Physics for Scientists and Engineers
6th Edition
ISBN: 9781429281843
Author: Tipler
Publisher: MAC HIGHER
expand_more
expand_more
format_list_bulleted
Concept explainers
Videos
Question
Chapter 2, Problem 78P
(a)
To determine
The time taken by the person A to reach the end of the trial.
(b)
To determine
The time taken by person A to meet person B after turning back from the trail and walking up to person B.
(c)
To determine
The distance of the persons from the end of the trail when they meet.
Expert Solution & Answer
Want to see the full answer?
Check out a sample textbook solution
Students have asked these similar questions
Amir starts riding his bike up a 194-m-long slope at a speed of 5 m/s, decelerating at -0.2 m/s2 as he goes up. At the same instant, Becky starts down from the top at a speed of -2 m/s, accelerating at -0.45 m/s2 as she goes down. How far has Amir ridden when they pass each other?
Hi, I am doing problem number 2 from the end of the chapter questions in my textbook. The problem reads as such:
"An 18-year-old runner can complete a 10.0-km course with an average speed of 4.39 m/s. A 50-year-old runner can cover the same distance with an average speed of 4.27 m/s. How much later (in seconds) should the younger runner start in order to finish the course at the same time as the older runner?"
I am looking at the solution for the problem and I did everything right except the last step. The solution says to subtract the time found for the 18 year old to run 10km from the time found for the 50 year old to run 10km. However, I divided the anwers I found. Why are we subtracting the answers from one another and not dividing them? Thank you!
From rest, the cheetah can accelerate at 8.8 m/s2 and reach a top speed of 30 m/s (108 km/h)! It can maintain this maximum speed over a distance of about 400 meters before it needs to stop.On the other hand, the Thomson’s gazelle has a top speed of 70 km/h, which is less than the cheetah’s, but it can maintain this top speed for a while as well. From rest, the gazelle can accelerate at 4.5 m/s2 to reach its top speed.
Q1. After what total distance from rest must the cheetah stop?
(clearly show calculations)
Q2. In the elapsed time that the cheetah started and must stop, what distance can the gazelle cover?
(again clearly show your calculations)
Chapter 2 Solutions
Physics for Scientists and Engineers
Ch. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10P
Ch. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 16PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 19PCh. 2 - Prob. 20PCh. 2 - Prob. 21PCh. 2 - Prob. 22PCh. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 32PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 35PCh. 2 - Prob. 36PCh. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 71PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86PCh. 2 - Prob. 87PCh. 2 - Prob. 88PCh. 2 - Prob. 89PCh. 2 - Prob. 90PCh. 2 - Prob. 91PCh. 2 - Prob. 92PCh. 2 - Prob. 93PCh. 2 - Prob. 94PCh. 2 - Prob. 95PCh. 2 - Prob. 96PCh. 2 - Prob. 97PCh. 2 - Prob. 98PCh. 2 - Prob. 99PCh. 2 - Prob. 100PCh. 2 - Prob. 101PCh. 2 - Prob. 102PCh. 2 - Prob. 103PCh. 2 - Prob. 104PCh. 2 - Prob. 105PCh. 2 - Prob. 106PCh. 2 - Prob. 107PCh. 2 - Prob. 108PCh. 2 - Prob. 109PCh. 2 - Prob. 110PCh. 2 - Prob. 111PCh. 2 - Prob. 112PCh. 2 - Prob. 113PCh. 2 - Prob. 114PCh. 2 - Prob. 115PCh. 2 - Prob. 116PCh. 2 - Prob. 117PCh. 2 - Prob. 118PCh. 2 - Prob. 119PCh. 2 - Prob. 120PCh. 2 - Prob. 121PCh. 2 - Prob. 122P
Knowledge Booster
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.Similar questions
- From rest, the cheetah can accelerate at 8.8 m/s2 and reach a top speed of 30 m/s (108 km/h)! It can maintain this maximum speed over a distance of about 400 meters before it needs to stop.On the other hand, the Thomson’s gazelle has a top speed of 70 km/h, which is less than the cheetah’s, but it can maintain this top speed for a while as well. From rest, the gazelle can accelerate at 4.5 m/s2 to reach its top speed. When a cheetah goes after a gazelle, success or failure is a simple matter of kinematics: you will determine if the cheetah’s high speed is enough to allow it to reach its prey before it runs out of steam (or time).You will apply basic kinematics and simple assumptions to determine how a chase can play out. The Scene:A cheetah has spotted a gazelle. At the same instant the cheetah leaps into action, the gazelle has spotted him and starts heading directly away.Q1. After what total distance from rest must the cheetah stop? (clearly show calculations and substitutions) Q2.…arrow_forwardFrom rest, the cheetah can accelerate at 8.8 m/s2 and reach a top speed of 30 m/s (108 km/h)! It can maintain this maximum speed over a distance of about 400 meters before it needs to stop.On the other hand, the Thomson’s gazelle has a top speed of 70 km/h, which is less than the cheetah’s, but it can maintain this top speed for a while as well. From rest, the gazelle can accelerate at 4.5 m/s2 to reach its top speed. When a cheetah goes after a gazelle, success or failure is a simple matter of kinematics: you will determine if the cheetah’s high speed is enough to allow it to reach its prey before it runs out of steam (or time).You will apply basic kinematics and simple assumptions to determine how a chase can play out. Q2. In the elapsed time that the cheetah started and must stop, what distance can the gazelle cover? (again clearly show your calculations) Why is the 70 multiplied by 5/18?arrow_forwardGretchen runs the first 4.0 km of a race at 5.0 m/s. Then a stiff wind comes up, so she runs the last 1.0 km at only 4.0 m/s. If she later ran the same course again, what constant speed would let her finish in the same time as in the first race?arrow_forward
- A car is moving at a velocity of 20 m/s. The car then accelerates uniformly at 1.8 m/s2. The car continues at the same acceleration until it reaches a velocity of 25 m/s, which is the legal speed limit. What is the distance the car travels in while accelerating?arrow_forward2.9 .. A ball moves in a straight line (the x-axis). The graph in Fig. E2.9 shows this ball's velocity as a function of time. (a) What are the ball's average speed and average velocity during the first 3.0 s? (b) Suppose that the ball moved in such a way that the graph seg- ment after 2.0 s was –3.0 m/s instead of +3.0 m/s. Find the ball's average speed and average velocity in this case.arrow_forwardA black mamba snake has a length of 2.67 m and a top speed of 3.80 m/s. Suppose a mongoose and a black mamba find themselves nose to nose. In an effort to escape, the snake accelerates at 4.73 m/s2 from rest. How much time does it take the snake to reach its top speed and how far does the snake travel in that time?arrow_forward
- 8. A tennis player moves in a straight-line path as shown x (m) 4 in Figure P2.8. Find her average velocity in the t (s) time intervals from (a) 0 to -2 1 2 3 45 1.0 s, (b) 0 to 4.0 s, (c) 1.0 s to 5.0 s, and (d) 0 to 5.0 s. Figure P2.8arrow_forwardA model rocket accelerates upward from the ground with a constant acceleration, reaching a height of 1000 m in 10 s. a) What is the speed (in m/s) at a height of 1000 m? b) What is the acceleration (in m/s 2)?arrow_forwardA motorcyclist heading east through a small town accelerates at a constant 4.9 m/s/s after he leaves the city limits (See figure). At time t = 0 s, he is 5.3 m east of the city-limits signpost, moving east at 27 m/s. Where is he when his velocity is = 37 m/s?arrow_forward
- A cat walks in a straight line, which we shall call the x-axis with the positive direction to the right. As an observant physicist, you make measurements of this cat's motion and con- struct a graph of the feline's velocity as a function of time (Fig. E2.30). (a) Find the cat's velocity at t = 4.0 s and at t = 7.0 s. (b) What is the cat's acceleration at t = 3.0 s? At t = 6.0 s? At t = 7.0 s? (c) What distance does the cat move dur- ing the first 4.5 s? From t = 0 tot = 7.5 s? (d) Sketch clear graphs of the cat's acceleration and position as functions of time, assuming that the cat started at the origin. Figure E2.30 U₂ (cm/s) 87 8 7 6 5 4 3 2 - O TT -T 1 2 3 4 15 6 7 t (s)arrow_forwardA subway train has to travel a distance of 1800 m until it stops at the next station. The train starts from rest and accelerates at a rate of 1.60 m/s2 for 15.0 s. It then runs at a constant speed for some time and finally slows down at a rate of 4.0m/s2 until it stops at the next station. How long did it take to reach the next station?arrow_forwardsketch a position vs time graph and a velocity vs time graph and an acceleration vs time graph. At time t = 0 you are walking in the positive x direction with a constant speed of 1 m/s. You maintain that speed for 6 s. Then, you decrease your speed uniformly to 0 over a 2 s interval. You rest for 2 s, then turn around and increase your speed uniformly to 2 m/s in 2 s. You continue at that speed until you return to the starting place.arrow_forward
arrow_back_ios
SEE MORE QUESTIONS
arrow_forward_ios
Recommended textbooks for you
College PhysicsPhysicsISBN:9781285737027Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College PhysicsPhysicsISBN:9781305952300Author:Raymond A. Serway, Chris VuillePublisher:Cengage Learning
College Physics
Physics
ISBN:9781285737027
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
College Physics
Physics
ISBN:9781305952300
Author:Raymond A. Serway, Chris Vuille
Publisher:Cengage Learning
Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY