21st Century Astronomy
6th Edition
ISBN: 9780393428063
Author: Kay
Publisher: NORTON
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Chapter 3, Problem 11QP
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8. The mean distance of Earth from the Sun is 149.6 x 10° km and the mean distance of
Mercury from the Sun is 57.9 x 10° km. The period of Earth's revolutions is 1 year,
what is the period of Mercury's revolution?
a. 0.24 year on Earth
b. 0.42 year on Earth
C. 1.13 year on Earth
d. 1.31 year on Earth
9. The planet Delta has 2 times the gravitational field strength and 3 times the radius of
Earth. How does the mass of the planet Delta compare with the mass of Earth?
9. Which of the following is NOT one of Kepler's Laws of Planetary Motion?
A. The square of a planet's period is proportional to its distance from the sun cubed,
B. The area of a planet's orbital plane is inversely proportional to its speed.
C. A planet sweeps out equal area in an equal time interval.
D. Planets move around the sun in elliptical orbits.
2. From Kepler's Third Law, the period (P) squared divided by the cube of semi-major axis (d) is
the same for all planets and is expressed as P2 / d = k, where k is a constant. One can
conclude that
A. In the same amount of time, every planet orbits the sun.
B. At the same distance from the sun, every planet orbits the sun.
C. It takes more time to orbit the sun if the planets are farthest from the sun.
D. It takes less time to orbit the sun if the planets are farthest from the sun.
Chapter 3 Solutions
21st Century Astronomy
Ch. 3.1 - Prob. 3.1ACYUCh. 3.1 - Prob. 3.1BCYUCh. 3.2 - Prob. 3.2CYUCh. 3.3 - Prob. 3.3CYUCh. 3.4 - Prob. 3.4CYUCh. 3 - Prob. 1QPCh. 3 - Prob. 2QPCh. 3 - Prob. 3QPCh. 3 - Prob. 4QPCh. 3 - Prob. 5QP
Ch. 3 - Prob. 6QPCh. 3 - Prob. 7QPCh. 3 - Prob. 8QPCh. 3 - Prob. 9QPCh. 3 - Prob. 10QPCh. 3 - Prob. 11QPCh. 3 - Prob. 12QPCh. 3 - Prob. 13QPCh. 3 - Prob. 14QPCh. 3 - Prob. 15QPCh. 3 - Prob. 16QPCh. 3 - Prob. 17QPCh. 3 - Prob. 18QPCh. 3 - Prob. 19QPCh. 3 - Prob. 20QPCh. 3 - Prob. 21QPCh. 3 - Prob. 22QPCh. 3 - Prob. 23QPCh. 3 - Prob. 24QPCh. 3 - Prob. 25QPCh. 3 - Prob. 26QPCh. 3 - Prob. 27QPCh. 3 - Prob. 28QPCh. 3 - Prob. 29QPCh. 3 - Prob. 30QPCh. 3 - Prob. 31QPCh. 3 - Prob. 32QPCh. 3 - Prob. 33QPCh. 3 - Prob. 34QPCh. 3 - Prob. 35QPCh. 3 - Prob. 36QPCh. 3 - Prob. 37QPCh. 3 - Prob. 38QPCh. 3 - Prob. 39QPCh. 3 - Prob. 40QPCh. 3 - Prob. 41QPCh. 3 - Prob. 42QPCh. 3 - Prob. 43QPCh. 3 - Prob. 44QPCh. 3 - Prob. 45QP
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- 1. Mars takes 1.88 years to complete one orbit around the sun. What is its average distance from the sun?arrow_forward1. The average orbital distance of Mars is 1.52 times the average orbital distance of the Earth. Knowing that the Earth orbits the sun in approximately 365 days, use Kepler's law of harmonies to predict the time for Mars to orbit the sun.arrow_forwardThe orbit of a planet around the sun is : O A. hyperbolic. O B. parabolic. OC. elliptic. OD. circular.arrow_forward
- Currently, the moon goes around the earth once every 27.3 days. If the moon could be brought into a new circular orbit with a smaller radius, its orbital period would beA. More than 27.3 days.B. 27.3 days.C. Less than 27.3 days.arrow_forwardThe rotation of the planets around the sun is governed by: A. The gravitational field of the sun. B. The gravity of the stars. C. The heat energy of the sun. D. The gravity of the other planets of the solar system. Kelper's second law relates between them: O A. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the sun. OB. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the earth. C. The time period of rotation of the orbiting planet around the sun and the average distance of the planet to the moon. OD. The time period of rotation of the orbiting planet around the earth and the average distance of the planet to the sun.arrow_forwardDirection: Complete the table below. Calculate the problem using the Laws of Planetary Motion based on the given basic planetary data below. F Earth Mars Saturn Uranus Neptune Jupiter 1. 3. Mean Distance(r) Period of 1.496 x 108 44.97x108 2.28 x 108 14.27x108 2. 4. Revolution (T) 365.2 days 1.88 yrs. 11.86 yrs. 84 yrs. Using the Earth as reference, determine the mean distance(r) or the Period of revolution (T) of each planet. Here is the formula in the Law of Period. (T₁)² (r₁)² (T₂)² (r₂)² = 1. Find the Mean distance of Jupiter. 2. Find the Period of Saturn 3. Find the mean distance of Uranus. 4. Find the Period of Neptune.arrow_forward
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