acceleration of 2.50 m/s2. (a) What is the acceleration of the 4.00 kg crate? (b) Draw a free-body diagram for the 4.00 kg crate. Use that diagram and Newton’s second law to find the tension T in the rope that connects the two crates. (c) Draw a free-body diagram for the 6.00 kg crate. What is the direction of the net force on the 6.00 kg crate? Which is larger in magnitude, T or F? (d) Use part (c) and Newton’s second law to calculate the magnitude of F.arrow_forwardTwo buckets of sand hang from opposite ends of a rope that passes over an ideal pulley. Onebucket is full and weighs 120 N; the other bucket is only partlyfilled and weighs 63 N. (a) Initially, you hold onto the lighterbucket to keep it from moving. What is the tension in the rope?(b) You release the lighter bucket and the heavier one descends.What is the tension in the rope now? (c) Eventually the heavierbucket lands and the two buckets come to rest. What is the tension in the rope now? Show your work and explainarrow_forward
- A stack of four textbooks sits on top of a desk. The mass of the bottom book is 5.0 kg, on top of which is a 4.5 kg book, then a 4.0 kg book, then a 3.5 kg book. What is the normal force exerted on each book?arrow_forwardThe block A with mass of 80 kg slides along the top of the block B with mass of 110 kg. The block A has an acceleration of 3.0 m/s2 when a horizontal force F of 700 N is applied, as in the Figure. There is no friction between the block B and a horizontal frictionless surface, but there is friction between the two blocks. Calculate the acceleration of the block A is going to B during the time that the block A remains in contact. (Your result must be in units of m/s2, contain 2 digits after the decimal. Take g=9.81 m/s2. 3% of error will be tolerated in your answers.)arrow_forwardA child is walking along the sidewalk at a constant speed of 1 m/s while pulling his dog sitting in a wagon. The dog has a mass of 30 kg and the wagon weighs 50 N. If the child pulls the wagon with a force of 60 N at an angle of 30°, what is the frictional force exerted by the wagon on the dog?arrow_forward
Principles of Physics: A Calculus-Based TextPhysicsISBN:9781133104261Author:Raymond A. Serway, John W. JewettPublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning