Concept explainers
(a)
Interpretation: Whether the solubility in water will be the same or different for the compounds
Concept introduction: Glyceraldehyde is an aldose which is the simplest monosaccharide that exists with three carbon atoms. Glyceraldehyde exists in two different forms,
(a)
Answer to Problem 18.50EP
The solubility in water for
Explanation of Solution
The most of the properties of
Hence, the solubility in water for
(b)
Interpretation: Whether the reaction with
Concept introduction: Glyceraldehyde is an aldose which is the simplest monosaccharide that exists with three carbon atoms. Glyceraldehyde exists in two different forms,
(b)
Answer to Problem 18.50EP
The given property for
Explanation of Solution
The most of the properties of
Hence, the reaction with
(c)
Interpretation: Whether the rotation of plane polarised light will be the same or different for the compounds
Concept introduction: Glyceraldehyde is an aldose which is the simplest monosaccharide that exists with three carbon atoms. Glyceraldehyde exists in two different forms,
(c)
Answer to Problem 18.50EP
The rotation of plane polarised light for
Explanation of Solution
The most of the properties of
Hence, the rotation of plane polarised light for
(d)
Interpretation: Whether the reaction with methanol will be the same or different for the compounds
Concept introduction: Glyceraldehyde is an aldose which is the simplest monosaccharide that exists with three carbon atoms. Glyceraldehyde exists in two different forms,
(d)
Answer to Problem 18.50EP
The reaction with methanol for
Explanation of Solution
The two forms of glyceraldehyde,
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Chapter 18 Solutions
General, Organic, and Biological Chemistry
- 1. Seliwanoff's test uses 6M HCl as dehydrating agent and resoncinol as condensation reagent. The test reagent dehydrates ketohexoses to produce a a. green compound b. violet precipitate c. faint pink color d. cherry red product 2. Bial’s test reacts with hexoses yield a a. red or pink product b. brown to grey product c. blue to purple color d. white precipitate 3. Bial’s test uses concentrated HCl as a dehydrating acid and orcinol + traces of ferric chloride as condensation reagent. The test reagent dehydrates pentoses to form furfural. Furfural further reacts with orcinol and the iron ion present in the test reagent to produce a a. bluish or green product b. red precipitate c. yellow solution d. light pink or pink solution 4. The copper sulfate (CuSO4) present in Benedict's solution reacts with electrons from the aldehyde or ketone group of certain sugars to form a carboxylic acid and a a. reddish…arrow_forwardHow would you describe the solubility of resorcinol in water? A. Resorcinol is soluble in hot water but not in cold. B. Resorcinol dissolves well in both hot and cold water. C. Resorcinol is insoluble in water. D. Resorcinol is soluble in cold water but not in hotarrow_forwardFatty acids are distributed throughout the body, via a time-release/transport molecule created by: a. an esterification reaction with glycerol b. a hydrolytic reaction with methylamine c. an alkylation reaction with butanol d. a carboxylation reaction with lactic acid e. an ether formation reaction with ethylene glycolarrow_forward
- Which of the following statements is true? a. Both aldehydes and ketones are easily oxidized.b. Neither aldehydes nor ketones are easily oxidized.c. Aldehydes are easily oxidized, but ketones are not.d. Ketones are easily oxidized, but aldehydes are not. 2. Which of the following is obtained by oxidizing hexanal? a. hexanol b. 2-hexanone c. hexanoic acid d. none of these 3. Which of the following oxidizing agents oxidizes aldehydes in the body? a. NADH b. NAD+c. O2 d. none of these 4. Which of the following will be obtained by the reaction of pentanal with H2 in the presence of a transition metal catalyst? a. pentene b. 1-pentanolc. 2-pentanol d. pentanoic acid 5. The reaction of which combination of reactants result in the formation of a hemiacetal? a. ketone and alcohol b. ketone and aldehydec. ketone and carboxylic acid d. none of thesearrow_forwardDiscuss why are triacylglycerols, steroids, and phospholipids easily isolated using non-polar solvents.arrow_forward2. Draw the skeletal carbon structure of triacylglycerol and highlight the ester linkage.arrow_forward
- 5. What products would result from the following processes? Write an equation for each reaction. a. 2-Methyl-2-butanol is subjected to controlled oxidation. b. 1-Propanol is heated to 140°C in the presence of sulfuric acid. c. 3-Pentanol is subjected to controlled oxidation. d. 3-Pentanol is heated to 180°C in the presence of sulfuric acid. e. 1-Hexanol is subjected to an excess of oxidizing agentarrow_forwardCaused by the severe dehydration effect of formaldehyde on tissue A. fumigation B. hydration C. searing D. soaponificationarrow_forwardWhich statement explains the basis for obtaining a positive Benedict's test a. Tertiary alcohols cannot be oxidized easily. b. Primary alcohols can be oxidized to from aldehydes. c. Secondary alcohols can be oxidized to form ketones. d. Aldehydes are easily oxidized to form carboxylic acidsarrow_forward
- draw structure for: 2-formylethanamidearrow_forward5. Dehydration of glycerin when heated in the presence of potassium hydrogen sulfate leads to the formation of:A) Unsaturated aldehydeB) Unsaturated hydrocarbonB) Unsaturated aldehyde alcoholD) Unsaturated esterarrow_forward1. Draw structure of the following compounds? A) ethyldimethylamine B) N,N-dimethylbutanamide C) 2-chlorobutanoic acidarrow_forward
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