Describe the behavior of the bulb in the two situations below. i. The switch is first moved to position 1 . Describe the behavior of the bulb from just after the switch is closed until a long time later . Explain. ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later . Explain your reasoning.

Question

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Answer 1

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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01:11

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How will the brightness of bulbs A and B change if bulb C is unscrewed? Will the result be different if bulb D or E is unscrewed instead? Explain. 7. Consider the circuit shown on the right. Are the bulbs C, D, and E connected in series, parallel, or neither? Explain. Parallel b/c the junction point is above point D where the current spreads a. Rank the bulbs in order of bright- ness. Use the symbols =, . Explain your ranking. b. с.

Consider the diagram at the right of a parallel circuit. Each light bulb in the circuit has an identical resistance. Use the labeled points on the diagram to answer the following questions. Each question may have one, less than one, or more than one answer. a. The electric potential at point A is the same as the electric potential at point(s) ____. Include all that apply, if any apply. b. The electric potential at point D is the same as the electric potential at point(s) ____. Include all that apply, if any apply. c. The electric potential at point J is the same as the electric potential at point(s) ____. Include all that apply, if any apply. d. The electric potential difference between points A and J is the same as the electric potential difference between points ___ and ____. Include all that apply, if any apply. e. The electric potential difference between points D and G is the same as the electric potential difference between points ___ and ____. Include all that apply, if any…

1. For all practical purposes, a capacitor is considered fully discharged (or fully charged) after 5 time constants. What is the voltage across a discharging capacitor in a RC circuit that has V₁ = 10V, and t = 5 t seconds? Show your work 2. What is the purpose of finding t in a RC circuit? 3. In the virtual simulation, the light bulb is a nice visual indicator of the behavior of a discharging series RC circuit. However, explain why is it easier to find C using a resistor instead of a Light Bulb.

Answer 2

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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01:11

Answer 3

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!

01:11

Answer 4

Textbook Question

Chapter 20.3, Problem 1aTH

Describe the behavior of the bulb in the two situations below.

Chapter 20.3, Problem 1aTH, Describe the behavior of the bulb in the two situations below. i. The switch is first moved to
i. The switch is first moved to position 1. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain.
ii. The switch is now moved to position 2. Describe the behavior of the bulb from just after the switch is closed until a long time later. Explain your reasoning.

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 8

(i)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 9

(i)

Expert Solution

Answer 10

(i)

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is first moved to position 1 .

Answer 13

Explanation of Solution

Introduction:

Consider the circuit shown in Figure 1.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 1

Figure 1

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 1 is shown in Figure 2.

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 2

Figure 2

Initially, thecapacitor is short circuited and starts charging slowly. As thecurrent decays with respect to time, the bulb initially glows, but later it goes dimmer with time, and after a long time it stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 14

(ii)

Expert Solution

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.

Answer 15

(ii)

Expert Solution

Answer 16

(ii)

Expert Solution

Answer 17

Expert Solution

Answer 18

To determine

The behavior of the bulb from just after the switch is closed until a long time later in the situation when the switch is now moved to position 2 .

Answer 19

Explanation of Solution

Introduction:

The brightness of the bulb depends upon the current flowing through that bulb. The bulb will be brighter if the flow of current through that bulb is high. In other words, more current passes through less resistance that mean if the resistance is less then bulb will appear brighter.

The circuit diagram when the switch is at position 2 is shown in Figure 3

Tutorials in Introductory Physics, Chapter 20.3, Problem 1aTH , additional homework tip 3

Figure 3

The capacitor voltage is equal to battery voltage at the initial stage.After this, capacitor startsdischarging and the currentdecays with time. So, blub glows bright initially, but thengoes dimmer with time, and after long timeit stops glowing.

If it stops glowing, the capacitor comes in the open circuit condition and the current flow across it is zero.

Conclusion:

Therefore, the behavior of the bulb from just after the switch is closed until a long time later is described above.